Problem 2
Question
\(1-12\) : Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in Example \(1 .\) $$ \sin 15^{\circ} $$
Step-by-Step Solution
Verified Answer
\( \sin(15^{\circ}) = \frac{\sqrt{6} - \sqrt{2}}{4} \).
1Step 1: Identify Trigonometric Identities
The exercise requires us to use an addition or subtraction formula to find the exact value of \( \sin 15^{\circ} \). Relevant trigonometric identities to consider are the angle addition and subtraction formulas.\[\sin(\alpha \pm \beta) = \sin\alpha \cos\beta \pm \cos\alpha \sin\beta\]To write 15° as a sum or difference of angles, we can choose 15° as \(45^{\circ} - 30^{\circ}\).
2Step 2: Apply the Sine Subtraction Formula
Use the subtraction formula for sine with \( \alpha = 45^{\circ} \) and \( \beta = 30^{\circ} \). Applying the formula gives: \[\sin(15^{\circ}) = \sin(45^{\circ} - 30^{\circ}) = \sin 45^{\circ} \cos 30^{\circ} - \cos 45^{\circ} \sin 30^{\circ}\]
3Step 3: Substitute Known Values
Substitute the known trigonometric values: \( \sin 45^{\circ} = \frac{\sqrt{2}}{2} \), \( \cos 30^{\circ} = \frac{\sqrt{3}}{2} \), \( \cos 45^{\circ} = \frac{\sqrt{2}}{2} \), and \( \sin 30^{\circ} = \frac{1}{2} \). This gives: \[\sin(15^{\circ}) = \left(\frac{\sqrt{2}}{2}\right) \left(\frac{\sqrt{3}}{2}\right) - \left(\frac{\sqrt{2}}{2}\right) \left(\frac{1}{2}\right)\]
4Step 4: Simplify the Expression
Simplify the products and combine the terms: \[\sin(15^{\circ}) = \frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4} = \frac{\sqrt{6} - \sqrt{2}}{4}\] This is the exact value of \( \sin(15^{\circ}) \).
Key Concepts
Angle Addition FormulaAngle Subtraction FormulaExact Values of Trigonometric Functions
Angle Addition Formula
The angle addition formula is extremely useful in trigonometry because it allows us to calculate the trigonometric functions of non-standard angles. For the sine function, the addition formula is expressed as:\[\sin(\alpha + \beta) = \sin\alpha \cos\beta + \cos\alpha \sin\beta\]This formula can be a bit tricky at first, but it breaks down the problem by using angles whose exact trigonometric values we already know. Let's see how it works:
- Pick two angles \( \alpha \) and \( \beta \) to add together to create the angle you're interested in.
- Use known sine and cosine values for these angles to fill in the formula.
Angle Subtraction Formula
The angle subtraction formula is similar to the angle addition formula, but it involves subtracting one angle from another. For the sine function, the angle subtraction formula is:\[\sin(\alpha - \beta) = \sin\alpha \cos\beta - \cos\alpha \sin\beta\]This formula is essential for finding the exact values of sine for angles like 15° or 75°, which are not available directly in common trigonometric tables. To use the angle subtraction formula effectively:
- Select angles \( \alpha \) and \( \beta \) that you know, which subtract to give the desired angle.
- Substitute their known trigonometric values into the formula.
- Simplify the result to find the exact value.
- Express 15° as 45° - 30°.
- Using the formula, compute \( \sin(45^{\circ} - 30^{\circ}) \).
Exact Values of Trigonometric Functions
To solve trigonometric problems like finding \( \sin(15^{\circ}) \) using the angle subtraction formula, it's crucial to know the exact values of some common angles. Here are a few examples with their trigonometric functions:
- \( \sin 30^{\circ} = \frac{1}{2} \)
- \( \cos 30^{\circ} = \frac{\sqrt{3}}{2} \)
- \( \sin 45^{\circ} = \frac{\sqrt{2}}{2} \)
- \( \cos 45^{\circ} = \frac{\sqrt{2}}{2} \)
Other exercises in this chapter
Problem 2
Find all solutions of the equation. $$\sin x+1=0$$
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1-8 Find \(\sin 2 x, \cos 2 x,\) and \(\tan 2 x\) from the given information. \(\tan x=-\frac{4}{3}, \quad x\) in quadrant \(\Pi\)
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