Problem 196
Question
In the following exercises, simplify. $$ \frac{1}{3} \sqrt{24}+\frac{1}{4} \sqrt{54} $$
Step-by-Step Solution
Verified Answer
\( \frac{17 \sqrt{6}}{12} \)
1Step 1 - Simplify the Radicals
Start by simplifying the radicals. Notice that \( \sqrt{24} \) can be written as \( \sqrt{4 \cdot 6} = \sqrt{4} \cdot \sqrt{6} = 2 \sqrt{6} \). Similarly, \( \sqrt{54} \) can be written as \( \sqrt{9 \cdot 6} = \sqrt{9} \cdot \sqrt{6} = 3 \sqrt{6} \).
2Step 2 - Substitute Simplified Radicals
Substitute the simplified radicals back into the expression: \( \frac{1}{3} \cdot 2 \sqrt{6} + \frac{1}{4} \cdot 3 \sqrt{6} \).
3Step 3 - Multiply the Coefficients
Multiply the coefficients to simplify each term: \( \frac{1}{3} \cdot 2 \sqrt{6} = \frac{2 \sqrt{6}}{3} \) and \( \frac{1}{4} \cdot 3 \sqrt{6} = \frac{3 \sqrt{6}}{4} \).
4Step 4 - Find a Common Denominator
To combine the terms, find a common denominator. The common denominator for 3 and 4 is 12. Rewrite each fraction with this common denominator: \( \frac{2 \sqrt{6}}{3} = \frac{8 \sqrt{6}}{12} \) and \( \frac{3 \sqrt{6}}{4} = \frac{9 \sqrt{6}}{12} \).
5Step 5 - Combine the Terms
Add the fractions together by combining the numerators: \( \frac{8 \sqrt{6}}{12} + \frac{9 \sqrt{6}}{12} = \frac{17 \sqrt{6}}{12} \). The final simplified form is \( \frac{17 \sqrt{6}}{12} \).
Key Concepts
Understanding Radical ExpressionsFinding Common DenominatorsAdding Fractions
Understanding Radical Expressions
A radical expression involves a root, most commonly the square root. In our problem, we start with the square roots of 24 and 54. To simplify these radicals, we break down each number into its prime factors. For example, 24 can be written as \( 24 = 4 \times 6 \), where 4 is a perfect square. Taking the square root of 4 gives us 2, making the simplified form \( 2 \times \sqrt{6} \). Similarly, 54 can be broken down into \( 9 \times 6 \). The square root of 9 is 3, hence simplifying \( \sqrt{54} \) to \( 3 \sqrt{6} \).
Simplifying radical expressions helps in making further mathematical operations, like addition and subtraction, more straightforward. Always look for perfect squares within the radical that can be simplified.
Simplifying radical expressions helps in making further mathematical operations, like addition and subtraction, more straightforward. Always look for perfect squares within the radical that can be simplified.
Finding Common Denominators
When dealing with fractions, a common denominator is essential for addition or subtraction. A common denominator is a shared multiple of the denominators of the fractions involved. In our problem, after simplifying the radicals, we are left with fractions \( \frac{2 \sqrt{6}}{3} \) and \( \frac{3 \sqrt{6}}{4} \).
To add these, we need the same denominator. The least common multiple (LCM) of 3 and 4 is 12. Converting each fraction:
To add these, we need the same denominator. The least common multiple (LCM) of 3 and 4 is 12. Converting each fraction:
- For \( \frac{2 \sqrt{6}}{3} \), multiply the numerator and the denominator by 4 to get \( \frac{8 \sqrt{6}}{12} \)
- For \( \frac{3 \sqrt{6}}{4} \), multiply the numerator and the denominator by 3 to get \( \frac{9 \sqrt{6}}{12} \)
Adding Fractions
Once you've found a common denominator, adding fractions becomes a matter of combining the numerators while keeping the denominator the same. From our previous steps, we have:
Here’s key advice: always check that the denominators match before adding or subtracting fractions. This ensures the operation is mathematically sound and simplifies the process significantly.
- \( \frac{8 \sqrt{6}}{12} \)
- \( \frac{9 \sqrt{6}}{12} \)
Here’s key advice: always check that the denominators match before adding or subtracting fractions. This ensures the operation is mathematically sound and simplifies the process significantly.
Other exercises in this chapter
Problem 194
In the following exercises, simplify. $$ \frac{1}{8} \sqrt{32}-\frac{1}{10} \sqrt{50} $$
View solution Problem 195
In the following exercises, simplify. $$ \frac{1}{4} \sqrt{98}-\frac{1}{3} \sqrt{128} $$
View solution Problem 197
In the following exercises, simplify. $$ \sqrt{72 a^{5}}-\sqrt{50 a^{5}} $$
View solution Problem 198
In the following exercises, simplify. $$ \sqrt{48 b^{5}}-\sqrt{75 b^{5}} $$
View solution