Problem 2
Question
In Problems \(1-8\), find \(d^{3} y / d x^{3}\). $$ y=x^{5}+x^{4} $$
Step-by-Step Solution
Verified Answer
The third derivative \(\frac{d^3y}{dx^3}\) is \(60x^2 + 24x\).
1Step 1: Differentiate the First Time
To begin, let's find the first derivative of the function \(y = x^5 + x^4\). Apply the power rule, which states that the derivative of \(x^n\) is \(nx^{n-1}\). Thus:\[ y' = \frac{dy}{dx} = 5x^4 + 4x^3 \]
2Step 2: Differentiate the Second Time
Now, differentiate the first derivative to get the second derivative. Again, apply the power rule:\[ y'' = \frac{d^2y}{dx^2} = 20x^3 + 12x^2 \]
3Step 3: Differentiate the Third Time
Finally, differentiate the second derivative to obtain the third derivative. Use the power rule once more:\[ y''' = \frac{d^3y}{dx^3} = 60x^2 + 24x \]
Key Concepts
Power RuleDifferentiationCalculus Problem Solving
Power Rule
The power rule is a fundamental technique in calculus for differentiation. It simplifies the process of finding derivatives for functions of the form \( x^n \). In essence, the power rule states: "Bring down the exponent as a coefficient and subtract one from the exponent."
This can be represented mathematically as:
By applying this rule successively to the polynomial \( y = x^5 + x^4 \), you can quickly find the derivatives needed. It's particularly useful for polynomials because each term can be differentiated independently.
This can be represented mathematically as:
- If \( y = x^n \), then the derivative \( \frac{dy}{dx} = nx^{n-1} \).
By applying this rule successively to the polynomial \( y = x^5 + x^4 \), you can quickly find the derivatives needed. It's particularly useful for polynomials because each term can be differentiated independently.
Differentiation
Differentiation is the process in calculus used to find the rate at which a function is changing. This is especially important in understanding how variables are related by a function.
To differentiate a function once is to find its first derivative. This derivative represents the instantaneous rate of change of the function with respect to one of its variables. For the function \( y = x^5 + x^4 \), when you perform differentiation:
To differentiate a function once is to find its first derivative. This derivative represents the instantaneous rate of change of the function with respect to one of its variables. For the function \( y = x^5 + x^4 \), when you perform differentiation:
- First derivative \( y' = 5x^4 + 4x^3 \).
- Second derivative \( y'' = 20x^3 + 12x^2 \).
- Third derivative \( y''' = 60x^2 + 24x \).
Calculus Problem Solving
Calculus problem-solving often involves systematically applying rules and methods to find derivatives, like the example problem, where you need to find the third derivative. Breaking down the problem into steps is key:
Approaching calculus systematically not only improves problem-solving skills but also deepens comprehension of mathematical relationships and the potential applications of derivatives.
- First, find the first derivative using the power rule.
- Then, find the second derivative by differentiating the first derivative.
- Finally, determine the third derivative by differentiating the second derivative.
Approaching calculus systematically not only improves problem-solving skills but also deepens comprehension of mathematical relationships and the potential applications of derivatives.
Other exercises in this chapter
Problem 1
Each edge of a variable cube is increasing at a rate of 3 inches per second. How fast is the volume of the cube increasing when an edge is 12 inches long?
View solution Problem 2
In Problems 1-18, find \(D_{x} y\). $$ y=\sin ^{2} x $$
View solution Problem 2
Show that \(f\) has an inverse by showing that it is strictly monotonic. \(f(x)=x^{7}+x^{5}+x^{3}+x\)
View solution Problem 2
Find \(D_{x} y\). $$ y=\cosh ^{2} x $$
View solution