Problem 2
Question
If a weight of \(8 \mathrm{~kg}\) is placed \(10 \mathrm{~m}\) from the fulcrum of a lever and a weight of \(12 \mathrm{~kg}\) is placed \(8 \mathrm{~m}\) from the fulcrum in the opposite direction, toward which weight will the lever incline?
Step-by-Step Solution
Verified Answer
Answer: The lever will incline towards the 12 kg weight.
1Step 1: Calculate the moment of force for the 8 kg weight
To calculate the moment of force for the 8 kg weight, we will multiply its weight by its distance from the fulcrum: \( 8 \mathrm{~kg} \times 10 \mathrm{~m}\).
Moment of force \(= 8 \times 10 = 80 \mathrm{~kg \cdot m}\).
2Step 2: Calculate the moment of force for the 12 kg weight
To calculate the moment of force for the 12 kg weight, we will multiply its weight by its distance from the fulcrum: \(12 \mathrm{~kg} \times 8 \mathrm{~m}\).
Moment of force \(= 12 \times 8 = 96 \mathrm{~kg \cdot m}\).
3Step 3: Compare the moments of force
Now, we will compare the moments of force calculated in steps 1 and 2 to determine towards which weight the lever will incline.
Moment of force for 8 kg weight \(= 80 \mathrm{~kg \cdot m}\).
Moment of force for 12 kg weight \(= 96 \mathrm{~kg \cdot m}\).
Since the moment of force for the 12 kg weight is greater than the moment of force for the 8 kg weight (96 > 80), the lever will incline towards the 12 kg weight.
Key Concepts
LeversMoments of forceEquilibrium
Levers
A lever is a simple machine that helps us lift or move loads with less effort. Imagine a seesaw; that's a common example of a lever.
Levers have three main parts:
By varying the distances of the effort and load arms from the fulcrum, levers can reduce the amount of force needed to lift a heavy load. In the given exercise, the lever tilts towards the heavier force, determining which side of the seesaw goes down.
- **Fulcrum:** The pivot point around which the lever turns.
- **Effort Arm:** The side where force is applied to lift the load.
- **Load Arm:** The side where the load is placed, opposite to the effort.
By varying the distances of the effort and load arms from the fulcrum, levers can reduce the amount of force needed to lift a heavy load. In the given exercise, the lever tilts towards the heavier force, determining which side of the seesaw goes down.
Moments of force
Moments of force, also known simply as moments, are vital in understanding how levers work.
A moment is the turning effect produced by a force acting at a distance from the pivot point.
The formula to find the moment of force is:\[\text{Moment of Force} = \text{Force} \times \text{Distance from Fulcrum}\]Key points about moments of force include:
A moment is the turning effect produced by a force acting at a distance from the pivot point.
The formula to find the moment of force is:\[\text{Moment of Force} = \text{Force} \times \text{Distance from Fulcrum}\]Key points about moments of force include:
- **Direction matters:** Moments can cause clockwise or counterclockwise rotation.
- **Balance is crucial:** For equilibrium (balance), the sum of clockwise moments should equal the sum of counterclockwise moments.
Equilibrium
Equilibrium in the context of levers means that the lever is at rest or balanced. This occurs when there are no net forces causing movement around the fulcrum.
To achieve equilibrium, the moments on either side of the fulcrum must be equal. Understanding equilibrium involves:
To achieve equilibrium, the moments on either side of the fulcrum must be equal. Understanding equilibrium involves:
- **Sum of moments:** The sum of moments on one side must equal the sum on the opposite side for balance.
- **Static condition:** No movement occurs when the system is in equilibrium.
- **Adjustment of positions:** Changing distances from the fulcrum or altering the weights can achieve balance.
Other exercises in this chapter
Problem 1
Find where to place the fulcrum in a lever of length \(10 \mathrm{~m}\) so that a weight of \(14 \mathrm{~kg}\) at one end will balance a weight of \(10 \mathrm
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An alternative method by which Archimedes could have solved the crown problem is given by Vitruvius in \(\mathrm{On}\) Architecture. Assume as in the text that
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Use calculus to prove Archimedes' result from The Method that the volume of the segment of the cylinder described in the text is \(1 / 6\) the volume of the rec
View solution Problem 11
Use calculus to prove Archimedes' result that the area of a parabolic segment is four-thirds of the area of the inscribed triangle.
View solution