Problem 2
Question
Conjugate acid of \(\mathrm{NH}_{2}^{-}\)is (a) \(\mathrm{NH}_{4}^{+}\) (b) \(\mathrm{NH}_{3}\) (c) \(\mathrm{NH}_{2}\) (d) \(\mathrm{NH}\)
Step-by-Step Solution
Verified Answer
The conjugate acid of \(\mathrm{NH}_{2}^{-}\) is \(\mathrm{NH}_{3}\) (option b).
1Step 1: Understanding Conjugate Acid Concept
The conjugate acid of a base is formed when the base gains a proton (H⁺). Here, we need to determine the conjugate acid of \(\mathrm{NH}_{2}^{-}\). Identify \(\mathrm{NH}_{2}^{-}\) as the base, and then figure out what results when \(\mathrm{NH}_{2}^{-}\) gains a proton.
2Step 2: Add a Proton to the Base
Next, add a proton (H⁺) to \(\mathrm{NH}_{2}^{-}\). Adding a proton to \(\mathrm{NH}_{2}^{-}\) results in the following chemical reaction: \(\mathrm{NH}_{2}^{-} + \mathrm{H}^{+} \rightarrow \mathrm{NH}_{3}\).
3Step 3: Identify the Conjugate Acid
The resulting molecule from Step 2 is \(\mathrm{NH}_{3}\). Therefore, \(\mathrm{NH}_{3}\) is the conjugate acid of \(\mathrm{NH}_{2}^{-}\).
4Step 4: Choose the Correct Option
According to the question, among the given options: (a) \(\mathrm{NH}_{4}^{+}\), (b) \(\mathrm{NH}_{3}\), (c) \(\mathrm{NH}_{2}\), (d) \(\mathrm{NH}\); option (b) \(\mathrm{NH}_{3}\) is the correct conjugate acid of \(\mathrm{NH}_{2}^{-}\).
Key Concepts
Proton TransferAmmonia MoleculeAcid-Base Reactions
Proton Transfer
Proton transfer is a fundamental process in chemistry, especially within the realm of acid-base reactions. It involves the transfer of a hydrogen ion, or proton (H⁺), from one molecule to another. When a base accepts a proton, it becomes a conjugate acid. Let's consider the specific case of \(\mathrm{NH}_{2}^{-}\). This is an anion known as the amide ion, and it acts as a base. During a proton transfer, \(\mathrm{NH}_{2}^{-}\) accepts a proton to form \(\mathrm{NH}_{3}\) (ammonia).
- Proton transfer is central to defining acid and base behavior.
- In the instance of \(\mathrm{NH}_{2}^{-}\), gaining a proton readily demonstrates this process.
Ammonia Molecule
Ammonia (\(\mathrm{NH}_{3}\)) is a small, simple molecule with significant importance in both nature and industry. It is created when a proton is added to the amide ion \(\mathrm{NH}_{2}^{-}\), as we see in acid-base chemistry. In this context, ammonia acts as the conjugate acid.
- Ammonia easily participates in reactions due to its ability to donate and accept protons.
- Its structure consists of one nitrogen atom bonded to three hydrogen atoms, showcasing a trigonal pyramidal shape.
Acid-Base Reactions
Acid-base reactions are essential interactions where acids donate protons and bases accept protons. These reactions often lead to the formation of conjugate acid-base pairs. In our specific example, the amide ion \(\mathrm{NH}_{2}^{-}\) (acting as a base) accepts a proton to become ammonia \(\mathrm{NH}_{3}\), which is the conjugate acid.
- An acid, in the Brønsted-Lowry sense, is any species that donates a proton.
- A base is any species that accepts a proton.
Other exercises in this chapter
Problem 1
Which of these can not be a bronsted acid? (a) \(\mathrm{HCO}_{3}^{-}\) (b) \(\mathrm{HCOO}^{-}\) (c) \(\mathrm{H}_{2} \mathrm{PO}_{3}^{-}\) (d) \(\mathrm{H}_{3
View solution Problem 3
The ionization constant of phenol is higher than that of ethanol because (a) phenoxide ion is bulkier than ethoxide (b) phenoxide ion is stronger base than etho
View solution Problem 4
The ionization constant of phenol is higher than that of ethanol because (a) phenoxide ion is bulkier than ethoxide (b) phenoxide ion is stronger base than etho
View solution Problem 5
Which one of the following orders of acid strength if correct? (a) \(\mathrm{RCOOH}>\mathrm{HC} \equiv \mathrm{CH}>\mathrm{HOH}>\mathrm{ROH}\) (b) \(\mathrm{RCO
View solution