Problem 2
Question
Name and sketch the graph of each of the following equations in three-space. $$ y^{2}+z^{2}=15 $$
Step-by-Step Solution
Verified Answer
The graph is an infinite cylinder along the \(x\)-axis with a radius of \(\sqrt{15}\) in the \(yz\)-plane.
1Step 1: Understand the Equation
The given equation is \(y^2 + z^2 = 15\). There is no \(x\) variable in this equation, which implies that \(x\) can take any real value. This suggests that the graph will extend infinitely along the \(x\)-axis.
2Step 2: Identify the Equation Type in 2D
The equation \(y^2 + z^2 = 15\) is similar to the equation of a circle in the \(yz\)-plane. In standard form, it can be written as \((y - 0)^2 + (z - 0)^2 = 15\), which tells us it is a circle centered at the origin \((0,0)\) in the \(yz\)-plane with a radius of \(\sqrt{15}\).
3Step 3: Extend the Equation to 3D
Since the circle \(y^2 + z^2 = 15\) exists in the \(yz\)-plane for any value of \(x\), the three-dimensional graph is formed by extending this circle across all \(x\) values. This results in a cylinder extending parallel to the \(x\)-axis.
4Step 4: Sketch the Graph
To sketch the graph, draw a circle in the \(yz\)-plane with radius \(\sqrt{15}\) and then extend this circle along the \(x\)-axis to form an infinite cylinder. This cylinder will have its axis aligned with the \(x\)-axis.
Key Concepts
graph of a cylindertransforming equationsplane coordinatesthree-dimensional circle
graph of a cylinder
In the world of three-dimensional graphing, visualizing a cylinder is a fundamental concept. The equation provided, \( y^2 + z^2 = 15 \), helps us depict a cylinder. Essentially, the graph represents a cylindrical surface in 3D space. Since there is no \( x \) variable in this equation, the resulting cylinder extends infinitely along the \( x \)-axis. This axis is the lengthwise direction of the cylinder.
In practical terms, imagine a vertical circle in the \( yz \)-plane being "stretched" infinitely along the \( x \)-axis. This creates a shape that can be visualized as a pipe or a tunnel. The absence of \( x \) in the equation means any \( x \) value is permissible, confirming the cylinder's infinite length.
In practical terms, imagine a vertical circle in the \( yz \)-plane being "stretched" infinitely along the \( x \)-axis. This creates a shape that can be visualized as a pipe or a tunnel. The absence of \( x \) in the equation means any \( x \) value is permissible, confirming the cylinder's infinite length.
transforming equations
Equation transformation is crucial in identifying the types of shapes described by mathematical expressions. By recognizing how to transform equations, we can understand the geometry they imply. Here, the equation \( y^2 + z^2 = 15 \) is rearranged to \((y - 0)^2 + (z - 0)^2 = 15\). This transformation helps us notice it's a circle equation.
- \( y^2 + z^2 = r^2 \) — This standardizes the circle's equation, where \( r \) is the radius.
- Here, \( r = \sqrt{15} \), hinting at the circle's size in the \( yz \)-plane.
plane coordinates
Coordinate planes are pivotal in graphing and understanding shapes in three dimensions. For the given problem, we consider the \( yz \)-plane specifically.
- This plane is where we visualize the circle first, before extending it into three-dimensional space.
- The \( yz \)-plane consists of the vertical and depth dimensions, ignoring height or horizontal lengths like \( x \).
three-dimensional circle
When moving from a two-dimensional circle to three-dimensional space, the concept can be confusing. The equation \( y^2 + z^2 = 15 \) represents a circle in the \( yz \)-plane
- Center: Origin \((0, 0)\) in \( yz \)-plane.
- Radius: \( \sqrt{15} \).
Other exercises in this chapter
Problem 2
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