Problem 2
Question
A ray of light is coming along the line which is parallel to \(y\)-axis and strikes a concave mirror whose intersection with the \(x y\)-plane is a parabola \((x-4)^{2}=4(y+2)\). After reflection, the ray must pass through the point (A) \((4,-1)\) (B) \((0,1)\) (C) \((-4,1)\) (D) none of these
Step-by-Step Solution
Verified Answer
(A) (4,-1) is the correct answer; the ray passes through this point.
1Step 1: Identify the Parabola Equation
The given equation of the parabola is \((x - 4)^2 = 4(y + 2)\). This is a standard parabola equation in the form \((x - h)^2 = 4p(y - k)\), where \((h, k)\) is the vertex. The vertex is at \((4, -2)\) and it opens upwards as the squared term \((x - 4)^2\) is on the left-hand side.
2Step 2: Determine Focus and Directrix
For the standard form \((x - h)^2 = 4p(y - k)\), the focus is at \((h, k + p)\). Here, \(p = 1\), so the focus is at \((4, -1)\). The directrix is the line \(y = k - p\), thus \(y = -3\).
3Step 3: Ray Striking Parallel to y-axis
A ray parallel to the y-axis means it has a direction along the y-axis and it's either moving up or down without changing its x-coordinate. When it strikes the parabola, it will reflect through the focus of the parabola, as this is a property of rays striking a parabolic mirror.
4Step 4: Determine the Ray's Path after Reflection
According to the property of parabolic mirrors, any ray parallel to the axis of the parabola (the y-axis here) will reflect through the focus of the parabola. Since the focus is at \((4, -1)\), the ray will pass through this point after reflection.
5Step 5: Verify the Correct Answer
After reflection, the ray passes through the focus. Checking against the choices, point \((4, -1)\) matches the point we determined as the intersection of the ray path after reflection. Therefore, the correct answer is option (A) \((4, -1)\).
Key Concepts
Parabola EquationFocus of a ParabolaRay Reflection
Parabola Equation
Understanding the equation of a parabola is crucial when working with reflections on concave mirrors. The equation given in the exercise is \((x - 4)^2 = 4(y + 2)\). This particular form is a "standard form" of a parabola that opens upwards. **Standard Form**: It can be generally described as \((x - h)^2 = 4p(y - k)\), where:
- \((h, k)\) is the vertex of the parabola.
- \(p\) represents the distance from the vertex to the focus of the parabola.
Focus of a Parabola
The focus of a parabola is a key point that influences how light rays reflect off the shape. For the parabola \((x - 4)^2 = 4(y + 2)\), once in the standard form \((x - h)^2 = 4p(y - k)\), it's evident that:
- The vertex \((h, k)\) is at \((4, -2)\).
- The parameter \(p = 1\) since \(4p = 4\).
- The focus is positioned at \((h, k + p)\), which calculates to \((4, -1)\).
Ray Reflection
When rays of light strike a concave mirror shaped like a parabola, such as the one in the exercise, they behave in an orderly manner due to the properties of the parabola. If a ray comes parallel to the y-axis, it will reflect through the focus of the parabola:
- The ray strikes the surface, maintaining the x-coordinate, as it is parallel to the y-axis.
- Upon reflection, it passes through the focus, acting according to the laws of optics.
Other exercises in this chapter
Problem 1
Let \(y=f(x)\) be a parabola, having its axis parallel to \(y\)-axis, which is touched by the line \(y=x\) at \(x=1\), then (A) \(f^{\prime}(0)=f^{\prime}(1)\)
View solution Problem 3
If \(y+3=m_{1}(x+2)\) and \(y+3=m_{2}(x+2)\) are two tangents to the parabola \(y^{2}=8 x\), then (A) \(m_{1}+m_{2}=0\) (B) \(m_{1} m_{2}=-1\) (C) \(m_{1} m_{2}
View solution Problem 4
A line bisecting the ordinate \(P N\) of a point \(P\left(a t^{2}, 2 a t\right)\), \(t>0\), on the parabola \(y^{2}=4 a x\) is drawn parallel to the axis to mee
View solution Problem 5
Coordinates of any point on the parabola, whose focus is \(\left(\frac{-3}{2},-3\right)\) and the directrix is \(2 x+5=0\) is given by (A) \(\left(2 t^{2}+2,2 t
View solution