Problem 199
Question
The main oxides formed on comustion of \(\mathrm{Li}, \mathrm{Na}\) and \(\mathrm{K}\) in excess of air are, respectively: (a) \(\mathrm{LiO}_{2}, \mathrm{Na}_{2} \mathrm{O}_{2}\) and \(\mathrm{K}_{2} \mathrm{O}\) (b) \(\mathrm{Li}_{2} \mathrm{O}_{2}, \mathrm{Na}_{2} \mathrm{O}_{2}\) and \(\mathrm{KO}_{2}\) (c) \(\mathrm{Li}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O}_{2}\) and \(\mathrm{KO}_{2}\) (d) \(\mathrm{Li}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O}\) and \(\mathrm{KO}_{2}\)
Step-by-Step Solution
Verified Answer
The correct answer is (c): \(\mathrm{Li}_2\mathrm{O}, \mathrm{Na}_2\mathrm{O}_2\), and \(\mathrm{KO}_2\).
1Step 1: Determine Lithium Oxide
Lithium \((\mathrm{Li})\) reacts with oxygen \((\mathrm{O}_2)\) in excess air to primarily form lithium oxide \((\mathrm{Li}_2\mathrm{O})\). The balanced equation for this reaction is: \(4\mathrm{Li} + \mathrm{O}_2 \rightarrow 2\mathrm{Li}_2\mathrm{O}\).
2Step 2: Determine Sodium Oxide
Sodium \((\mathrm{Na})\), when burned in excess air, forms sodium peroxide \((\mathrm{Na}_2\mathrm{O}_2)\) as the primary oxide. The balanced equation is: \(2\mathrm{Na} + \mathrm{O}_2 \rightarrow \mathrm{Na}_2\mathrm{O}_2\).
3Step 3: Determine Potassium Oxide
Potassium \((\mathrm{K})\) reacts with excess oxygen to form potassium superoxide \((\mathrm{KO}_2)\). The balanced reaction is: \(\mathrm{K} + \mathrm{O}_2 \rightarrow \mathrm{KO}_2\).
4Step 4: Match Oxides to Choices
From our analysis: Lithium forms \(\mathrm{Li}_2\mathrm{O}\), Sodium forms \(\mathrm{Na}_2\mathrm{O}_2\), and Potassium forms \(\mathrm{KO}_2\). Reviewing the given choices, the pattern matches option (c): \(\mathrm{Li}_2\mathrm{O}, \mathrm{Na}_2\mathrm{O}_2\), and \(\mathrm{KO}_2\).
Key Concepts
Lithium OxideSodium PeroxidePotassium Superoxide
Lithium Oxide
Lithium oxide, written chemically as \( \mathrm{Li}_2\mathrm{O} \), is the primary oxide that forms when lithium reacts with oxygen. To create lithium oxide, lithium metal is combusted in the presence of excess oxygen. The reaction is straightforward and can be expressed by the equation:
- \( 4\mathrm{Li} + \mathrm{O}_2 \rightarrow 2\mathrm{Li}_2\mathrm{O} \)
Sodium Peroxide
Sodium peroxide, \( \mathrm{Na}_2\mathrm{O}_2 \), is the main oxide of sodium formed when sodium is burned in an excess of air. Here, sodium and oxygen combine to form this compound, which occurs through the reaction:
- \( 2\mathrm{Na} + \mathrm{O}_2 \rightarrow \mathrm{Na}_2\mathrm{O}_2 \)
Potassium Superoxide
Potassium superoxide, represented as \( \mathrm{KO}_2 \), is particularly interesting among alkali metal oxides due to its unique properties. This superoxide is formed when potassium reacts with oxygen, as depicted in the equation:
- \( \mathrm{K} + \mathrm{O}_2 \rightarrow \mathrm{KO}_2 \)
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