Problem 2
Question
Lead-210 is used to prepare eyes for corneal transplants. Its decay product is bismuth-210. Identify the emission from lead-210.
Step-by-Step Solution
Verified Answer
Answer: Beta-minus particle (an electron).
1Step 1: Understanding the Radioactive Decay Process
Radioactive decay is a random process where unstable atomic nuclei lose energy by emitting radiation. There are several types of radioactive decay, including alpha decay, beta decay (beta-minus and beta-plus), and gamma decay. In each decay process, a nucleus will release particles or energy in order to become more stable.
2Step 2: Writing the Decay Reaction
To determine the type of emission from lead-210 (Pb-210) as it decays into bismuth-210 (Bi-210), we can write the decay reaction as follows:
\[ ^{210}_{82}Pb → ^{210}_{83}Bi + X \]
In this reaction, the lead-210 nucleus is converted to a bismuth-210 nucleus and some emission X. To identify X, we need to compare the atomic numbers and mass numbers of the initial nucleus (Pb-210) and the final nucleus (Bi-210).
3Step 3: Identifying the Emission Type
Let's examine the atomic numbers and mass numbers of the initial and final nuclei:
- Initial nucleus: Lead-210 (Pb-210): atomic number (Z) = 82, mass number (A) = 210
- Final nucleus: Bismuth-210 (Bi-210): atomic number (Z) = 83, mass number (A) = 210
From the reaction, we can observe that the mass number remains constant (A = 210), whereas the atomic number increases by one (83 - 82 = 1). This increase in atomic number corresponds to the emission of a beta-minus particle (an electron), which can be represented by the symbol \(β^-\).
Therefore, the decay reaction for lead-210 turning into bismuth-210 is:
\[ ^{210}_{82}Pb → ^{210}_{83}Bi + β^- \]
4Step 4: Conclusion
The emission from lead-210 as it decays into bismuth-210 is a beta-minus particle (an electron).
Key Concepts
Beta DecayNuclear ReactionsLead-210 Decay
Beta Decay
When it comes to understanding radioactive decay, beta decay is an essential piece of the puzzle. Beta decay is a process that allows unstable atomic nuclei to transform into more stable configurations. This occurs through the emission of beta particles. There are two types of beta decay: beta-minus and beta-plus.
In beta-minus decay, a neutron in the nucleus turns into a proton. This process emits an electron, which we refer to as a beta particle, symbolized as \( β^- \). This emission increases the atomic number by one, turning the element into a new element located right next to it on the periodic table. Meanwhile, the mass number remains unchanged.
In beta-minus decay, a neutron in the nucleus turns into a proton. This process emits an electron, which we refer to as a beta particle, symbolized as \( β^- \). This emission increases the atomic number by one, turning the element into a new element located right next to it on the periodic table. Meanwhile, the mass number remains unchanged.
- Beta-minus example: As seen in the decay of lead-210 to bismuth-210, \(^{210}_{82}Pb \rightarrow ^{210}_{83}Bi + β^- \), an electron is emitted, increasing the atomic number from 82 to 83.
Nuclear Reactions
Nuclear reactions are processes in which the nucleus of an atom changes its composition or energy state. Unlike chemical reactions, which involve electron interactions, nuclear reactions alter the nucleus itself.
These reactions can occur naturally, as with radioactive decay, or can be induced artificially in laboratory settings.
These reactions can occur naturally, as with radioactive decay, or can be induced artificially in laboratory settings.
- Types of nuclear reactions: There are several types, such as fusion, fission, and decay processes (including beta decay, alpha decay, etc.).
- Conservation laws: Important principles in nuclear reactions include the conservation of mass number and atomic number. Mass number refers to the total count of protons and neutrons, while the atomic number refers solely to the number of protons.
Lead-210 Decay
Lead-210 decay is a fascinating example of radioactive decay, showcasing various principles in nuclear chemistry. Lead-210 is an isotope of lead, often used in medical applications such as preparing eyes for corneal transplants.
When lead-210 decays, it transforms into bismuth-210 through beta-minus decay. This specific decay process maintains the mass number at 210 and increases the atomic number by one, from 82 to 83. This increase in atomic number indicates the formation of a new element, bismuth-210.
When lead-210 decays, it transforms into bismuth-210 through beta-minus decay. This specific decay process maintains the mass number at 210 and increases the atomic number by one, from 82 to 83. This increase in atomic number indicates the formation of a new element, bismuth-210.
- Decay equation: The decay can be represented as \(^{210}_{82}Pb \rightarrow ^{210}_{83}Bi + β^- \).
- Real-world implications: Understanding such decay processes is crucial for applications in nuclear medicine and radiometric dating.
Other exercises in this chapter
Problem 1
Smoke detectors contain a small amount of americium-241. Its decay product is neptunium-237. Identify the emission from americium-241.
View solution Problem 3
Write balanced nuclear reactions for the following: (a) Formation of Am-241 through \(\beta\) -emissions. (b) Formation of Kr-81 by K-electron capture. (c) Form
View solution Problem 4
Write balanced nuclear equations for the following: (a) Formation of Mn-52 by positron emission. (b) Formation of Ac-228 by \(\beta\) -emission. (c) Formation o
View solution Problem 5
Write balanced nuclear equations for (a) the alpha emission resulting in the formation of \(\mathrm{Pa}-233\). (b) the loss of a positron by \(\mathrm{Y}-85\).
View solution