Problem 2
Question
A property of groups is said to be "preserved under homomorphism" if, whenever a group \(G\) has that property, every homomorphic image of \(G\) does also. In this exercise set, we will survey a few typical properties preserved under homomorphism. If \(f: G \rightarrow H\) is a homomorphism of \(G\) onto \(H\), prove each of the following: If \(G\) is cyclic, then \(H\) is cyclic.
Step-by-Step Solution
Verified Answer
If \(G\) is cyclic and \(f: G \rightarrow H\) is a surjective homomorphism, then \(H\) is cyclic, generated by \(f(g)\).
1Step 1: Understand the Concepts
A group \(G\) is cyclic if there exists an element \(g \in G\) such that every element of \(G\) can be written as \(g^n\) for some integer \(n\). A homomorphism \(f: G \rightarrow H\) is a function that respects the group operation, meaning \(f(g_1 \cdot g_2) = f(g_1) \cdot f(g_2)\) for any elements \(g_1, g_2 \in G\). To say \(f\) is surjective (onto) means every element \(h \in H\) has a preimage in \(G\). We aim to prove if \(G\) is cyclic, \(H\) is also cyclic under these conditions.
2Step 2: Define the Cyclic Property of G
Assume \(G\) is cyclic, generated by element \(g\), i.e., \(G = \langle g \rangle\). This means every element of \(G\) can be expressed in the form \(g^n\) for some integer \(n\).
3Step 3: Apply the Homomorphism
The homomorphism \(f: G \rightarrow H\) is surjective, so for every element \(h \in H\), there is an element \(x \in G\) such that \(f(x) = h\). Specifically, for each \(g^n \in G\), compute \(f(g^n) = f(g)^n\). We denote \(f(g) = h_0\), which is some element of \(H\).
4Step 4: Show H is Generated by f(g)
Since \(f\) is onto, every element in \(H\) is of the form \(f(g^n) = (f(g))^n\) because \(f\) respects the group operation \((f(g^m) \cdot f(g^n) = f(g^{m+n}))\). Therefore, \(H\) is generated by the single element \(h_0 = f(g)\), indicating \(H\) is cyclic.
Key Concepts
Cyclic GroupsGroup HomomorphismHomomorphic ImageCyclic Property
Cyclic Groups
Cyclic groups are an essential concept in group theory and appear frequently in mathematical problems. A group is called cyclic if there exists a single element, known as a generator, which can produce every element of the group through repeated application of the group operation. In formal terms, a group \( G \) is cyclic if there is an element \( g \) in \( G \) such that every element \( x \) in \( G \) can be written as \( g^n \) for some integer \( n \).
This means if you choose a generator wisely, you can "build" the entire group from it.
This means if you choose a generator wisely, you can "build" the entire group from it.
- Generators play a crucial role in understanding the structure and order of cyclic groups.
- The simplest example of a cyclic group is the group of integers under addition, \( \mathbb{Z} \), which is generated by the element 1.
- Another notable example is the multiplicative group of units modulo \( n \), denoted as \( \mathbb{Z}_n^* \).
Group Homomorphism
A group homomorphism is a special type of function between two groups that respects the group structure. In simpler terms, if \( f: G \rightarrow H \) is a homomorphism from group \( G \) to group \( H \), this means for any two elements \( a, b \in G \), the function satisfies the property \( f(a \cdot b) = f(a) \cdot f(b) \).
This property ensures that the group operation is maintained under the function.
This property ensures that the group operation is maintained under the function.
- Homomorphisms play a key role in linking different groups and analyzing their properties.
- An important aspect of homomorphisms is whether they are injective (one-to-one) or surjective (onto).
- Surjective homomorphisms allow every element in the target group \( H \) to be possibly mapped from the source group \( G \).
Homomorphic Image
The concept of a homomorphic image comes into play when looking at the result of applying a group homomorphism to a group.
The homomorphic image of a group \( G \) through a homomorphism \( f: G \rightarrow H \) is the subgroup \( H \) itself, assuming \( f \) is surjective.
The homomorphic image of a group \( G \) through a homomorphism \( f: G \rightarrow H \) is the subgroup \( H \) itself, assuming \( f \) is surjective.
- This image retains much of the original group's structure, but it may lose certain details depending on \( f \).
- It is the output of the group \( G \) processed through the function \( f \).
- The image group \( H \) inherits any properties of \( G \) that are preserved under homomorphism, like the cyclic property.
Cyclic Property
The cyclic property, in the context of group theory, specifies that a group's structure can be generated by a single element.
When a group is cyclic, any homomorphic image of the group will also exhibit this cyclic nature, given certain conditions are met, such as surjectivity.
When a group is cyclic, any homomorphic image of the group will also exhibit this cyclic nature, given certain conditions are met, such as surjectivity.
- If \( G \) is cyclic and \( f: G \rightarrow H \) is a surjective homomorphism, then \( H \) will be cyclic as well.
- This holds because if \( G \) is generated by \( g \), then \( f(g) \) will generate \( H \).
- The cyclic nature is a perfect example of a property preserved under homomorphism, showing the power and boundaries of mapping between groups.
Other exercises in this chapter
Problem 1
Prove that each of the following is a homomorphism, and describe its kernel. The function \(\phi: \mathscr{F}(\mathbb{R}) \rightarrow \mathbb{R}\) given by \(\p
View solution Problem 2
If \(G\) is any group, let \(H\) and \(K\) be normal subgroups of \(G\) such that \(H \cap K=\\{e\\}\). Prove the following: For any \(h \in H\) and \(k \in K,
View solution Problem 2
If \(f: G \rightarrow H\) is a homomorphism, prove each of the following: The order of any element \(b \neq e\) in the range of \(f\) is a common divisor of \(|
View solution Problem 2
Let \(G\) denote a group, and \(H\) a subgroup of \(G\). Prove the following: Suppose an element \(a \in G\) has order \(2 .\) Then \(\langle a\rangle\) is a no
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