Problem 2
Question
Explain the difference between direct variation and inverse variation.
Step-by-Step Solution
Verified Answer
Direct variation: \( y = kx \); both variables increase together. Inverse variation: \( y = \frac{k}{x} \); as one increases, the other decreases.
1Step 1: Understanding Direct Variation
Direct variation occurs when two variables, say \( x \) and \( y \), are related in such a way that as one variable increases, the other also increases. This relationship can be expressed by the formula \( y = kx \), where \( k \) is a constant known as the constant of variation. In this formula, \( y \) is directly proportional to \( x \). For example, if \( k = 3 \), then the equation is \( y = 3x \).
2Step 2: Understanding Inverse Variation
Inverse variation describes a situation where two variables are related such that as one variable increases, the other decreases. The relationship can be captured by the equation \( y = \frac{k}{x} \), where \( k \) is a constant. Here, \( y \) is inversely proportional to \( x \). For example, if \( k = 6 \), then the equation is \( y = \frac{6}{x} \).
3Step 3: Comparing Direct and Inverse Variation
In direct variation, both variables change in the same direction; if \( x \) increases, \( y \) also increases. However, in inverse variation, the variables change in opposite directions; if \( x \) increases, \( y \) decreases. The formulas \( y = kx \) (direct variation) and \( y = \frac{k}{x} \) (inverse variation) show these relationships mathematically.
Key Concepts
Direct VariationInverse VariationProportional Relationships
Direct Variation
Direct variation is a simple and common relationship found in algebra. When two variables have a direct variation relationship, they change in tandem. This means if one variable goes up, the other follows the same path and increases too. The formula that describes this is\[ y = kx \]where \( y \) is directly proportional to \( x \), and \( k \) is a constant, known as "the constant of variation."
- This constant, \( k \), determines how much \( y \) changes for every unit change in \( x \).
- For example, if \( k = 3 \), the equation becomes \( y = 3x \), suggesting that for every increase in \( x \) by 1, \( y \) increases by 3.
Inverse Variation
Inverse variation presents a contrasting idea. Here, as one variable increases, the other decreases. Such a relationship can be described by the formula:\[ y = \frac{k}{x} \]where \( y \) is inversely proportional to \( x \), and \( k \) remains a constant.
- In inverse variation, \( k \) helps balance and define how the change in \( x \) will inversely affect \( y \).
- For instance, with \( k = 6 \), the equation \( y = \frac{6}{x} \) suggests that as \( x \) increases, \( y \) becomes smaller, maintaining the value of the product \( xy = k \).
Proportional Relationships
Proportional relationships are at the core of understanding both direct and inverse variation. In these relationships, the way two variables relate is through a consistent and predictable pattern involving a constant.
- Direct proportionality ensures that the ratio between two quantities stays the same. For example, if the constant \( k = 5 \), then \( \frac{y}{x} = 5 \).
- In inverse proportion, however, it is the product that remains constant. This can be seen as \( xy = k \). In this situation, doubling one variable halves the other.
Other exercises in this chapter
Problem 1
Explain why \(\left\\{(x, y) : x=y^{2}\right\\}\) is not a function but \(\\{(x, y) : \sqrt{x}=y\\}\) is a function.
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Give an example of a function g for which \(2 \mathrm{g}(x) \neq \mathrm{g}(2 x) .\) Give an example of a function \(\mathrm{f}\) for which \(2 \mathrm{f}(x)=\m
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Explain why \((x-h)^{2}+(y-k)^{2}=-4\) is not the equation of a circle.
View solution Problem 2
Christopher said that \(\mathrm{f}(x)=|x-2|\) and \(\mathrm{g}(x)=|x+2|\) are inverse functions after he showed that \(\mathrm{f}(\mathrm{g}(2))=2, \mathrm{f}(\
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