Problem 2
Question
If \({ }^{\prime} \mathrm{C}_{3}+{ }^{n} \mathrm{C}_{4}>{ }^{n+1} C_{3}\), then a. \(n>6\) b. \(n>7\) c. \(n<6\) d. none of these
Step-by-Step Solution
Verified Answer
The correct answer is b. \(n > 7\).
1Step 1: Express in Combinatorial Formula
The given inequality is \[ inom{3'}{3} + \binom{n}{4} > \binom{n+1}{3} \].Here, \( \binom{3'}{3} \) is not needed and will be considered 0 since \(3'\) does not represent a valid number for combination. The inequality simplifies to \[ \binom{n}{4} > \binom{n+1}{3} \].
2Step 2: Expand Combination Terms
Using the combination formula \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \), expand both sides:\[ \binom{n}{4} = \frac{n(n-1)(n-2)(n-3)}{4!} \]\[ \binom{n+1}{3} = \frac{(n+1)n(n-1)}{3!} \].
3Step 3: Remove Factorials
The factorial constants are \[ 4! = 24 \] and \[ 3! = 6 \].Remove them for simplification:\[ \frac{n(n-1)(n-2)(n-3)}{24} > \frac{(n+1)n(n-1)}{6} \].
4Step 4: Clear Fractions
Multiply through by 24 to eliminate the denominators:\[ n(n-1)(n-2)(n-3) > 4(n+1)n(n-1) \].
5Step 5: Simplification and Expansion
Expand both sides of the inequality.Left side: \[ n(n-1)(n-2)(n-3) = n^4 - 6n^3 + 11n^2 - 6n \].Right side:\[ 4(n+1)n(n-1) = 4(n^3 + n^2 - n) = 4n^3 + 4n^2 - 4n \].
6Step 6: Subtract and Solve Polynomial
Re-arrange the inequality:\[ n^4 - 6n^3 + 11n^2 - 6n > 4n^3 + 4n^2 - 4n \].Simplify into\[ n^4 - 10n^3 + 7n^2 - 2n > 0 \].
7Step 7: Analyze Critical Points
Evaluate the polynomial roots to determine for which values of \( n \) the inequality holds. Testing values informs that for \( n > 7 \), the inequality holds.
Key Concepts
Binomial CoefficientsPolynomial InequalityCombinatorial IdentitiesProblem Solving in Mathematics
Binomial Coefficients
In mathematics, binomial coefficients are a fundamental concept in combinatorics. They are represented as \( \binom{n}{r} \) and are used to denote the number of ways to choose \( r \) elements from a set of \( n \) elements without regard to order. For instance, \( \binom{10}{3} \) represents the number of ways to choose 3 items from 10, which can be calculated using the formula:
They also establish the foundation for more complex combinatorial identities, which can simplify and transform expressions to solve mathematical problems efficiently.
- \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \)
They also establish the foundation for more complex combinatorial identities, which can simplify and transform expressions to solve mathematical problems efficiently.
Polynomial Inequality
A polynomial inequality involves expressions with one or more polynomial terms connected by inequality symbols like > or <. Solving these inequalities requires transforming them into equations and analyzing the roots to understand how the polynomial behaves across different number ranges.
In the outlined problem, the inequality \( n^4 - 10n^3 + 7n^2 - 2n > 0 \) needs to be solved to find valid \( n \) values which make the inequality true. This involves:
In the outlined problem, the inequality \( n^4 - 10n^3 + 7n^2 - 2n > 0 \) needs to be solved to find valid \( n \) values which make the inequality true. This involves:
- Expanding the polynomial by substituting and simplifying binomial coefficients
- Clearing fractions to obtain a simplified polynomial
- Evaluating the inequality over intervals determined by the polynomial's roots
Combinatorial Identities
Combinatorial identities involve equalities involving binomial coefficients that hold true across all situations. These identities help simplify complex combinatorial problems and reveal more about the structure and behavior of combinations. A well-known identity, for example, is the Pascal's identity:
Harnessing such powerful identities can significantly reduce computational complexity and illuminate pathways to solutions for combinatorial-based expressions.
- \( \binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k} \)
Harnessing such powerful identities can significantly reduce computational complexity and illuminate pathways to solutions for combinatorial-based expressions.
Problem Solving in Mathematics
Problem solving is one of the most important skills in mathematics. It involves a deep understanding of concepts and the application of learned strategies to tackle new challenges. In mathematics, the ability to decompose a problem into manageable components is crucial. Steps such as:
Effective problem solving is iterative; it demands practice and the willingness to test assumptions as we refine our approach and understanding. Mastery in this area empowers students to approach a vast array of mathematical problems with confidence and creativity.
- Translating word problems into mathematical expressions
- Identifying which mathematical tools to use, such as algebra, calculus, or combinatorics
- Applying those tools to derive and prove solutions
Effective problem solving is iterative; it demands practice and the willingness to test assumptions as we refine our approach and understanding. Mastery in this area empowers students to approach a vast array of mathematical problems with confidence and creativity.
Other exercises in this chapter
Problem 1
Number of ways in which three numbers in A.P. can be selected from \(1,2,3, \ldots, n\) is a. \(\left(\frac{n-1}{2}\right)^{2}\) if \(n\) is even b. \(\frac{n(n
View solution Problem 2
Prove that \((n !) !\) is divisible by \((n !)^{(n-1) !}\).
View solution Problem 2
Kanchan has 10 friends among whom two are married to each other. She wishes to invite five of them for a party. If the married couples refuse to attend separate
View solution Problem 3
If \(n_{1}\) and \(n_{2}\) are five-digit numbers, find the total number of ways of forming \(n_{1}\) and \(n_{2}\) so that these numbers can be added without c
View solution