Problem 2
Question
A particle \(A\) of mass \(3 m\) is suspended from a fixed point \(O\) by a spring of strength \(\alpha\) and a second particle \(B\) of mass \(2 m\) is suspended from \(A\) by a second identical spring. The system performs small oscillations in the vertical straight line through \(O\). Find the normal frequencies, the forms of the normal modes, and a set of normal coordinates.
Step-by-Step Solution
Verified Answer
The normal frequencies are given by the square roots of the eigenvalues of the coefficient matrix for the system of differential equations of motion. The forms of normal modes are described by the corresponding eigenvectors. Normal coordinates correspond to these eigenvectors and they execute simple harmonic motion independently.
1Step 1: Formula representation
Start by representing the system mathematically. The equation for the motion of the upper mass \(A\) is given by \[a_1 = \frac{{d^2x_1}}{{dt^2}} = \frac{{α(2x_2-x_1)}}{{3m}}\] and the motion of the lower mass \(B\) is \[a_2 = \frac{{d^2x_2}}{{dt^2}} = \frac{{α(x_1 - 2x_2)}}{{2m}}\]. Here, \(x_1\) and \(x_2\) are the displacements of \(A\) and \(B\) respectively from the equilibrium position. The above equations can be written in the matrix form as follows: \[\begin{bmatrix} \frac{{d^2x_1}}{{dt^2}} \ \frac{{d^2x_2}}{{dt^2}} \end{bmatrix} = -\frac{α}{m}\begin{bmatrix} 1/3 & -2/3 \ -1/2 & 1 \end{bmatrix}\begin{bmatrix} x_1 \ x_2 \end{bmatrix}\]
2Step 2: Solving the Matrix
Now, let's solve the characteristic equation for the matrix to get the normal frequencies. The characteristic equation from the above system is given by \[| \frac{α}{m}I - A| = 0\] Solving this equation gives us the eigenvalues \(λ_1\) and \(λ_2\). The normal (or natural) frequencies \(w_1\) and \(w_2\) are the square roots of \(λ_1\) and \(λ_2\) respectively.
3Step 3: Forms of the Normal Modes
Calculate the eigenvectors (which describe the forms of the normal modes) by substituting each eigenvalues into the equation \[(\frac{α}{m}I - A)v = 0\] These eigenvectors form a new coordinate system (normal coordinate system) in which each coordinate executes simple harmonic motion independently.
4Step 4: Finding Normal Coordinates
To find the normal coordinates, make a change of variables to the new set of coordinates corresponding to the eigenvectors found above. The new variables (or the normal coordinates) decouple the equations of motion, that is, they execute simple harmonic motion independently.
Key Concepts
Understanding Small OscillationsNormal Frequencies and Their SignificanceEigenvalues and Eigenvectors: Keys to Resolving Oscillatory MotionsSimple Harmonic Motion: The Foundation of Oscillation AnalysisCharacteristic Equation and Its Role in Oscillatory SystemsMatrix Representation of Oscillations in Coupled SystemsThe Physical Pendulum and Its Comparison to the Oscillators
Understanding Small Oscillations
Small oscillations occur when a system is displaced slightly from its equilibrium position, resulting in oscillatory motion around that position. In the context of coupled oscillators, like our particles A and B, this assumption simplifies the problem by linearizing the equations of motion.
This approach is valid because the forces responsible for the oscillations can be approximated as being directly proportional to the displacement from equilibrium – a hallmark of harmonic motion. Essentially, when the displacements \(x_1\) and \(x_2\) are small, the complex interplay between particles can be effectively described using linear algebra.
This approach is valid because the forces responsible for the oscillations can be approximated as being directly proportional to the displacement from equilibrium – a hallmark of harmonic motion. Essentially, when the displacements \(x_1\) and \(x_2\) are small, the complex interplay between particles can be effectively described using linear algebra.
Normal Frequencies and Their Significance
Normal frequencies, often denoted as \(\omega\), are vital in understanding the behavior of coupled oscillators. They represent the intrinsic frequencies at which the system naturally oscillates when disturbed. In our particle system, finding these frequencies revealed how particle A and B oscillate with respect to each other.
These frequencies are unique to the system and are significant because once identified, they allow us to predict the behavior of the system under oscillation without external forces. In the exercise, the calculation of normal frequencies involves solving the characteristic equation which stems from matrix representation of oscillations.
These frequencies are unique to the system and are significant because once identified, they allow us to predict the behavior of the system under oscillation without external forces. In the exercise, the calculation of normal frequencies involves solving the characteristic equation which stems from matrix representation of oscillations.
