Problem 197
Question
The reaction of toluene with \(\mathrm{Cl}_{2}\) in presence of \(\mathrm{FeCl}_{3}\) gives predominantly: (a) benzyl chloride (b) 0 - and p-chlorotoluene (c) m-chlorotoluene (d) benzoyl chloride
Step-by-Step Solution
Verified Answer
The correct answer is (b) o- and p-chlorotoluene.
1Step 1: Understanding the Reaction Process
The reaction involves toluene and chlorine in the presence of a catalyst, ferric chloride (\(\mathrm{FeCl}_3\)). This setup is typical of an electrophilic aromatic substitution reaction, which introduces a chlorine atom into the aromatic ring of toluene.
2Step 2: Identifying the Electrophilic Aromatic Substitution Mechanism
Electrophilic aromatic substitution in the presence of \(\mathrm{FeCl}_3\) leads to the formation of a chloronium ion, which attacks the aromatic ring. Toluene, being an aromatic compound, will have its methyl group acting as an electron-donating group (EDG) and directing the incoming chlorine atom towards the ortho and para positions. This is due to the methyl group increasing electron density at these positions relative to the meta position.
3Step 3: Recognizing Substitution Products
For aromatic substitution reactions in toluene, the major products are ortho- and para-chlorotoluene. This occurs because the methyl group on toluene directs electrophilic attack to the ortho and para positions, favoring these products.
4Step 4: Selecting the Correct Option
Upon understanding that the reaction predominantly yields ortho- and para-chlorotoluene, we can see that the correct answer choice must be (b) o- and p-chlorotoluene.
Key Concepts
Toluene chlorinationOrtho-para directorsReaction mechanisms
Toluene chlorination
When toluene undergoes chlorination, the chemical reaction takes place in the presence of chlorine gas ( \(\mathrm{Cl}_2 \)) and a catalyst like ferric chloride ( \(\mathrm{FeCl}_3 \)). The chlorination of toluene is an example of an electrophilic aromatic substitution reaction. In this process, chlorine atoms are introduced into the aromatic ring of toluene, forming chlorotoluene isomers.
- The catalyst, \(\mathrm{FeCl}_3 \), plays a crucial role by generating the electrophile, which is the chloronium ion in this context, making the aromatic ring more receptive to substitution.
- Toluene has a methyl group attached to the benzene ring, enhancing the electron cloud and making it more reactive under these conditions.
Ortho-para directors
In electrophilic aromatic substitution reactions, the presence of substituents affects where new atoms are added to the aromatic ring. Substituents can be categorized as ortho-para directors or meta directors based on how they influence incoming groups.
- Ortho-Para Directors: These are typically electron-donating groups (EDGs), such as the methyl group on toluene, which direct incoming electrophiles to the ortho (adjacent) and para (opposite) positions on the ring relative to themselves.
- The increased electron density at the ortho and para positions makes them more attractive to electrophiles, leading to faster and more favorable reactions at these sites.
Reaction mechanisms
Understanding reaction mechanisms is crucial to predicting the outcomes of chemical reactions. In electrophilic aromatic substitution, the reaction mechanism involves several key steps that transform reactants into products.
- Step 1: Formation of Electrophile - The chlorine molecule ( \(\mathrm{Cl}_2 \)) interacts with the catalyst ( \(\mathrm{FeCl}_3 \)) to form a chloronium ion, which is the active electrophile.
- Step 2: Electrophile Attack - The chloronium ion attacks the aromatic ring of toluene. The electron-donating nature of the methyl group directs the attack to the ortho and para positions.
- Step 3: Deprotonation - To restore aromaticity, a proton is removed from the intermediate cationic complex, finalizing the substitution process and yielding chlorotoluene.
Other exercises in this chapter
Problem 194
Reaction of one molecule of HBr with one molecule of 1,3 -butadiene at \(40^{\circ} \mathrm{C}\) gives predominantly (a) 3-bromobutene under kinetically control
View solution Problem 195
HBr reacts with \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{OCH}_{3}\) under anhydrous conditions at room temperature to give (a) \(\mathrm{CH}_{3} \mathrm{CHO}\) and
View solution Problem 198
The compound formed as a result of oxidation of ethyl benzene by \(\mathrm{KMnO}_{4}\) is: (a) acetophenone (b) benzoic acid (c) benzyl alcohol (d) benzophenone
View solution Problem 199
Which of the following reactions will yield 2,2 dibromopropane? \(\quad\) (a) \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHBr}+\mathrm{HBr} \longrightarrow\) (b) \(\
View solution