Problem 2
Question
If the equation of a parabola is written in standard form and \(p\) is positive and the directrix is a vertical line, then what can we conclude about its graph?
Step-by-Step Solution
Verified Answer
The graph of the parabola opens upwards.
1Step 1: Recall the Standard Form of a Parabola
A parabola with a vertical directrix is typically represented by the equation \((x-h)^2 = 4p(y-k)\) where \((h,k)\) is the vertex of the parabola and \(p\) is the distance from the vertex to the focus, which is also distance to the directrix.
2Step 2: Analyze Positive Parameter 'p'
The value of \(p\) indicates the direction in which the parabola opens. Since \(p > 0\), the parabola will open upwards, away from the directrix, because it is positioned at a positive distance from the vertex.
3Step 3: Determine Orientation of the Graph
Since we have determined that \(p > 0\) and the directrix is a vertical line, the axis of symmetry of the parabola is vertical. Thus, the parabola opens upwards, with its vertex below its focus.
Key Concepts
VertexFocusDirectrix
Vertex
The vertex of a parabola is a crucial point as it defines the location from which the parabola originates. Imagine this as the starting position of a parabola that opens up or down.
The vertex is denoted by the coordinates \((h,k)\) when the parabola equation is in the form \((x-h)^2 = 4p(y-k)\). This means that the vertex acts as the center point of the parabola, horizontally at \(x = h\) and vertically at \(y = k\).
Knowing the vertex is essential because:
The vertex is denoted by the coordinates \((h,k)\) when the parabola equation is in the form \((x-h)^2 = 4p(y-k)\). This means that the vertex acts as the center point of the parabola, horizontally at \(x = h\) and vertically at \(y = k\).
Knowing the vertex is essential because:
- It helps in determining the axis of symmetry of the parabola.
- It gives a starting reference point to calculate the position of the focus and the directrix.
- It provides insight into the direction in which the parabola opens.
Focus
The focus of a parabola is a special point that affects the shape and position of the parabola.
A simple way to comprehend this is by thinking of the focus as a light source—places on the parabola such as fixtures direct their paths by heading towards the focus.
In the standard form equation \((x-h)^2 = 4p(y-k)\):
A simple way to comprehend this is by thinking of the focus as a light source—places on the parabola such as fixtures direct their paths by heading towards the focus.
In the standard form equation \((x-h)^2 = 4p(y-k)\):
- The focus lies on the vertical line passing through \(x = h\).
- It is located at the point \((h, k + p)\) when \(p\) is positive, meaning the parabola opens upwards.
Directrix
The directrix of a parabola might sound complex, but it's quite straightforward. It's an imaginary line, guide, or a boundary that dictates the balance of distances—the directrix ensures a mirrored arrangement between the other mathematical elements of the parabola.
For the equation \((x-h)^2 = 4p(y-k)\):
For the equation \((x-h)^2 = 4p(y-k)\):
- If \(p > 0\), the parabola opens upward and the directrix is defined by the line \(y = k - p\). This line lies beneath the vertex.
- The directrix is always perpendicular to the axis that connects the vertex to the focus.
Other exercises in this chapter
Problem 1
Define a hyperbola in terms of its foci.
View solution Problem 2
If a conic section is written as a polar equation, what must be true of the denominator?
View solution Problem 2
What can we conclude about a hyperbola if its asymptotes intersect at the origin?
View solution Problem 2
Where must the foci of an ellipse lie?
View solution