Problem 2
Question
In the development of Young's double-slit experiment, a small-angle approximation \((\tan \theta \approx \sin \theta)\) was used to find the lateral displacements of the maxima (bright) and minima (dark) positions. How good is this approximation? For example, what is the percentage error for \(\theta=10^{\circ} ?\)
Step-by-Step Solution
Verified Answer
The percentage error for \( \theta = 10^{\circ} \) is approximately 1.55\%.
1Step 1: Understand the small-angle approximation
The small-angle approximation states that for small angles, typically measured in radians, the values of \( \tan(\theta) \) and \( \sin(\theta) \) are approximately equal. This is often used when \( \theta \) is small (usually below 15°) to simplify calculations in trigonometry.
2Step 2: Convert degrees to radians
Angles in trigonometric calculations like this should be in radians. Convert \( \theta = 10^{\circ} \) to radians using the conversion \( 1^{\circ} = \frac{\pi}{180} \, \text{radians} \). Thus, \( 10^{\circ} = \frac{10 \pi}{180} = \frac{\pi}{18} \approx 0.1745 \, \text{radians} \).
3Step 3: Calculate \( \tan(\theta) \) and \( \sin(\theta) \)
Evaluate \( \tan(0.1745) \) and \( \sin(0.1745) \) using a calculator. For \( \theta = 0.1745 \): \( \tan(0.1745) \approx 0.1763 \), \( \sin(0.1745) \approx 0.1736 \).
4Step 4: Determine the difference
Find the difference between \( \tan(\theta) \) and \( \sin(\theta) \) by subtracting the two: \( \tan(0.1745) - \sin(0.1745) = 0.1763 - 0.1736 = 0.0027 \).
5Step 5: Percentage error calculation
To find the percentage error, use the formula: \( \text{Percentage Error} = \left( \frac{|\tan(\theta) - \sin(\theta)|}{\sin(\theta)} \right) \times 100 \). So, \( \text{Percentage Error} = \left( \frac{0.0027}{0.1736} \right) \times 100 \approx 1.55\%. \)
Key Concepts
Small-Angle ApproximationTrigonometry in PhysicsPercentage Error Calculation
Small-Angle Approximation
In physics, the small-angle approximation is a powerful simplification, especially in scenarios where the angle \(\theta\) is small enough that \(\tan \theta\) and \(\sin \theta\) can be treated as nearly equal. This approximation often applies when \(\theta\) is less than about 15 degrees. The simplification allows physicists and engineers to make complex calculations more manageable.
- The basic principle centers around measuring angles in radians. In radians, small angles appear very close in value when comparing \(\tan \theta\), \(\sin \theta\), and even \(\theta\) itself.
- For instance, in Young's double-slit experiment, this approximation helps in predicting points of constructive and destructive interference without complicating trigonometric calculations.
Trigonometry in Physics
Trigonometry is a cornerstone of physics, enabling the study of angles and their relationships in different scenarios, such as in Young's double-slit experiment. There, trigonometry helps analyze the path differences and interference patterns arising when two waves meet. It plays a crucial role in understanding various physical phenomena.
- Trigonometric functions like sine and tangent describe the ratios of sides in a right triangle relative to an angle.
- In practical physics applications, these functions assist in outlining the angles and dimensions of physical scenarios involving waves, projectiles, and optics.
Percentage Error Calculation
Calculating the percentage error is a fundamental skill in mathematics and physics, providing a measure of an approximation's accuracy. In the context of the small-angle approximation, it quantifies how close \(\tan(\theta)\) is to \(\sin(\theta)\), stipulating the precision of using one in the place of the other.
- The formula for percentage error is \(\text{Percentage Error} = \left( \frac{|\tan(\theta) - \sin(\theta)|}{\sin(\theta)} \right) \times 100\).
- It expresses the error as a percentage of the actual value, helping to assess the reliability of approximations in calculations.
Other exercises in this chapter
Problem 1
To study wave interference, a student uses two speakers driven by the same sound wave of wavelength \(0.50 \mathrm{~m}\). If the distances from a point to the s
View solution Problem 3
Two parallel slits \(0.075 \mathrm{~mm}\) apart are illuminated with monochromatic light of wavelength \(480 \mathrm{nm}\). Find the angle between the center of
View solution Problem 4
When two parallel slits are illuminated with monochromatic light of wavelength \(632.8 \mathrm{nm}\), the angle between the center of the central maximum and th
View solution Problem 5
In a double-slit experiment that uses monochromatic light, the angular separation between the central maximum and the second-order maximum is \(0.160^{\circ} .\
View solution