Problem 2
Question
Adrien said that if the roots of a quadratic equation are \(\frac{1}{2}\) and \(\frac{3}{4}\) , the equation is \(4 x^{2}-5 x+\frac{3}{2}=0 .\) Olivia said that the equation is \(8 x^{2}-10 x+3=0 .\) Who is correct? Justify your answer.
Step-by-Step Solution
Verified Answer
Olivia's equation is correct because both the sum and product of the given roots match her equation's coefficients.
1Step 1: Understanding the problem
We need to determine which quadratic equation, proposed by Adrien or Olivia, is correct given the roots \( \frac{1}{2} \) and \( \frac{3}{4} \). In a quadratic equation, the sum and product of the roots are related to the coefficients. Let's check both equations.
2Step 2: Check the Sum and Product of Roots
For a quadratic equation \( ax^2 + bx + c = 0 \) with roots \( p \) and \( q \), the sum of the roots \( p + q = -\frac{b}{a} \), and the product \( pq = \frac{c}{a} \). For both proposed equations, let's calculate and compare these values to the given roots.
3Step 3: Calculating for Adrien's Equation
Adrien's equation is \( 4x^2 - 5x + \frac{3}{2} = 0 \). Here, \( a = 4, b = -5, c = \frac{3}{2} \). The sum of the roots is \( \frac{1}{2} + \frac{3}{4} = \frac{5}{4} \). We compare this to \( -\frac{b}{a} = \frac{5}{4} \). The product is \( \frac{3}{2} \times 1 = \frac{3}{2} \), which matches \( \frac{c}{a} = \frac{3}{2} / 4 = \frac{3}{8} \), so this does not match.
4Step 4: Calculating for Olivia's Equation
Olivia's equation is \( 8x^2 - 10x + 3 = 0 \). Here, \( a = 8, b = -10, c = 3 \). The sum of the roots \( \frac{1}{2} + \frac{3}{4} = \frac{5}{4} \) matches \( -\frac{b}{a} = \frac{10}{8} = \frac{5}{4} \). The product of the roots \( \frac{1}{2} \times \frac{3}{4} = \frac{3}{8} \) matches \( \frac{c}{a} = \frac{3}{8} \). Olivia is, therefore, correct.
Key Concepts
Roots of a QuadraticSum and Product of RootsQuadratic Equation Coefficients
Roots of a Quadratic
In a quadratic equation of the form \( ax^2 + bx + c = 0 \), the values of \( x \) that satisfy the equation are called the roots. These roots can be real or complex numbers. The quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) can be used to find the roots of any quadratic equation.
The nature of the roots depends on the discriminant \( b^2 - 4ac \):
The nature of the roots depends on the discriminant \( b^2 - 4ac \):
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there are two identical real roots.
- If the discriminant is negative, the roots are complex and not real numbers.
Sum and Product of Roots
The sum and product of the roots of a quadratic equation relate to its coefficients.
For an equation \( ax^2 + bx + c = 0 \) with roots \( p \) and \( q \), the sum of the roots \( p + q \) can be found using the formula \(-\frac{b}{a}\), while the product \( pq \) is equal to \( \frac{c}{a} \).
For an equation \( ax^2 + bx + c = 0 \) with roots \( p \) and \( q \), the sum of the roots \( p + q \) can be found using the formula \(-\frac{b}{a}\), while the product \( pq \) is equal to \( \frac{c}{a} \).
- The sum formula \( p + q = -\frac{b}{a} \) indicates that the sum of the roots correlates with the linear coefficient and is inverted in sign.
- The product formula \( pq = \frac{c}{a} \) contrasts the relation between the roots and the constant term, modified by the leading coefficient.
Quadratic Equation Coefficients
The coefficients \( a, b, \) and \( c \) in the equation \( ax^2 + bx + c = 0 \) play pivotal roles in shaping its graph and nature.
- \(a\): The leading coefficient, dictates the parabola's direction of opening. A positive \(a\) opens upward, while a negative \(a\) opens downward.
- \(b\): This coefficient, in conjunction with \(a\), affects the position and symmetry of the parabola.
- \(c\): The constant term marks the y-intercept of the quadratic graph.
Other exercises in this chapter
Problem 2
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