Eigenvalues and Eigenvectors: Keys to Resolving Oscillatory Motions
The terms eigenvalues (\(\lambda\)) and eigenvectors are central to the analysis of oscillatory systems in physics. Eigenvalues are obtained by solving the characteristic equation of the system's matrix, and they relate directly to the square of the normal frequencies of oscillations.
Eigenvectors, on the other hand, give us the forms of the normal modes – the independent oscillation patterns the system can exhibit. When we determine the eigenvectors, we find the specific way in which each particle moves during each normal mode. In the solution provided, the eigenvectors help establish a set of normal coordinates which simplifies the overall coupled motion into individually recognizable harmonic motions.
Eigenvectors, on the other hand, give us the forms of the normal modes – the independent oscillation patterns the system can exhibit. When we determine the eigenvectors, we find the specific way in which each particle moves during each normal mode. In the solution provided, the eigenvectors help establish a set of normal coordinates which simplifies the overall coupled motion into individually recognizable harmonic motions.
Simple Harmonic Motion: The Foundation of Oscillation Analysis
Simple harmonic motion (SHM) constitutes a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to the displacement. It can be described by the linear differential equation \(\frac{d^2x}{dt^2} + \omega^2x = 0\), where \(x\) is the displacement.
In the context of our problem, simple harmonic motion is what each normal coordinate undergoes once we have transformed our initial complex system into a decoupled one, via the normal coordinates associated with the eigenvectors.
In the context of our problem, simple harmonic motion is what each normal coordinate undergoes once we have transformed our initial complex system into a decoupled one, via the normal coordinates associated with the eigenvectors.
Characteristic Equation and Its Role in Oscillatory Systems
The characteristic equation is derived from the matrix that represents the coupled oscillations. It is a determinant equation of the form \(\lvert \frac{\alpha}{m}I - A \rvert = 0\), and its solution yields the eigenvalues. In our exercise, these eigenvalues are crucial because they are connected to the normal frequencies of the system.
By solving the characteristic equation, we find the values that the frequencies can take, which are fundamentally linked to how energy is exchanged within the system during oscillation. The process of solving the equation leads us to the values of \(\lambda_1\) and \(\lambda_2\) in the step-by-step solution provided.
By solving the characteristic equation, we find the values that the frequencies can take, which are fundamentally linked to how energy is exchanged within the system during oscillation. The process of solving the equation leads us to the values of \(\lambda_1\) and \(\lambda_2\) in the step-by-step solution provided.
Matrix Representation of Oscillations in Coupled Systems
To analyze the oscillations of coupled systems, it's practical to use matrix representation. The matrix embodies how the forces are translated between different parts of the system during displacement. In our problem, a 2x2 matrix relates the accelerations and displacements of masses A and B.
The matrix model simplifies otherwise complex calculations because it allows the use of linear algebra techniques to determine the behavior of the system. By finding the eigenvalues and eigenvectors of this matrix, we can decipher the normal modes and frequencies of oscillation, resulting in a clearer understanding of the system dynamics.
The matrix model simplifies otherwise complex calculations because it allows the use of linear algebra techniques to determine the behavior of the system. By finding the eigenvalues and eigenvectors of this matrix, we can decipher the normal modes and frequencies of oscillation, resulting in a clearer understanding of the system dynamics.
The Physical Pendulum and Its Comparison to the Oscillators
A physical pendulum is an extended rigid body swinging about a pivot point under the influence of gravity. It contrasts with our problem, which deals with masses connected by springs. Yet, both can exhibit small oscillations. For a physical pendulum, the oscillation frequency depends on its moment of inertia and the distance between the pivot point and the center of mass.
While the physical pendulum is a gravity-driven oscillator, our spring-mass system relies on elastic restoring forces. Nonetheless, both systems can be described using similar mathematical tools for analyzing small oscillations and, when idealized, both follow simple harmonic motion under small angle approximations.
While the physical pendulum is a gravity-driven oscillator, our spring-mass system relies on elastic restoring forces. Nonetheless, both systems can be described using similar mathematical tools for analyzing small oscillations and, when idealized, both follow simple harmonic motion under small angle approximations.
Other exercises in this chapter
Problem 1
A particle \(P\) of mass \(3 m\) is connected to a particle \(Q\) of mass \(8 m\) by a light elastic spring of natural length \(a\) and strength \(\alpha\). Two
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Rod pendulum A uniform rod of length \(2 a\) is suspended from a fixed point \(O\) by a light inextensible string of length \(b\) attached to one of its ends. T
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Triple pendulum A triple pendulum has three strings of equal length \(a\) and the three particles (starting from the top) have masses \(6 m, 2 m, m\) respective
View solution Problem 6
A rod of mass \(M\) and length \(L\) is suspended from two fixed points at the same horizontal level and a distance \(L\) apart by two equal strings of length \
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