Problem 2
Question
\(\cos (2 x-3)<0\)
Step-by-Step Solution
Verified Answer
The solution to the inequality \(\cos (2x - 3) < 0\) will be \(x > ((π/2 + α +3) / 2)\) and \(x < ((3π/2 + α + 3) / 2)\), for integer \(n\).
1Step 1: Identify the intervals where cosine is negative
Recall that cosine function is negative in the second \((π/2 < x < π)\) and third quadrants \((π < x < 3π/2)\). Therefore, \(\cos (x) < 0\) for \(π/2 < x < 3π/2\). Adding any full period of \(2π\) to these intervals will also give intervals where the cosine is negative.
2Step 2: Adjust for the transformed function
The given function is not simply \(\cos (x)\), but \(\cos (2x - 3)\). This represents a shift and rescaling of the input value. To isolate the input to the cosine function, set \(2x - 3 = α\). So our intervals for negative cosine values become \(π/2 + α < x < 3π/2 + α\). We need to find the values of \(α\) that fall within these intervals.
3Step 3: Solve for x
In the modified form \(2x - 3 = α\), solve for \(x\). The solutions will be \(x > ((π/2 + α +3) / 2)\) and \(x < ((3π/2 + α + 3) / 2)\), for integer \(n\). These are the intervals for which \(\cos (2x - 3) < 0\).
Key Concepts
Cosine FunctionQuadrants in TrigonometryPeriodic Functions
Cosine Function
The cosine function is one of the fundamental trigonometric functions. It is often denoted as \( \cos(x) \), where \( x \) is the angle in radians. The cosine function relates to the x-coordinate of a point on the unit circle.
- Range: The range of \( \cos(x) \) is between -1 and 1.
- Symmetry: Cosine is an even function. This means \( \cos(-x) = \cos(x) \).
- Behavior: It starts from 1 at \( x=0 \), dips to -1, and comes back to 1 again as \( x \) goes from 0 to \( 2\pi \).
Quadrants in Trigonometry
In trigonometry, the coordinate plane is divided into four quadrants. Each quadrant influences the sign of trigonometric functions.
- Quadrant I: All trigonometric functions are positive.
- Quadrant II: Sine is positive, but cosine and tangent are negative.
- Quadrant III: Tangent is positive, but sine and cosine are negative.
- Quadrant IV: Cosine is positive, while sine and tangent are negative.
Periodic Functions
The cosine function is a periodic function, meaning it repeats its values in regular intervals. This periodic nature is crucial for understanding trigonometric inequalities.
- Period: The period of \( \cos(x) \) is \( 2\pi \).
- Repetition: This means every \( 2\pi \) interval, the cosine pattern repeats itself.
- Applications: In equations like \( \cos(2x - 3) < 0 \), adjusting for transformations such as stretching or shifting can change the intervals where cosine is negative.
Other exercises in this chapter
Problem 1
Solve for \(x\) : $$ \sin x>\frac{1}{2} $$
View solution Problem 2
Solve for \(x\) : $$ |\sin x|>|\cos x| $$
View solution Problem 2
Solve for \(x\) : $$ \sin x \geq 1 $$
View solution Problem 3
Solve for \(x\) : $$ \cot x+\frac{\sin x}{\cos x-2} \geq 0 $$
View solution