Problem 2
Question
If one can find the ratio of the number of moles of the elements in a compound to one another, one can find the formula of the compound. In a certain compound of copper and oxygen, \(\mathrm{Cu}_{x}\) o, we find that a sample weighing 0.6349 g contains 0.5639 g Cu. a. How many moles of Cu are there in the sample? $$\left(\text {No. moles} =\frac{\text { mass Cu }}{\text { molar mass } \mathrm{Cu}}\right)$$ ______________ moles b. How many grams of O are there in the sample? (The mass of the sample equals the mass of Cu plus the mass of O.) ______________ g c. How many moles of O are there in the sample? ______________ moles d. What is the mole ratio (no. moles Cu/no. moles O) in the sample? ______________ : 1 e. What is the formula of the oxide? (The atom ratio equals the mole ratio, and is expressed using the smallest integers possible.) ______________ f. What is the molar mass of the copper oxide? ______________ g/mol
Step-by-Step Solution
VerifiedKey Concepts
Molar Mass Calculations
In our example, we needed to determine the moles of copper (Cu) in a given sample. First, we identified that the molar mass of Cu is approximately 63.55 g/mol. Using this information, we can calculate the number of moles by dividing the mass of Cu in the sample (0.5639 g) by its molar mass:
- Number of moles of Cu = \( \frac{0.5639 \, \text{g}}{63.55 \, \text{g/mol}} \approx 0.00887 \, \text{moles} \).
Mole Concept
In our example, after finding the moles of copper, we also determined the moles of oxygen in the compound. The mass of oxygen was found to be 0.0710 g. The molar mass of oxygen is approximately 16.00 g/mol, enabling us to calculate the moles of oxygen:
- Number of moles of O = \( \frac{0.0710 \, \text{g}}{16.00 \, \text{g/mol}} \approx 0.00444 \, \text{moles} \).
Chemical Stoichiometry
In practice, stoichiometry helps us determine how much of each element is present in a compound by using mole ratios derived from empirical formulas. For our copper oxide compound, we found the mole ratio of copper to oxygen by dividing the number of moles of copper by the number of moles of oxygen:
- Mole Ratio = \( \frac{0.00887}{0.00444} \approx 2.00 \).