Problem 2
Question
Exer. 1-2: Show that the given sequence is arithmetic, and find the common difference. $$ 53,48,43, \ldots, 58-5 n, \ldots $$
Step-by-Step Solution
Verified Answer
The sequence is arithmetic with a common difference of -5.
1Step 1: Identify the sequence pattern
The sequence given is \( 53, 48, 43, \ldots, 58-5n, \ldots \). We need to check if the sequence is arithmetic by verifying if the difference between consecutive terms is constant.
2Step 2: Calculate the difference between terms
To find the common difference, calculate the difference between the first two terms: \( 48 - 53 = -5 \), and between the second and third terms: \( 43 - 48 = -5 \). The difference is constant.
3Step 3: Confirm the pattern with the general formula
The nth term of the sequence is given by \( 58 - 5n \). For an arithmetic sequence, the nth term can be expressed as \( a + (n-1)d \), where \( a \) is the first term and \( d \) is the common difference. Here, the common difference \( d \) is \(-5\) which matches our earlier calculation.
4Step 4: Verify consistency of the first term
Substitute \( n=1 \) into \( 58-5n \) to get \( 58 - 5 \cdot 1 = 53 \), which matches the first term of the sequence. This consistency confirms the formula is accurate for an arithmetic sequence.
Key Concepts
Common DifferenceArithmetic ProgressionSequence Formula
Common Difference
An arithmetic sequence is a sequence of numbers in which each term, after the first, is obtained by adding a constant difference to the previous term. This constant is known as the 'common difference'. It represents the uniform interval between consecutive numbers in the series.
In our example sequence, the common difference is found by subtracting the previous term from the subsequent term. For example:
In our example sequence, the common difference is found by subtracting the previous term from the subsequent term. For example:
- The difference between the first two terms is calculated as: \( 48 - 53 = -5 \).
- Repeating this calculation for the next pair, \( 43 - 48 = -5 \), shows the difference remains consistent.
Arithmetic Progression
An arithmetic progression (AP) is a sequence of numbers in which the difference of any two successive members is a constant, referred to as the common difference. Fundamentally, this type of sequence is linear, as illustrated by the example provided: 53, 48, 43, ...
Given an arithmetic progression, you can visualize it like stepping down a set of equally spaced stairs. If you start at 53, each step drops you down by 5, matching the consistent negative common difference. Recognizing this regular interval helps identify and validate the consistency of an arithmetic sequence.
In a broader context, AP’s enable mathematicians and students to predict future terms or backtrack to previous ones based on known values. In analytical settings, understanding this pattern applies to various disciplines, including economics, computing, and physics.
Given an arithmetic progression, you can visualize it like stepping down a set of equally spaced stairs. If you start at 53, each step drops you down by 5, matching the consistent negative common difference. Recognizing this regular interval helps identify and validate the consistency of an arithmetic sequence.
In a broader context, AP’s enable mathematicians and students to predict future terms or backtrack to previous ones based on known values. In analytical settings, understanding this pattern applies to various disciplines, including economics, computing, and physics.
Sequence Formula
For arithmetic sequences, mathematical formulas allow you to find any term directly without listing all preceding terms. This formula calculates the nth term of an arithmetic sequence as:\[ a_n = a + (n-1)d \]where:
- \(a_n\) is the nth term,
- \(a\) is the first term of the sequence,
- \(d\) is the common difference,
- \(n\) is the term number.
Other exercises in this chapter
Problem 2
\(P(8,5)\)
View solution Problem 2
Exer. 1-26: Prove that the statement is true for every positive integer \(n\). $$ 1+4+7+\cdots+(3 n-2)=\frac{n(3 n-1)}{2} $$
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Find the \(n\)th term, the fifth term, and the eighth term of the geometric sequence. $$8,4,2,1, \ldots$$
View solution Problem 3
Exer. 1-8: Find the number. $$ C(9,8) $$
View solution