Problem 195
Question
Which one of the following species is diamagnetic in nature? 2 (a) \(\mathrm{H}_{2}^{-}\) (b) \(\mathrm{H}_{2}\) (c) \(\mathrm{H}_{2}^{+}\) (d) \(\mathrm{He}_{2}^{+}\)
Step-by-Step Solution
Verified Answer
The species \\(\mathrm{H}_{2}\\) is diamagnetic.
1Step 1: Define Diamagnetic
A diamagnetic species is one that does not have any unpaired electrons. It is repelled by a magnetic field due to the absence of unpaired electrons.
2Step 2: Determine Molecular Orbital Configuration
Using molecular orbital theory, determine the electron configuration for each option. Diamagnetic species will have fully paired electrons in molecular orbitals.
3Step 3: Evaluate \\(\mathrm{H}_{2}^{-}\\)
For \(\mathrm{H}_{2}^{-}\), construct the molecular orbitals: - It has 3 electrons. - The configuration is \(\sigma_{1s}^2\, \sigma^*_{1s}^1\).- It has one unpaired electron, so it is paramagnetic.
4Step 4: Evaluate \\(\mathrm{H}_{2}\\)
For \(\mathrm{H}_{2}\), construct the molecular orbitals: - It has 2 electrons.- The configuration is \(\sigma_{1s}^2\).- All electrons are paired, so it is diamagnetic.
5Step 5: Evaluate \\(\mathrm{H}_{2}^{+}\\)
For \(\mathrm{H}_{2}^{+}\), construct the molecular orbitals:- It has 1 electron.- The configuration is \(\sigma_{1s}^1\).- It has one unpaired electron, so it is paramagnetic.
6Step 6: Evaluate \\(\mathrm{He}_{2}^{+}\\)
For \(\mathrm{He}_{2}^{+}\), construct the molecular orbitals:- It has 3 electrons.- The configuration is \(\sigma_{1s}^2\, \sigma^*_{1s}^1\).- It has one unpaired electron, so it is paramagnetic.
7Step 7: Conclusion
Out of the options, only \(\mathrm{H}_{2}\) has all electrons paired and is thus diamagnetic.
Key Concepts
Molecular Orbital TheoryElectron ConfigurationParamagnetic
Molecular Orbital Theory
Molecular Orbital Theory is an essential concept in chemistry that helps understand the behavior of electrons in molecules. Unlike the valence bond theory that considers electrons localized between two atoms, molecular orbital theory suggests that electrons in a molecule are delocalized and exist in orbitals that belong to the entire molecule.
In this theory, atomic orbitals from each atom combine to form molecular orbitals. These molecular orbitals can be classified as bonding, anti-bonding, or non-bonding.
In this theory, atomic orbitals from each atom combine to form molecular orbitals. These molecular orbitals can be classified as bonding, anti-bonding, or non-bonding.
- Bonding molecular orbitals have lower energy and more stability compared to the original atomic orbitals. Electrons here contribute to the bond between two atoms.
- Anti-bonding molecular orbitals are higher in energy and can destabilize a molecule if occupied by electrons. They are typically indicated with an asterisk, for example, \(\sigma^*\).
- Non-bonding molecular orbitals are those that do not help in holding the two atoms together.
Electron Configuration
Electron configuration refers to the distribution of electrons in an atom or molecule's orbitals. In molecular orbital theory, electron configuration is crucial in determining the properties of a species.
For example, when evaluating the electron configuration of the molecular species \(\mathrm{H}_2\), \(\mathrm{H}_{2}^{-}\), and \(\mathrm{H}_{2}^{+}\), you need to know the number of electrons and then fill in the orbitals in order of increasing energy:
For example, when evaluating the electron configuration of the molecular species \(\mathrm{H}_2\), \(\mathrm{H}_{2}^{-}\), and \(\mathrm{H}_{2}^{+}\), you need to know the number of electrons and then fill in the orbitals in order of increasing energy:
- \(\mathrm{H}_2\) has two electrons filling the \(\sigma_{1s}\) bonding orbital with a configuration of \(\sigma_{1s}^2\).
- \(\mathrm{H}_{2}^{-}\) has three electrons, filling \(\sigma_{1s}^2\) and one electron in \(\sigma^*_{1s}\), making it \(\sigma_{1s}^2\ \sigma^*_{1s}^1\).
- \(\mathrm{H}_{2}^{+}\) contains only one electron in the \(\sigma_{1s}\) orbital, \(\sigma_{1s}^1\).
Paramagnetic
A paramagnetic species is identified by the presence of one or more unpaired electrons in its atomic or molecular orbital configuration. These unpaired electrons have a magnetic moment, allowing the species to be attracted to magnetic fields.
In the context of the original exercise:
In the context of the original exercise:
- \(\mathrm{H}_{2}^{-}\) is paramagnetic because its electron configuration \(\sigma_{1s}^2\ \sigma^*_{1s}^1\) includes an unpaired electron in the anti-bonding orbital.
- \(\mathrm{H}_{2}\) is diamagnetic as all electrons are paired.
- \(\mathrm{H}_{2}^{+}\) is paramagnetic with its single unpaired electron in the \(\sigma_{1s}\) orbital.
Other exercises in this chapter
Problem 193
Which of the following has the regular tetrahedral structure? (a) \(\mathrm{BF}_{4}{\underline{\phantom{xx}}}^{-}\) (b) \(\mathrm{SF}_{4}\) (c) \(\left[\mathrm{Ni}(\mathrm{CN})_{a}\ri
View solution Problem 194
The maximum number of \(90^{\circ}\) angles between bond pair-bond pair of electrons is observed in [2004] (a) \(\mathrm{sp}^{3} \mathrm{~d}^{2}\) hybridization
View solution Problem 196
Lattice energy of an ionic compound depends upon [2005] (a) packing of ions only (b) size of the ion only (c) charge on the ion and size of the ion (d) charge o
View solution Problem 197
The molecular shapes of \(\mathrm{SF}_{4}, \mathrm{CF}_{4}\) and \(\mathrm{XeF}_{4}\) are \([2005]\) (a) the same with 2,0 and 1 lone pairs of electrons on the
View solution