Problem 2
Question
A ray of light is coming along the line which is parallel to \(y\)-axis and strikes a concave mirror whose intersection with the \(x y\)-plane is a parabola \((x-4)^{2}=4(y+2)\). After reflection, the ray must pass through the point (A) \((4,-1)\) (B) \((0,1)\) (C) \((-4,1)\) (D) none of these
Step-by-Step Solution
Verified Answer
The ray must pass through point (4, -1), corresponding to option (A).
1Step 1: Understand the Parabola Equation
The given equation of the parabola is \((x-4)^2 = 4(y+2)\). This is a parabola that opens upwards with its vertex at \((4, -2)\). The focus of the parabola can be calculated using the equation of a parabola \((x-h)^2 = 4p(y-k)\). Here, \(h = 4\), \(k = -2\), and \(4p = 4\), leading to \(p = 1\). Hence, the focus is at \((4, -1)\).
2Step 2: Determine the Path of Incoming Ray
The ray of light is said to be coming parallel to the \(y\)-axis. This implies that the line representing the ray is vertical (such as \(x = k\) where \(k\) is constant) and it's moving towards the parabola.
3Step 3: Reflection Property of Parabolas
Parabolas have the property that any incoming ray parallel to the axis of symmetry of the parabola reflects through its focus. Thus, a ray parallel to the \(y\)-axis striking this parabola will reflect through the parabola's focus point.
4Step 4: Choose the Correct Option
From the properties of the parabola, since the ray after striking the parabola must pass through the focus of the parabola, the correct choice for the reflected ray passing through is point \((4, -1)\), corresponding to option (A).
Key Concepts
Reflection Property of a ParabolaFocus of ParabolaAxis of Symmetry
Reflection Property of a Parabola
A parabola exhibits a fascinating geometric attribute known as the reflection property. This property states that rays of light initially traveling parallel to the parabola's axis of symmetry will reflect towards its focus.
This occurs because of the unique shape of a parabola, where all points are equidistant from a single point (the focus) and a straight line (the directrix).
In practical terms, when a light ray strikes a parabolic reflector such as the one defined by \[(x-4)^2 = 4(y+2)\], the trajectories of these rays are redirected, converging at the parabola's focus.
This principle is critical in various applications like satellite dishes and headlight reflectors, as it ensures that signals or light are concentrated precisely.
This occurs because of the unique shape of a parabola, where all points are equidistant from a single point (the focus) and a straight line (the directrix).
In practical terms, when a light ray strikes a parabolic reflector such as the one defined by \[(x-4)^2 = 4(y+2)\], the trajectories of these rays are redirected, converging at the parabola's focus.
This principle is critical in various applications like satellite dishes and headlight reflectors, as it ensures that signals or light are concentrated precisely.
- Light reflects toward the focus.
- Axis-parallel rays converge precisely at one point.
- This principle underlies the working of various optical devices.
Focus of Parabola
The focus is a pivotal part of a parabola's geometric structure, serving as one of the defining components which the shape revolves around. For the parabola described by the equation \[(x-4)^2 = 4(y+2)\], the focus is determined through the parameter \(p\) in the standard equation form \[(x-h)^2 = 4p(y-k)\].
Here, \(h = 4\) and \(k = -2\), placing the vertex at \((4, -2)\). Since \(4p = 4\), we find that \(p = 1\). Thus, the focus is located at \((4, -1)\).
In essence:
Here, \(h = 4\) and \(k = -2\), placing the vertex at \((4, -2)\). Since \(4p = 4\), we find that \(p = 1\). Thus, the focus is located at \((4, -1)\).
In essence:
- The focus serves as the convergence point for incoming parallel rays due to the reflection property.
- It is used in designing parabolic reflectors in antennas and headlights for optimum focus.
Axis of Symmetry
The axis of symmetry is an essential characteristic of a parabola, dividing it perfectly into two symmetrical halves. For the given parabola \[(x-4)^2 = 4(y+2)\], this line is vertical as the equation is in the form \[(x-h)^2 = 4p(y-k)\].
The axis of symmetry here is the line \(x = 4\), matching the \(x\)-coordinate of the vertex. This line plays a pivotal role because it is along this line that the reflection property operates.
The axis of symmetry here is the line \(x = 4\), matching the \(x\)-coordinate of the vertex. This line plays a pivotal role because it is along this line that the reflection property operates.
- The parabola is symmetrical around this axis.
- Incident rays parallel to this axis are reflected towards the focus.
- Lighting up the symmetry can be key in applications involving light paths and parabolic reflectors.
Other exercises in this chapter
Problem 1
Let \(y=f(x)\) be a parabola, having its axis parallel to \(y\)-axis, which is touched by the line \(y=x\) at \(x=1\), then (A) \(f^{\prime}(0)=f^{\prime}(1)\)
View solution Problem 3
If \(y+3=m_{1}(x+2)\) and \(y+3=m_{2}(x+2)\) are two tangents to the parabola \(y^{2}=8 x\), then (A) \(m_{1}+m_{2}=0\) (B) \(m_{1} m_{2}=-1\) (C) \(m_{1} m_{2}
View solution Problem 4
A line bisecting the ordinate \(P N\) of a point \(P\left(a t^{2}, 2 a t\right)\) \(t>0\), on the parabola \(y^{2}=4 a x\) is drawn parallel to the axis to meet
View solution Problem 6
The mirror image of the directrix of the parabola \(y^{2}=\) \(4(x+1)\) in the line mirror \(x+2 y=3\) is (A) \(x=-2\) (B) \(4 y-3 x=16\) (C) \(3 x+4 y+16=0\) (
View solution