Problem 2
Question
a point on the terminal side of angle \(\theta\) is given. Find the exact value of each of the six trigonometric functions of \(\theta .\) $$ (-12,5) $$
Step-by-Step Solution
Verified Answer
The exact values of the six trigonometric functions of \(\theta\) are: \(sin(\theta) = \frac{5}{13}, cos(\theta) = -\frac{12}{13}, tan(\theta) = -\frac{5}{12}, csc(\theta) = \frac{13}{5}, sec(\theta) = -\frac{13}{12}, cot(\theta) = -\frac{12}{5}\).
1Step 1: Identify the sides of right triangle
First, the point (-12,5) forms a right triangle with the origin. This is because the x-coordinate corresponds to the adjacent side (-12) and the y-coordinate to the opposite side (5). In this notation, negative values mean that the distance is to the left of the origin for the x-coordinate or below the origin for the y-coordinate.
2Step 2: Calculate the Hypotenuse
Using the Pythagorean theorem, \(c = \sqrt{a^2 + b^2} \), calculate the length of the hypotenuse. In our case, the 'a' corresponds to the x-coordinate which is -12, and 'b' corresponds to the y-coordinate which is 5. Hence, the hypotenuse is \(c = \sqrt{(-12)^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13\).
3Step 3: Calculate Trigonometric Values
The six trigonometric functions of the angle can now be calculated as follows:- Sine (\(sin(\theta)\)) is \( \frac{Opposite}{Hypotenuse} = \frac{5}{13} \),- Cosine (\(cos(\theta)\)) is \( \frac{Adjacent}{Hypotenuse} = \frac{-12}{13} \) because the x-axis value is to the left,- Tangent (\(tan(\theta)\)) is \( \frac{Opposite}{Adjacent} = -\frac{5}{12} \),- Cosecant (\(csc(\theta)\)) is \( \frac{1}{sin(\theta)} = \frac{13}{5} \),- Secant (\(sec(\theta)\)) is \( \frac{1}{cos(\theta)} = -\frac{5}{12} \),- Cotangent (\(cot(\theta)\)) is \( \frac{1}{tan(\theta)} = -\frac{12}{5} \).Note: The negative sign value indicates in which quadrant the angle lies.
Key Concepts
Right TrianglePythagorean TheoremSine Cosine TangentCosecant Secant Cotangent
Right Triangle
A right triangle is a type of triangle that has one angle measuring exactly 90 degrees. This distinct property makes it a fundamental piece in trigonometry. When working with points in the coordinate plane, such as the point \((-12,5)\), you can imagine this point forming a right triangle with the origin (0,0).
Here, the x-coordinate \(-12\) serves as the base (adjacent side) along the x-axis and the y-coordinate \(5\) is the height (opposite side) along the y-axis. These two sides meet at a right angle on the coordinate grid.
Why is this important? The relationship between the sides of a right triangle is what allows trigonometric functions to be defined and used for various calculations.
Here, the x-coordinate \(-12\) serves as the base (adjacent side) along the x-axis and the y-coordinate \(5\) is the height (opposite side) along the y-axis. These two sides meet at a right angle on the coordinate grid.
Why is this important? The relationship between the sides of a right triangle is what allows trigonometric functions to be defined and used for various calculations.
Pythagorean Theorem
The Pythagorean Theorem is a crucial concept in geometry and trigonometry. It describes the relationship between the sides of a right triangle. Mathematically, it is expressed as \(c = \sqrt{a^2 + b^2}\), where \(c\) is the hypotenuse, and \(a\) and \(b\) are the other two sides.
This theorem allows us to calculate the hypotenuse when the other two sides are known. For our example with sides \(-12\) and \(5\), the hypotenuse is determined to be \(13\) using this formula.
The Pythagorean Theorem not only helps with these calculations but is also invaluable in proving concepts related to distance and establishing properties of trigonometric ratios.
This theorem allows us to calculate the hypotenuse when the other two sides are known. For our example with sides \(-12\) and \(5\), the hypotenuse is determined to be \(13\) using this formula.
The Pythagorean Theorem not only helps with these calculations but is also invaluable in proving concepts related to distance and establishing properties of trigonometric ratios.
Sine Cosine Tangent
Sine, cosine, and tangent are the primary trigonometric functions that relate the angles of a right triangle to its side lengths. These functions are defined as:
- Sine \(\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}}\)
- Cosine \(\cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}}\)
- Tangent \(\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}\)
- \(\sin(\theta) = \frac{5}{13}\)
- \(\cos(\theta) = \frac{-12}{13}\)
- \(\tan(\theta) = -\frac{5}{12}\)
Cosecant Secant Cotangent
The secondary trigonometric functions are cosecant, secant, and cotangent, which are the reciprocals of sine, cosine, and tangent:
- Cosecant \(\csc(\theta) = \frac{1}{\sin(\theta)}\)
- Secant \(\sec(\theta) = \frac{1}{\cos(\theta)}\)
- Cotangent \(\cot(\theta) = \frac{1}{\tan(\theta)}\)
- \(\csc(\theta) = \frac{13}{5}\)
- \(\sec(\theta) = -\frac{13}{12}\)
- \(\cot(\theta) = -\frac{12}{5}\)
Other exercises in this chapter
Problem 2
Find the exact value of each expression. $$ \sin ^{-1} 0 $$
View solution Problem 2
Determine the amplitude of each function. Then graph the function and \(y=\sin x\) in the same rectangular coordinate system for \(0 \leq x \leq 2 \pi\) $$y=5 \
View solution Problem 2
In Exercises \(1-6,\) the measure of an angle is given. Classify the angle as acute, right, obtuse, or straight. $$ 177^{\circ} $$
View solution Problem 3
Find the exact value of each expression. $$ \sin ^{-1} \frac{\sqrt{2}}{2} $$
View solution