Problem 2
Question
a. Sarah said that in the set of real numbers, \(\sqrt{a}\) is one of the two equal factors whose product is \(a .\) Therefore, \(\sqrt{a} \cdot \sqrt{a}=a\) for some values of \(a\) . Do you agree with Sarah? Explain why or why not. b. If you agree with Sarah, for which values of \(a\) is the statement true? Explain.
Step-by-Step Solution
Verified Answer
I agree with Sarah, but the statement is true for non-negative values of \(a\) only.
1Step 1: Understand the Notation
Sarah is using the square root notation, which means that for any non-negative real number \(a\), \(\sqrt{a}\) is the principal (or non-negative) square root. This means \(\sqrt{a} \cdot \sqrt{a} = a\) should hold true for non-negative numbers, as square roots are defined for them in the real number set.
2Step 2: Analyze the Possibility
Consider whether \(\sqrt{a} \cdot \sqrt{a} = a\) holds for all real numbers. For this, remember that square roots of negative numbers are not real; thus for negative real numbers, this equation does not apply.
3Step 3: Identify Non-Negative Real Numbers
The equation \(\sqrt{a} \cdot \sqrt{a} = a\) is valid for non-negative real numbers \(a\), as for these \(\sqrt{a}\) is real and positive or zero. Hence, \(a\) must be greater than or equal to zero.
4Step 4: Conclusion
Sarah's statement is true but only for non-negative values of \(a\) since the square root of a negative number is not a real number. Hence, \(a\) should be in the set of non-negative real numbers.
Key Concepts
Square RootsNon-Negative NumbersPrincipal Square RootNegative Numbers
Square Roots
The concept of square roots is fundamental in mathematics. Essentially, the square root of a number is a value that, when multiplied by itself, gives the original number. For example, the square root of 9 is 3 because 3 multiplied by 3 equals 9. In notation, this is expressed as \( \sqrt{9} = 3 \). Understanding this concept is crucial for solving various types of mathematical problems. Here are some important points about square roots:
- Square roots are often represented by the radical symbol \( \sqrt{} \).
- Every positive number has two square roots: one positive and one negative.
- The square root of zero is zero, as \( 0 \times 0 = 0 \).
- Finding a square root is essentially asking, "What number times itself results in the original number?"
Non-Negative Numbers
Non-negative numbers include all the positive numbers and zero. These are numbers that are not less than zero. In terms of square roots, non-negative numbers are extremely significant because square roots are defined for them within the set of real numbers.
- Non-negative numbers make it possible to apply the square root operation directly.
- They include zero, which is a special case where the square root results in zero itself.
- In problem-solving, specifying that a number is non-negative can often simplify calculations.
Principal Square Root
When discussing square roots in the context of real numbers, the principal square root refers to the non-negative square root of a number. For any non-negative real number \( a \), the principal square root is indicated as \( \sqrt{a} \).- This principal square root is always non-negative.- For example, the principal square root of 16 is 4, written as \( \sqrt{16} = 4 \), even though -4 is also a mathematical square root of 16.- The principal square root provides a consistent result that aids in mathematical calculations.Understanding this concept helps avoid errors when working with equations and ensures that we are considering the appropriate value that fits the context of real numbers in most calculations.
Negative Numbers
Negative numbers are all the numbers less than zero. When it comes to square roots, negative numbers introduce a certain level of complexity due to the properties of real numbers.
- In the realm of real numbers, the square root of a negative number is not defined. This is because no real number multiplied by itself gives a negative result.
- For example, there is no real number \( b \) such that \( b \times b = -9 \).
- This limitation is why negative numbers fall outside the scope of the equation \( \sqrt{a} \cdot \sqrt{a} = a \), as formulated within real numbers.
- However, complex numbers extend this idea by introducing the imaginary unit \( i \), where \( i^2 = -1 \), allowing for the square roots of negatives within that context.
Other exercises in this chapter
Problem 2
Jennifer said that if \(a\) is a positive real number, then \(\sqrt[4]{a^{2}}=\sqrt{a} .\) Do you agree with Jennifer? Justify your answer.
View solution Problem 2
To rationalize the denominator of \(\frac{4}{2+\sqrt{8}},\) Brittany multiplied by \(\frac{2-\sqrt{8}}{2}\) and Justin multiplied by \(\frac{1-\sqrt{2}}{1-\sqrt
View solution Problem 2
Show that the quotient of two irrational numbers can be either rational or irrational.
View solution Problem 2
Does \(\sqrt{16}+\sqrt{48}=\sqrt{64} ?\) Justify your answer.
View solution