Problem 2
Question
In Problems 1-4, show that each function is continuous at the given value. $$ f(x)=-x, c=1 $$
Step-by-Step Solution
Verified Answer
The function \( f(x) = -x \) is continuous at \( x = 1 \) because \( \lim_{x \to 1} f(x) = f(1) = -1 \).
1Step 1: Define Continuity at a Point
To show that a function is continuous at a given point \( c \), the limit of the function as \( x \) approaches \( c \) must equal the function's value at \( c \). Mathematically, this means \( \lim_{x \to c} f(x) = f(c) \).
2Step 2: Substitute the Given Function and Point
For the function \( f(x) = -x \) and \( c = 1 \), we first calculate the value of the function at \( c \): \( f(1) = -1 \).
3Step 3: Evaluate the Limit of the Function as x Approaches c
Calculate \( \lim_{x \to 1} f(x) = \lim_{x \to 1} (-x) \). Since \( f(x) = -x \) is a linear function, its limit as \( x \to 1 \) is simply \(-1\).
4Step 4: Compare the Limit with the Function Value
Compare the limit \( \lim_{x \to 1} f(x) = -1 \) with the function value \( f(1) = -1 \). Both the limit and the function value are equal.
Key Concepts
Understanding LimitsFunction EvaluationPoint of Continuity
Understanding Limits
In calculus, the concept of limits plays a crucial role in determining the behavior of functions as they approach a particular point. The limit essentially provides a way to predict where the function is heading as the input, often denoted as \( x \), gets closer and closer to a specific value. When we speak of the limit of a function \( f(x) \) as \( x \to c \), we are asking what value \( f(x) \) is approaching when \( x \) gets increasingly close to \( c \).
There are a few central characteristics to remember about limits:
There are a few central characteristics to remember about limits:
- Limits examine the trend of a function as inputs approach a given value, without necessarily reaching it.
- They help us understand what happens with function values very close to a certain point.
- Finding limits is often the first step when checking for continuity.
Function Evaluation
Function evaluation refers to substituting a specific value into a function and computing the result, which is crucial for analyzing the function's characteristics at particular points.
Let's go through the process of evaluating the function \( f(x) = -x \) at \( x = 1 \). By substituting into the function, we perform the operation \( f(1) = -(1) \), which gives us \(-1\).
Let's go through the process of evaluating the function \( f(x) = -x \) at \( x = 1 \). By substituting into the function, we perform the operation \( f(1) = -(1) \), which gives us \(-1\).
- It’s a straightforward process but forms the backbone of many higher-level calculus concepts.
- This evaluated result of \( f(1) = -1 \) allows us to compare it with the limit we previously calculated.
- The accuracy of function evaluation is crucial for determining continuity.
Point of Continuity
A point of continuity is where a function is seamless and unbroken; the graph is smooth at that particular point. For a function to be continuous at a point \( c \), three conditions must be satisfied:
In our solution, all three conditions were met for \( f(x) = -x \) at \( c = 1 \):
- The function \( f(x) \) must be defined at \( c \). This means \( f(c) \) exists.
- The limit of \( f(x) \) as \( x \cc \to c \) should exist.
- The limit of \( f(x) \) as \( x \to c \) must equal the function value \( f(c) \).
In our solution, all three conditions were met for \( f(x) = -x \) at \( c = 1 \):
- We calculated \( f(1) = -1 \), so the function is defined at \( x = 1 \).
- We found \( \lim_{x \to 1} (-x) \) which also resulted in \(-1\), confirming the limit exists at the point.
- The limit and function value both agree, showing no disruptions.
Other exercises in this chapter
Problem 2
Let $$ f(x)=x^{3}-2 x+3, \quad-3 \leq x \leq-1 $$ (a) Graph \(y=f(x)\) for \(-3 \leq x \leq-1\). (b) Use the intermediate-value theorem to conclude that $$ x^{3
View solution Problem 2
In Problems 1-32, use a table or a graph to investigate each limit. $$ \lim _{x \rightarrow 2} \frac{x^{2}+3}{x+2} $$
View solution Problem 2
Evaluate the limits in problems. $$ \lim _{x \rightarrow \infty} \frac{x^{2}+3}{5 x^{2}-2 x+1} $$
View solution Problem 3
Let $$f(x)=\frac{\ln x}{x}, \quad x>0$$ (a) Use a graphing calculator to graph \(y=f(x)\). (b) Use a graphing calculator to investigate the values of \(x\) for
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