Problem 2
Question
In Exercises \(1-8,\) find the divergence of the field. $$ \mathbf{F}=(x \ln y) \mathbf{i}+(y \ln z) \mathbf{j}+(z \ln x) \mathbf{k} $$
Step-by-Step Solution
Verified Answer
The divergence of the field is \( \ln(xyz) \).
1Step 1: Understand the Divergence Formula
The divergence of a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \) is given by the formula \( abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \). Here, \( P = x \ln y \), \( Q = y \ln z \), and \( R = z \ln x \).
2Step 2: Compute Partial Derivative of P with Respect to x
To find \( \frac{\partial P}{\partial x} \), differentiate \( P = x \ln y \) with respect to \( x \), treating \( y \) as a constant. This yields \( \frac{\partial (x \ln y)}{\partial x} = \ln y \).
3Step 3: Compute Partial Derivative of Q with Respect to y
To find \( \frac{\partial Q}{\partial y} \), differentiate \( Q = y \ln z \) with respect to \( y \), treating \( z \) as a constant. This yields \( \frac{\partial (y \ln z)}{\partial y} = \ln z \).
4Step 4: Compute Partial Derivative of R with Respect to z
To find \( \frac{\partial R}{\partial z} \), differentiate \( R = z \ln x \) with respect to \( z \), treating \( x \) as a constant. This yields \( \frac{\partial (z \ln x)}{\partial z} = \ln x \).
5Step 5: Add the Partial Derivatives
Combine the partial derivatives computed in the previous steps: \( abla \cdot \mathbf{F} = \ln y + \ln z + \ln x = \ln(xyz) \). Thus, the divergence of the field is \( \ln(xyz) \).
Key Concepts
Vector FieldPartial DerivativesDivergence Theorem
Vector Field
In the realm of mathematics, particularly vector calculus, a vector field is a construction where each point in space is associated with a vector. This is a crucial concept in physical sciences and engineering, often representing quantities like velocity fields in fluid dynamics or electromagnetic fields.
These fields are denoted as \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), where \( P \), \( Q \), and \( R \) are functions of the coordinates \( x \), \( y \), and \( z \).
These fields are denoted as \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), where \( P \), \( Q \), and \( R \) are functions of the coordinates \( x \), \( y \), and \( z \).
- **Components**: Each vector field consists of three components, which describe the magnitude and direction in each Cartesian coordinate.
- **Representation**: In the example, \( \mathbf{F} = (x \ln y) \mathbf{i} + (y \ln z) \mathbf{j} + (z \ln x) \mathbf{k} \) describes a field where each spatial point determines a vector based on these component functions.
Partial Derivatives
Partial derivatives extend the concept of a derivative to functions of multiple variables, where you differentiate with respect to one variable while keeping the others constant.
In vector fields, this is essential for calculating properties like divergence or curl. Let's break down their significance and calculation.
In vector fields, this is essential for calculating properties like divergence or curl. Let's break down their significance and calculation.
- **Definition**: A partial derivative of a function with several variables, such as \( f(x, y, z) \), is found by differentiating with respect to one variable and treating others as constants.
- **Calculation**: For the field \( \mathbf{F} \), partial derivatives are calculated as follows:
- For \( P = x \ln y \), the partial derivative with respect to \( x \) is \( \frac{\partial P}{\partial x} = \ln y \).
- For \( Q = y \ln z \), the partial derivative with respect to \( y \) is \( \ln z \).
- For \( R = z \ln x \), the partial derivative with respect to \( z \) is \( \ln x \).
Divergence Theorem
The divergence theorem is a fundamental statement in vector calculus, translating a surface integral into a volume integral and vice versa.
It bridges divergence of vector fields with tangible physical properties, like fluid flow and electric fields.
It bridges divergence of vector fields with tangible physical properties, like fluid flow and electric fields.
- **Concept**: The divergence of a vector field at a point provides a scalar that indicates whether there is a source (divergence > 0) or a sink (divergence < 0) at that point.
- **Formula**: Given a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), its divergence is \( abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \).
- **Application**: By summing up the partial derivatives as seen in the exercise, we arrive at the divergence \( \ln(xyz) \), conveying how the field behaves around each point.
Other exercises in this chapter
Problem 2
Find the \(\mathbf{k}\) -component of \(\operatorname{curl}(\mathbf{F})\) for the following vector fields on the plane. \(\mathbf{F}=\left(x^{2}-y\right) \mathb
View solution Problem 2
In Exercises \(1-6,\) find the curl of each vector field \(\mathbf{F}\) $$\mathbf{F}=\left(x^{2}-y\right) \mathbf{i}+\left(y^{2}-z\right) \mathbf{j}+\left(z^{2}
View solution Problem 2
In Exercises \(1-8,\) integrate the given function over the given surface. Circular cylinder \(G(x, y, z)=z,\) over the cylindrical surface \(y^{2}+z^{2}=4, z \
View solution Problem 2
Find the gradient fields of the functions in Exercises \(1-4\) $$f(x, y, z)=\ln \sqrt{x^{2}+y^{2}+z^{2}}$$
View solution