Problem 2
Question
Challenge Write the chemical equation that has the equilibrium constant expression \(K_{\mathrm{eq}}=\frac{[\mathrm{CO}]^{2}\left[\mathrm{O}_{2}\right]}{\left[\mathrm{CO}_{2}\right]^{2}}\).
Step-by-Step Solution
Verified Answer
2CO₂ ↔ 2CO + O₂
1Step 1: Understanding the Equilibrium Constant Expression
Identify the reactants and products based on the equilibrium expression.
- The numerator ([CO]²[O₂]) of the expression represents the concentration of products. This implies that the products are CO and O₂.
- The denominator ([CO₂]²) represents the concentration of reactants. This indicates that CO₂ is the reactant.
2Step 2: Balancing the Chemical Equation
Start with the unbalanced equation based on the equilibrium expression:
CO₂ ↔ CO + O₂.
To balance the chemical equation, ensure the number of atoms of each element on the reactant side equals the number on the product side.
3Step 3: Final Balanced Equation
The balanced chemical equation is achieved by balancing the coefficients: 2CO₂ ↔ 2CO + O₂. This satisfies the requirement of the equilibrium expression, with the concentration of products as CO and O₂, and the concentration of reactants as CO₂, matching the given expression: \[ K_{eq} = \frac{[CO]^2[O_2]}{[CO_2]^2} \]
Key Concepts
Equilibrium ConstantChemical EquationBalancing Chemical Equations
Equilibrium Constant
The equilibrium constant, denoted as \( K_{eq} \), is a value that expresses the ratio of products to reactants at equilibrium for a reversible reaction. It provides insight into the composition of a reaction mixture at equilibrium. Consider the general reversible reaction:\[ aA + bB \rightleftharpoons cC + dD \]The equilibrium constant expression for this reaction is defined in terms of concentrations as:\[ K_{eq} = \frac{[C]^c[D]^d}{[A]^a[B]^b} \]Here, the square brackets \([ ]\) express molar concentrations, and the coefficients \(a, b, c,\) and \(d\) from the balanced chemical equation become the exponents in the equilibrium constant expression.The value of \( K_{eq} \) tells us about the position of equilibrium:
- If \( K_{eq} \) is much greater than 1, the products are favored at equilibrium.
- If \( K_{eq} \) is much less than 1, the reactants are favored.
- If \( K_{eq} \) is around 1, neither reactants nor products are favored.
Chemical Equation
A chemical equation is a symbolic representation of a chemical reaction. It shows the reactants transforming into the products. The equation spells out the substances involved, typically using their chemical formulas.An example of a simple chemical equation is: \[ \text{CO}_2 \rightarrow \text{CO} + \text{O}_2 \]This notation signifies a potential reaction where carbon dioxide (\(\text{CO}_2\)) would break down into carbon monoxide (\(\text{CO}\)) and oxygen (\(\text{O}_2\)).The arrow (\(\rightarrow\)) represents the direction of the reaction—from reactants to products. Sometimes, a double arrow (\(\rightleftharpoons\)) is used to indicate that the reaction can proceed in both directions, emphasizing its reversible nature.Chemical equations enable scientists to:
- Visualize the substances involved in a reaction.
- Identify the nature of chemical transformations.
- Predict the outcome of reactions.
Balancing Chemical Equations
Balancing chemical equations ensures that the Law of Conservation of Mass is respected; that is, matter cannot be created or destroyed. In a balanced equation, the number of each type of atom on the reactant side is equal to the number of each type on the product side. For example, in balancing:\[ \text{CO}_2 \rightarrow \text{CO} + \text{O}_2 \]You notice that on the left side, there are two oxygen atoms and one carbon atom in \(\text{CO}_2\). On the right in \(\text{CO}\) and \(\text{O}_2\), there are three oxygen atoms and one carbon atom. This equation is not balanced.The correctly balanced version would be:\[ 2\text{CO}_2 \rightleftharpoons 2\text{CO} + \text{O}_2 \]Here, the coefficients (the numbers before the compounds) have been adjusted to achieve balance:
- 2 carbon atoms and 4 oxygen atoms on both sides.
Other exercises in this chapter
Problem 1
Write equilibrium constant expressions for these equilibria. \begin{equation} \begin{array}{l}{\text { a. } N_{2} O_{4}(g) \rightleftharpoons 2 N O_{2}(g)} \\\
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Write equilibrium constant expressions for these heterogeneous equilibria. \begin{equation} \begin{array}{l}{\text { a. } C_{10} \mathrm{H}_{8}(\mathrm{s}) \rig
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Challenge Solid iron reacts with chlorine gas to form solid iron(llI) chloride \(\left(\mathrm{FeCl}_{3}\right)\). Write the balanced equation and the equilibri
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Challenge The reaction \(\mathrm{COCl}_{2}(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g})\) reaches equilibrium at 900 \(\ma
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