Problem 2
Question
Find the moment-generating function for a chi square random variable and use it to show that \(E\left(\chi_{n}^{2}\right)=n\) and \(\operatorname{Var}\left(\chi_{n}^{2}\right)=2 n\).
Step-by-Step Solution
Verified Answer
The moment generating function for a chi-square random variable \(\chi_{n}^{2}\) is \(\left(\frac{1}{\sqrt{1-2t}}\right)^n\) for \(t < 0.5\). Using this function, the expected value of the chi-square variable is \(n\) and the variance is \(2n\).
1Step 1: Determine the moment-generating function (MGF) of a chi-square random variable
If \(X_1, X_2, ..., X_n\) are independent standard normal variables, then the chi-square random variable with \(n\) degrees of freedom, denoted by \(\chi_{n}^{2}\), is \(\chi_{n}^{2} = (X_1^2 + X_2^2 + ... + X_n^2)\). The MGF of \(X_i^2\) is given by \(M(t) = \frac{1}{\sqrt{1-2t}}\) for \(t < 0.5\), therefore, the MGF of \(\chi_{n}^{2}\) is the product of the MGFs of \(X_i^2\) i.e. \(M_{\chi_{n}^{2}}(t) = \left(\frac{1}{\sqrt{1-2t}}\right)^n\) for \(t < 0.5\).
2Step 2: Calculation of the expected value \(E\left(\chi_{n}^{2}\right)\)
The expected value \(E(X)\) of a random variable \(X\) can be calculated as the derivative of the MGF at \(t = 0\). Therefore, \(E\left(\chi_{n}^{2}\right) = \frac{d}{dt}M_{\chi_{n}^{2}}(t)\Big|_{t=0} = \frac{n}{2\sqrt{1-2t}}\Big|_{t=0} = n\). This proves the first half of the second part of the exercise.
3Step 3: Calculation of the variance \(\operatorname{Var}\left(\chi_{n}^{2}\right)\)
Variance \(Var(X)\) of a random variable \(X\) can be computed as the the second derivative of the MGF at \(t = 0\). After applying the variance formula, \(\operatorname{Var}\left(\chi_{n}^{2}\right) = \frac{d^2}{dt^2}M_{\chi_{n}^{2}}(t)\Big|_{t=0} - [E\left(\chi_{n}^{2}\right)]^2 = \frac{2n}{(1-2t)^2}\Big|_{t=0} - n^2 = 2n\). This last step completes the exercise.
Key Concepts
Chi-square distributionExpected valueVariance
Chi-square distribution
The chi-square distribution is a fundamental concept in statistics, especially when working with hypotheses tests and confidence intervals. It's a distribution of a sum of the squares of independent standard normal variables. Consider independent random variables:
Chi-square distributions are positively skewed, especially with fewer degrees of freedom, but they become more symmetric as \(n\) increases. This distribution is widely used in tests like the chi-square test for independence and goodness of fit.
- Each follows a standard normal distribution.
- You square each variable and then sum them.
Chi-square distributions are positively skewed, especially with fewer degrees of freedom, but they become more symmetric as \(n\) increases. This distribution is widely used in tests like the chi-square test for independence and goodness of fit.
Expected value
The expected value, or mean, of a random variable provides a measure of the central tendency. It's similar to the average value you would expect over numerous trials. For the chi-square distribution with \(n\) degrees of freedom, the expected value is straightforward:
Finding the expected value involves using the moment-generating function (MGF) because it simplifies many calculations. By taking the derivative of the MGF for \(\chi^2_n\) and evaluating it at \(t = 0\), you find the mean: \(n\). This step is crucial in understanding the spread and center of the distribution.
- \(E(\chi^2_n) = n\)
Finding the expected value involves using the moment-generating function (MGF) because it simplifies many calculations. By taking the derivative of the MGF for \(\chi^2_n\) and evaluating it at \(t = 0\), you find the mean: \(n\). This step is crucial in understanding the spread and center of the distribution.
Variance
Variance measures the dispersion or spread in a set of random variables. For a chi-square distribution, variance is particularly insightful as it provides a sense of how much variability there is from the mean.
The variance for \(\chi^2_n\) is:
Variance calculation involves understanding both the concepts of MGF and algebraic manipulation. Since it's derived from adding squared standard normal variables, the variance scales linearly with degrees of freedom \(n\). Thus, as \(n\) increases, the variability also increases, doubling at each step.
The variance for \(\chi^2_n\) is:
- \(\operatorname{Var}(\chi^2_n) = 2n\)
Variance calculation involves understanding both the concepts of MGF and algebraic manipulation. Since it's derived from adding squared standard normal variables, the variance scales linearly with degrees of freedom \(n\). Thus, as \(n\) increases, the variability also increases, doubling at each step.
Other exercises in this chapter
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