Problem 2
Question
How would you go about finding the number of "chalk molecules" it takes to write your name on the board? Provide an explanation of all you would need to do and a sample calculation.
Step-by-Step Solution
Verified Answer
To estimate the number of chalk molecules needed to write your name on the board, follow these steps:
1. Measure the dimensions (height, width, thickness) of each letter and calculate the total volume of chalk used.
2. Multiply the total volume by the density of chalk (2.71 g/cm³) to find the mass of chalk used.
3. Divide the mass of chalk used by the molar mass of calcium carbonate (100 g/mol) to find the number of moles.
4. Multiply the number of moles by Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of chalk molecules.
For the sample calculation with the name "John," we estimated that it takes approximately 9.78 x 10^22 chalk molecules to write the name on the board. This number depends on writing style and chalk pressure applied.
1Step 1: Estimate the volume of chalk used for writing the name
We can do this by measuring the dimensions of each letter and then multiplying the height, width, and thickness of each letter. Sum up the volume of each letter to get the total volume of chalk used for writing the entire name.
For our sample calculation, let's consider writing the name "John" on the board. Assume that each letter is 5 cm in height, 3 cm in width, and 0.1 cm in thickness.
2Step 2: Use the density of chalk to calculate the mass of the chalk used
Chalk is primarily composed of calcium carbonate (CaCO3) and its density is approximately 2.71 g/cm³. To find the mass of the chalk used for writing the name, multiply the total volume (obtained in Step 1) by the density.
3Step 3: Calculate the number of moles of calcium carbonate in the mass of chalk used
To do this, divide the mass of chalk used for writing the name (obtained in Step 2) by the molar mass of calcium carbonate (CaCO3). The molar mass of CaCO3 is approximately 100 g/mol.
4Step 4: Calculate the number of chalk molecules used
Now, using Avogadro's number (approximately 6.022 x 10^23 molecules/mol), multiply the number of moles of calcium carbonate (obtained in Step 3) by Avogadro's number to find the number of chalk molecules used for writing the name.
Sample Calculation:
Step 1: Calculate the total volume of chalk used
"John" has four letters, and let's assume that each letter has a volume of 5 cm x 3 cm x 0.1 cm = 1.5 cm³.
Total volume = 1.5 cm³ x 4 = 6 cm³
Step 2: Calculate the mass of chalk used
Mass = Volume x Density
Mass = 6 cm³ x 2.71 g/cm³ = 16.26 g
Step 3: Calculate the number of moles of calcium carbonate
Moles = Mass / Molar mass
Moles = 16.26 g / 100 g/mol = 0.1626 moles
Step 4: Calculate the number of chalk molecules used
Number of chalk molecules = Moles x Avogadro's number
Number of chalk molecules = 0.1626 moles x 6.022 x 10^23 molecules/mol ≈ 9.78 x 10^22 molecules
So, it takes approximately 9.78 x 10^22 chalk molecules to write the name "John" on the board. Keep in mind that this is an estimation and the exact number of chalk molecules will vary depending on the writing style and chalk pressure applied.
Key Concepts
Molar Mass CalculationAvogadro's Number ApplicationChemical Compound Mole Concept
Molar Mass Calculation
Understanding molar mass is essential in the realm of chemistry, particularly when deciphering the intricate dance of atoms and molecules in chemical reactions. It represents the mass of one mole of a substance, typically measured in grams per mole (g/mol). To conduct a molar mass calculation, one would diligently sum the atomic masses of all the atoms present in a molecule.
For a practical elucidation, consider calcium carbonate (CaCO3), a compound comprising calcium (Ca), carbon (C), and oxygen (O) atoms. The atomic masses of these atoms are approximately 40.08 g/mol for Ca, 12.01 g/mol for C, and 16.00 g/mol for each O atom. Summing these gives us the molar mass of CaCO3:
(Ca) 40.08 g/mol + (C) 12.01 g/mol + 3(O) 3 x 16.00 g/mol = 100.09 g/mol.
Grasping this concept enables students to convert between mass and moles of a substance, a pivotal step in any stoichiometric calculation.
For a practical elucidation, consider calcium carbonate (CaCO3), a compound comprising calcium (Ca), carbon (C), and oxygen (O) atoms. The atomic masses of these atoms are approximately 40.08 g/mol for Ca, 12.01 g/mol for C, and 16.00 g/mol for each O atom. Summing these gives us the molar mass of CaCO3:
(Ca) 40.08 g/mol + (C) 12.01 g/mol + 3(O) 3 x 16.00 g/mol = 100.09 g/mol.
Grasping this concept enables students to convert between mass and moles of a substance, a pivotal step in any stoichiometric calculation.
Avogadro's Number Application
Avogadro's number, a constant denoted by the symbol NA, is the cornerstone of quantitative chemistry. Representing approximately 6.022 x 1023 entities per mole, it serves as a bridge between the microscopic world of atoms and the macroscopic realm we interact with daily.
Applying Avogadro's number is relatively straightforward but utterly profound. Once the moles of a substance are determined—by dividing the mass by the molar mass—one can unleash the power of Avogadro's number to transmute moles into discrete particles (atoms, ions, or molecules), and vice versa. For instance, using the problem at hand, if one mole of calcium carbonate contains 6.022 x 1023 molecules, then 0.1626 moles will have:0.1626 moles x 6.022 x 1023 molecules/mole ≈ 9.78 x 1022 molecules.
This application is integral in predicting the sheer number of particles involved in chemical formulas and responses, laying the groundwork for stoichiometric calculations in numerous chemical scenarios.
Applying Avogadro's number is relatively straightforward but utterly profound. Once the moles of a substance are determined—by dividing the mass by the molar mass—one can unleash the power of Avogadro's number to transmute moles into discrete particles (atoms, ions, or molecules), and vice versa. For instance, using the problem at hand, if one mole of calcium carbonate contains 6.022 x 1023 molecules, then 0.1626 moles will have:0.1626 moles x 6.022 x 1023 molecules/mole ≈ 9.78 x 1022 molecules.
This application is integral in predicting the sheer number of particles involved in chemical formulas and responses, laying the groundwork for stoichiometric calculations in numerous chemical scenarios.
Chemical Compound Mole Concept
The mole concept stands as a fundamental pillar in the study of chemistry, central to the mutual language that chemists share worldwide. A mole is an SI unit that measures the amount of substance, defined as the number of particles (usually atoms or molecules) equal to Avogadro's number.
To breathe life into this abstract notion, consider this real-world application: the task of gauging how many chalk molecules are required to inscribe a name on a chalkboard. Employing the mole concept involves several exhilarating steps - estimating the chalk volume, determining mass through density, then translating mass to moles using molar mass, and finally, the thrilling climax of multiplying by Avogadro's number to yield the total molecules.
To breathe life into this abstract notion, consider this real-world application: the task of gauging how many chalk molecules are required to inscribe a name on a chalkboard. Employing the mole concept involves several exhilarating steps - estimating the chalk volume, determining mass through density, then translating mass to moles using molar mass, and finally, the thrilling climax of multiplying by Avogadro's number to yield the total molecules.
Connecting Moles to Real Quantities
With the determined number of moles, it's as if one can order distinct packets of molecules right off the shelf - each packet containing exactly Avogadro's number of entities. The mole serves not just as a unit but also as a bridge, expertly connecting the microscopic scale to our tactile reality, enabling chemists and students alike to fathom and quantify the sublime nature of matter.Other exercises in this chapter
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