Problem 2
Question
Name and sketch the graph of each of the following equations in three-space. $$ y^{2}+z^{2}=15 $$
Step-by-Step Solution
Verified Answer
The graph is a circular cylinder centered along the x-axis with radius \(\sqrt{15}\).
1Step 1: Understand the Equation
The equation given is \(y^2 + z^2 = 15\). This looks like an equation of a cylinder. In three-space, when an equation is in the form \(y^2 + z^2 = r^2\), where \(r^2\) is a constant, it represents a cylindrical surface centered around the x-axis with radius \(r\).
2Step 2: Identify the Type of Graph
Based on the equation \(y^2 + z^2 = 15\), we identify this as a circular cylinder because it is centered along the x-axis where \(y\) and \(z\) are present together in a circular form and \(x\) does not appear in the equation.
3Step 3: Determine the Radius
To find the radius of the cylinder, compare it to \(y^2 + z^2 = r^2\). Here, \(r^2 = 15\), thus the radius \(r = \sqrt{15}\).
4Step 4: Sketch the Graph
To sketch the graph of the cylinder: 1. Recognize that the cylinder is infinite along the x-axis.2. For any fixed value of x, the graph in the yz-plane should be a circle with radius \(\sqrt{15}\).3. Draw several circles along the x-axis with radius \(\sqrt{15}\), illustrating the cylindrical shape expanding along the x-axis.
5Step 5: Name the Graph
The final graph is a circular cylinder. It extends infinitely in both directions along the x-axis, with circular cross-sections in the yz-plane, each having a radius of \(\sqrt{15}\).
Key Concepts
Equation of a CylinderThree-Dimensional GraphingCircular Cross-SectionRadius Calculation
Equation of a Cylinder
Understanding the equation of a cylinder is key to grasping three-dimensional shapes. In three-dimensional space, a cylinder's equation typically takes the form \(y^2 + z^2 = r^2\). Here, \(r^2\) is a constant that depicts the squared radius of the cylinder. Unlike a circle in two dimensions, this equation does not contain the variable \(x\). Instead, it implies that the cylinder stretches infinitely along the x-axis.
The equation \(y^2 + z^2 = 15\) is an example of a cylinder's equation. This representation clearly signifies a circular cross-section, with its axis along the x-direction. A cylinder can be understood as a series of stacked circles, all sharing an axis and having the same radius, thus forming a "tube-like" shape in space.
The equation \(y^2 + z^2 = 15\) is an example of a cylinder's equation. This representation clearly signifies a circular cross-section, with its axis along the x-direction. A cylinder can be understood as a series of stacked circles, all sharing an axis and having the same radius, thus forming a "tube-like" shape in space.
Three-Dimensional Graphing
Graphing in three dimensions can initially seem daunting, but it's a powerful tool for visualizing complex equations. When considering the cylinder like \(y^2 + z^2 = 15\), we think of it in the context of three-space.
- Visualize the x-axis as the direction along which the cylinder extends infinitely. This implies that no matter the x value, the circular cross-section's characteristics remain the same.
- In the yz-plane, where x is held constant at any value, the graph appears as a circle with the determined radius.
Circular Cross-Section
The concept of a circular cross-section is crucial for understanding cylinders. A cross-section is essentially a two-dimensional "slice" of a three-dimensional object. For the equation \(y^2 + z^2 = 15\), every cross-section parallel to the yz-plane is a circle.
Here’s how it works:
Here’s how it works:
- Each circle has the same radius, \(\sqrt{15}\).
- Because the equation lacks an x-component, each cross-section appears identical regardless of the x value chosen.
Radius Calculation
Determining the radius of a cylinder when given an equation is a straightforward process. In the context of the equation \(y^2 + z^2 = r^2\), calculating the radius requires only taking the square root of the constant on the right-hand side.
For the equation \(y^2 + z^2 = 15\):
For the equation \(y^2 + z^2 = 15\):
- The right side is 15, which means \(r^2 = 15\).
- Thus, the radius \(r\) is \(\sqrt{15}\).
Other exercises in this chapter
Problem 1
Let \(\quad \mathbf{a}=-3 \mathbf{i}+2 \mathbf{j}-2 \mathbf{k}, \quad \mathbf{b}=-\mathbf{i}+2 \mathbf{j}-4 \mathbf{k}, \quad\) and \(\mathbf{c}=7 \mathbf{i}+3
View solution Problem 1
Let \(\mathbf{a}=-2 \mathbf{i}+3 \mathbf{j}, \mathbf{b}=2 \mathbf{i}-3 \mathbf{j}\), and \(\mathbf{c}=-5 \mathbf{j}\). Find each of the following: (a) \(2 \math
View solution Problem 2
Change the following from cylindrical to spherical coordinates. (a) \((1, \pi / 2,1)\) (b) \((-2, \pi / 4,2)\)
View solution Problem 2
sketch the curve over the indicated domain for \(t\). Find \(\mathbf{v}, \mathbf{a}, \mathbf{T}\), and \(\kappa\) at the point where \(t=t_{1} .\) $$ \mathbf{r}
View solution