Problem 2
Question
Find \(\sin 2 x, \cos 2 x,\) and \(\tan 2 x\) under the given conditions.
$$\sin x=-\frac{4}{5} \quad\left(\pi
Step-by-Step Solution
Verified Answer
Question: Find the values of \(\sin 2x, \cos 2x,\) and \(\tan 2x\) given that \(\sin x = -\frac{4}{5}\) and \(\pi < x < \frac{3\pi}{2}\).
Answer: \(\sin 2x = \frac{24}{25}, \cos 2x = -\frac{7}{25}, \tan 2x = -\frac{24}{7}\)
1Step 1: Find the value of \(\cos x\) using Pythagorean identity
Since the given condition is \(\sin x = -\frac{4}{5}\), we can find the value of \(\cos x\) by using the Pythagorean identity: \(\sin^2 x +\cos^2 x =1\). Plugging in \(\sin x\) value, we find:
$$\cos^2 x= 1 - (-\frac{4}{5})^2$$
$$\cos^2 x= 1 - \frac{16}{25}$$
$$\cos^2 x= \frac{9}{25}$$
As \(\cos x\) is negative in the given interval (\(\pi < x < \frac{3\pi}{2}\)), we get \(\cos x = -\frac{3}{5}\).
2Step 2: Calculate \(\sin 2x\) using Double-Angle identity
We'll use the double-angle formula for the sine function: \(\sin 2x = 2 \sin x \cos x\). Now, plug the values of \(\sin x\) and \(\cos x\) into the equation:
$$\sin 2x = 2 \cdot -\frac{4}{5} \cdot -\frac{3}{5}$$
$$\sin 2x = \frac{24}{25}$$
3Step 3: Calculate \(\cos 2x\) using Double-Angle identity
We'll use the double-angle formula for the cosine function: \(\cos 2x = \cos^2 x - \sin^2 x\). Now, plug the values of \(\sin x\) and \(\cos x\) into the equation:
$$\cos 2x = (-\frac{3}{5})^2 - (-\frac{4}{5})^2$$
$$\cos 2x = \frac{9}{25} - \frac{16}{25}$$
$$\cos 2x = -\frac{7}{25}$$
4Step 4: Calculate \(\tan 2x\) using Double-Angle identity
We'll use the double-angle formula for the tangent function: \(\tan 2x = \frac{\sin 2x}{\cos 2x}\). Now, plug the values of \(\sin 2x\) and \(\cos 2x\) into the equation:
$$\tan 2x = \frac{\frac{24}{25}}{-\frac{7}{25}}$$
$$\tan 2x = -\frac{24}{7}$$
#Conclusion#
Under the given conditions, we have found out that \(\sin 2x = \frac{24}{25}\), \(\cos 2x = -\frac{7}{25}\), and \(\tan 2x = -\frac{24}{7}\).
Key Concepts
Double-Angle FormulasPythagorean IdentityTrigonometric Functions
Double-Angle Formulas
Double-angle formulas are crucial tools in trigonometry. They help us express trigonometric functions of doubled angles, such as \(\sin 2x\), \(\cos 2x\), and \(\tan 2x\), using the functions of \(x\). These formulas are derived from sum identities and simplify many problems involving angles.
- For sine, the double-angle formula is \(\sin 2x = 2 \sin x \cos x\). This gives us a way to find the sine of a double angle by multiplying the sine and cosine of the single angle and then doubling the result.
- The cosine formula is \(\cos 2x = \cos^2 x - \sin^2 x\). This illustrates that the cosine of a double angle is the difference of squares of the cosine and sine.
- For tangent, the formula is \(\tan 2x = \frac{2 \tan x}{1 - \tan^2 x}\), which helps in finding the tangent of a doubled angle by knowing the tangent of the angle.
Pythagorean Identity
The Pythagorean identity is one of the fundamental building blocks in trigonometry. It comes from the Pythagorean theorem applied to a unit circle. The identity tells us that:
- \(\sin^2 x + \cos^2 x = 1\)
- \(\cos^2 x = 1 - \sin^2 x\)
Trigonometric Functions
Trigonometric functions like \(\sin x\), \(\cos x\), and \(\tan x\) describe angles in terms of ratios. These functions are essential for understanding wave patterns, sound, light, and cycles in nature.Here's a brief overview:
- Sine (\(\sin x\)): Represents the ratio of the opposite side to the hypotenuse in a right triangle.
- Cosine (\(\cos x\)): Represents the ratio of the adjacent side to the hypotenuse.
- Tangent (\(\tan x\)): Calculated as the ratio of \(\sin x\) to \(\cos x\), representing the slope of the angle in the unit circle.
Other exercises in this chapter
Problem 1
Find all solutions of the equation. $$\sin x=.465$$
View solution Problem 1
$$\text {Find the exact value.}$$ $$\cos \frac{\pi}{12}$$
View solution Problem 2
Find the exact functional value without using a calculator: $$\cos ^{-1} 0$$
View solution Problem 2
Find all solutions of the equation. $$\sin x=.682$$
View solution