Problem 2
Question
Cory said that in Example \(3,1-\sin \theta=\frac{\cos ^{2} \theta}{1+\sin \theta}\) could have been shown to be an identity by multiplying the left side by \(\frac{1+\sin \theta}{1+\sin \theta} \cdot\) Do you agree with Cory? Explain why or why not.
Step-by-Step Solution
Verified Answer
Yes, multiplying left side equals right, verifying identity using trigonometric identities.
1Step 1: Understand the Given Expression
We want to determine if multiplying the left side of the equation \(1 - \sin \theta\) by \(\frac{1 + \sin \theta}{1 + \sin \theta}\) will turn it into an identity, meaning the left and the right side are equal.
2Step 2: Multiply the Left Side
To transform \(1 - \sin \theta\), multiply it by \(\frac{1 + \sin \theta}{1 + \sin \theta}\):\[ \left(1 - \sin \theta\right) \cdot \frac{1 + \sin \theta}{1 + \sin \theta} = \frac{(1 - \sin \theta)(1 + \sin \theta)}{1 + \sin \theta}. \]
3Step 3: Apply the Difference of Squares
The numerator \((1 - \sin \theta)(1 + \sin \theta)\) can be expanded using the identity for the difference of squares: \((a - b)(a + b) = a^2 - b^2\). Here, it becomes \(1 - \sin^2 \theta\).
4Step 4: Simplify Using Pythagorean Identity
We know from the Pythagorean identity that \(1 - \sin^2 \theta = \cos^2 \theta\). Substitute this back into the expression:\[ \frac{1 - \sin^2 \theta}{1 + \sin \theta} = \frac{\cos^2 \theta}{1 + \sin \theta}. \]
5Step 5: Verify Equality
The expression we obtained on the left matches the right side of the original equation. Therefore, multiplying \(1 - \sin \theta\) by \(\frac{1 + \sin \theta}{1 + \sin \theta}\) does indeed show the equation is an identity.
Key Concepts
Understanding the Difference of SquaresThe Power of the Pythagorean IdentityMastering Trigonometric Simplification
Understanding the Difference of Squares
The difference of squares is a well-known algebraic identity that allows us to simplify expressions involving products of the form \((a - b)(a + b)\). This identity states that:
It's an essential stepping stone toward applying more complex identities to simplify trigonometric expressions.
- \((a - b)(a + b) = a^2 - b^2\)
- We get \(1^2 - (\sin \theta)^2\).
It's an essential stepping stone toward applying more complex identities to simplify trigonometric expressions.
The Power of the Pythagorean Identity
In trigonometry, the Pythagorean identity is one of the most important identities, and it expresses a fundamental relationship between the sine and cosine functions. It states that:
This is a notable simplification step, as it translates a part of the expression solely in terms of cosine, aligning it directly with the right side of the equation. Therefore, understanding and applying the Pythagorean identity is key to unlocking simplified forms of trigonometric expressions.
- \(\sin^2 \theta + \cos^2 \theta = 1\)
- \(1 - \sin^2 \theta = \cos^2 \theta\)
This is a notable simplification step, as it translates a part of the expression solely in terms of cosine, aligning it directly with the right side of the equation. Therefore, understanding and applying the Pythagorean identity is key to unlocking simplified forms of trigonometric expressions.
Mastering Trigonometric Simplification
Trigonometric simplification involves reducing complex trigonometric expressions to their simplest form. This process often utilizes identities, such as the Pythagorean identity, to make one side of an equation look like the other.
In the given exercise, the goal is to show that \(1 - \sin \theta\) can be transformed to \(\frac{\cos^2 \theta}{1 + \sin \theta}\) by multiplying \(1 - \sin \theta\) by \(\frac{1 + \sin \theta}{1 + \sin \theta}\). This fraction is equivalent to 1, meaning it is essentially multiplying by 1 without changing the value.
By multiplying, we apply the difference of squares and then the Pythagorean identity in succession:
In the given exercise, the goal is to show that \(1 - \sin \theta\) can be transformed to \(\frac{\cos^2 \theta}{1 + \sin \theta}\) by multiplying \(1 - \sin \theta\) by \(\frac{1 + \sin \theta}{1 + \sin \theta}\). This fraction is equivalent to 1, meaning it is essentially multiplying by 1 without changing the value.
By multiplying, we apply the difference of squares and then the Pythagorean identity in succession:
- The numerator becomes \(1 - \sin^2 \theta\) using the difference of squares.
- Then, replace \(1 - \sin^2 \theta\) with \(\cos^2 \theta\) using the Pythagorean identity.
Other exercises in this chapter
Problem 2
Explain why \(\frac{\tan A+\tan B}{1-\tan A \tan B}\) is undefined when \(A=\frac{\pi}{6}\) and \(B=\frac{\pi}{3}\)
View solution Problem 2
Freddy said that \(\sin (A+B)+\sin (A-B)=2 \sin A \cos B .\) Do you agree with Freddy? Justify your answer.
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Germaine said \(\cos (A+B)+\cos (A-B)=2 \cos A \cos B .\) Do you agree with Germaine? Justify your answer.
View solution Problem 2
Emily said that, without finding the values on a calculator, she knows that \(\sin 100^{\circ}=\cos \left(-10^{\circ}\right) .\) Do you agree with Emily? Explai
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