Problem 2
Question
How many different nine-letter arrangements can be formed from the nine letters of the word APPARATUS? \(\quad 30,240\)
Step-by-Step Solution
Verified Answer
45,360 distinct arrangements can be formed.
1Step 1: Identify the Problem
We want to find the number of distinct nine-letter arrangements that can be made using the letters from the word 'APPARATUS'. This is a permutation problem involving repeating elements.
2Step 2: Determine the Total Number of Letters
The word 'APPARATUS' consists of 9 letters, which we need to arrange. These include repeated letters which are: two 'A's, two 'P's, and two 'T's.
3Step 3: Calculate the Total Permutations Without Repetition
First, calculate the total number of arrangements if all letters were different. This would be the factorial of the number of letters: \[ 9! = 362,880 \]
4Step 4: Adjust for Repeated Letters
Divide the total permutations by the factorial of the frequency of each repeating letter to account for those repetitions:1. The letters 'A', 'P', and 'T' each repeat twice.So, divide by \[(2!)^3 = 2! \times 2! \times 2! = 2 \times 2 \times 2 = 8\]Thus, the number of distinct permutations is:\[ \frac{9!}{(2!)^3} = \frac{362,880}{8} = 45,360 \]
Key Concepts
Factorials and Their ImportanceThe Magic of CombinatoricsUnderstanding Distinct Arrangements
Factorials and Their Importance
When you're tasked with arranging different objects, like letters, numbers, or any other elements, the concept of "factorials" becomes essential. Factorials help us determine how many different ways we can arrange a set of items. The notation for a factorial looks like this: \[ n! \] Where \(n\) is a whole number, and the "!" denotes factorial. For example, if you have 3 different items, the factorial \(3!\) tells you the number of different arrangements. To compute 3!, you multiply 3 by all the whole numbers below it:\[ 3! = 3 \times 2 \times 1 = 6 \]This means there are 6 possible ways to arrange 3 items.
A key factor here is understanding that as the number of items increases, the number of possible arrangements grows very quickly due to the multiplication of descending integers.
A key factor here is understanding that as the number of items increases, the number of possible arrangements grows very quickly due to the multiplication of descending integers.
- Factorials provide the "total permutations" when each item in a set is distinct.
- They form the backbone of more complex arrangements, especially when dealing with repetitions, as in the exercise above.
The Magic of Combinatorics
Combinatorics is the branch of mathematics focused on counting, arrangement, and combination of sets. Understanding combinatorics is pivotal in problems where permutations with repetition arise.
When we talk about permutations, we essentially mean the arrangement of a set in a particular order. The role of combinatorics is to help us calculate these arrangements more effectively by consideration of various factors, like repetitions.
When we talk about permutations, we essentially mean the arrangement of a set in a particular order. The role of combinatorics is to help us calculate these arrangements more effectively by consideration of various factors, like repetitions.
- Permutations are an arrangement of all elements in a particular order. When elements repeat, we adjust our calculations accordingly.
- Without the language of combinatorics, solving these problems systematically would be much more difficult and less intuitive.
Understanding Distinct Arrangements
When solving permutation problems, the biggest challenge is often creating distinct arrangements, especially with repeated items. In our exercise, the word "APPARATUS" contains repeating letters: two 'A's, two 'P's, and two 'T's.
- Without these repetitions, you would calculate arrangements through a simple factorial of all letters.
- However, with repetitions, the permutations must be adjusted to ensure that arrangements forming the same sequence with different repetitions are only counted once.
Other exercises in this chapter
Problem 1
If a woman has two skirts and ten blouses, how many different skirt-blouse combinations does she have? 20
View solution Problem 1
In Problems \(1-12\), evaluate each.\(P(5,3)\)
View solution Problem 2
If a man has eight shirts, five pairs of slacks, and three pairs of shoes, how many different shirt-slacks-shoe combinations does he have? 120
View solution Problem 2
Find the probability of tossing each of the following events: Two tails
View solution