Problem 2
Question
Find the values of \(x\) such that $$ |3 x-9|<0.01 $$
Step-by-Step Solution
Verified Answer
The values of \(x\) that satisfy the inequality are in the interval \((2.9967, 3.0033)\).
1Step 1: Understanding Absolute Value Inequality
To solve the inequality \(|3x - 9| < 0.01\), we start by recalling that an absolute value inequality of the form \(|u| < a\) means \(-a < u < a\). In this problem, \(u = 3x - 9\) and \(a = 0.01\).
2Step 2: Write the Compound Inequality
From the inequality \(|3x - 9| < 0.01\), we write the compound inequality:\[ -0.01 < 3x - 9 < 0.01 \]
3Step 3: Solve the Left Part of the Inequality
Solve \(-0.01 < 3x - 9\):1. Add 9 to both sides to isolate the term involving \(x\): \[ -0.01 + 9 < 3x \] \[ 8.99 < 3x \]2. Divide both sides by 3: \[ x > rac{8.99}{3} \] \[ x > 2.9967 \]
4Step 4: Solve the Right Part of the Inequality
Solve \(3x - 9 < 0.01\):1. Add 9 to both sides: \[ 3x < 0.01 + 9 \] \[ 3x < 9.01 \]2. Divide both sides by 3: \[ x < rac{9.01}{3} \] \[ x < 3.0033 \]
5Step 5: Combine the Solutions
Combine the results from Step 3 and Step 4 to find the interval for \(x\):\[ 2.9967 < x < 3.0033 \]
Key Concepts
Compound InequalitiesSolving InequalitiesAlgebraic Techniques
Compound Inequalities
Compound inequalities involve two separate inequalities united by the word "and" or "or." In math, these compound statements reveal where a variable lies within specified limits. For our inequality, the absolute value form \(|3x - 9| < 0.01\)translates into the compound form \(-0.01 < 3x - 9 < 0.01\).This hinges on the property that \(|u| < a\) implies \(-a < u < a\).
Here, it's all about finding a range of values for \(x\).
Here, it's all about finding a range of values for \(x\).
- The number \(3x - 9\) falls between two bounds: -0.01 and 0.01.
- This tells us precisely how close \(3x - 9\) needs to be to 0.
- Instead of a single outcome, you achieve an interval.
Solving Inequalities
Solving inequalities involves determining the variable's possible values that satisfy the equation's rules. The objective is, essentially, to isolate \(x\). Starting with our compound inequality \(-0.01 < 3x - 9 < 0.01\), we break it into two solid parts:
- The left part: \(-0.01 < 3x - 9\)
- The right part: \(3x - 9 < 0.01\)
- Add 9 to both sides, transferring numbers so that \(x\) is left standing alone.
- Divide by 3 to completely solve for \(x\) in each section.
Algebraic Techniques
Algebraic techniques are essential for untangling intricate problems like inequalities. When we talk about solving the inequality \(|3x - 9| < 0.01\), several algebra skills come into play.First, the absolute value handling shifts into a compound inequality using the basic principle that makes \(-0.01 < 3x - 9 < 0.01\) possible from \(|3x - 9| < 0.01\).
You utilize fundamental skills like:
You utilize fundamental skills like:
- Adding or subtracting numbers to keep the equation balanced while pushing coefficients to one side.
- Dividing through by constants, a crucial step for isolating \(x\).
Other exercises in this chapter
Problem 1
Evaluate the limits in problems. $$ \lim _{x \rightarrow \infty} \frac{2 x^{2}-3 x+5}{x^{4}-2 x+1} $$
View solution Problem 2
Let $$f(x)=x \cos \frac{1}{x}, \quad x \neq 0$$ (a) Use a graphing calculator to sketch the graph of \(y=f(x)\). (b) Use the sandwich theorem to show that $$ \l
View solution Problem 2
Let $$ f(x)=x^{3}-2 x+3, \quad-3 \leq x \leq-1 $$ (a) Graph \(y=f(x)\) for \(-3 \leq x \leq-1\). (b) Use the intermediate-value theorem to conclude that $$ x^{3
View solution Problem 2
In Problems 1-32, use a table or a graph to investigate each limit. $$ \lim _{x \rightarrow 2} \frac{x^{2}+3}{x+2} $$
View solution