Problem 192
Question
Find the total differential of the function \(w=e^{y} \cos (x)+z^{2}.\)
Step-by-Step Solution
Verified Answer
The total differential is \(dw = -e^y \sin(x) dx + e^y \cos(x) dy + 2z dz.\)
1Step 1: Understand the Total Differential
The total differential of a function with multiple variables is a way to approximate the change in a function based on changes in its input variables. For a function like \(w = f(x, y, z)\), the total differential \(dw\) is given by \(dw = \frac{\partial f}{\partial x}dx + \frac{\partial f}{\partial y}dy + \frac{\partial f}{\partial z}dz\).
2Step 2: Compute Partial Derivative with Respect to x
Compute the partial derivative of \(w = e^{y} \cos(x)+z^{2}\) with respect to \(x\). Hold \(y\) and \(z\) constant: \(\frac{\partial w}{\partial x} = -e^y \sin(x).\)
3Step 3: Compute Partial Derivative with Respect to y
Compute the partial derivative of \(w = e^{y} \cos(x)+z^{2}\) with respect to \(y\). Hold \(x\) and \(z\) constant: \(\frac{\partial w}{\partial y} = e^y \cos(x).\)
4Step 4: Compute Partial Derivative with Respect to z
Compute the partial derivative of \(w = e^{y} \cos(x)+z^{2}\) with respect to \(z\). Hold \(x\) and \(y\) constant: \(\frac{\partial w}{\partial z} = 2z.\)
5Step 5: Construct the Total Differential
Combine the partial derivatives into the total differential: \(dw = \frac{\partial w}{\partial x} dx + \frac{\partial w}{\partial y} dy + \frac{\partial w}{\partial z} dz.\)Substitute the computed partial derivatives:\[dw = (-e^y \sin(x)) dx + (e^y \cos(x)) dy + (2z) dz.\]
Key Concepts
Partial DerivativeMultivariable CalculusFunction Approximation
Partial Derivative
A partial derivative is like a regular derivative, but it focuses on one variable at a time. Imagine a function with many variables, like the weather has temperature, humidity, and wind speed. If we only care about how the weather changes with temperature, we find the partial derivative with respect to temperature.
For our function, which is given by \(w = e^{y} \cos(x) + z^2\), taking the partial derivative with respect to \(x\) means treating \(y\) and \(z\) as constants. This gives us \(\frac{\partial w}{\partial x} = -e^y \sin(x)\).
For our function, which is given by \(w = e^{y} \cos(x) + z^2\), taking the partial derivative with respect to \(x\) means treating \(y\) and \(z\) as constants. This gives us \(\frac{\partial w}{\partial x} = -e^y \sin(x)\).
- Focus on one variable, hold others constant.
- Helps isolate the effect of one variable change.
Multivariable Calculus
Multivariable calculus is the branch of mathematics where you deal with functions of more than one variable. It's like regular calculus but expanded to consider multi-dimensional space, like land, sea, and air. Think about graphs not just drawn on paper, but in real 3D or even higher dimensions.
With the function \(w = e^{y} \cos(x) + z^2\), multivariable calculus helps us understand how \(w\) changes when \(x\), \(y\), or \(z\) change. By calculating partial derivatives, we can create a complete picture of how the function behaves.
With the function \(w = e^{y} \cos(x) + z^2\), multivariable calculus helps us understand how \(w\) changes when \(x\), \(y\), or \(z\) change. By calculating partial derivatives, we can create a complete picture of how the function behaves.
- Work in two or more dimensions.
- Essential for physics, engineering, and economics.
Function Approximation
Function approximation is about estimating how a function behaves. The total differential is a technique for making these estimations. By using the partial derivatives, we can predict small changes in the function's output based on small changes in its inputs.
Approximating the change in \(w = e^{y} \cos(x) + z^2\) involves calculating \(dw = (-e^y \sin(x)) dx + (e^y \cos(x)) dy + (2z) dz\). Each term in this expression gives a snapshot of how sensitive \(w\) is to changes in \(x\), \(y\), and \(z\).
Approximating the change in \(w = e^{y} \cos(x) + z^2\) involves calculating \(dw = (-e^y \sin(x)) dx + (e^y \cos(x)) dy + (2z) dz\). Each term in this expression gives a snapshot of how sensitive \(w\) is to changes in \(x\), \(y\), and \(z\).
- Use the total differential to estimate function changes.
- Useful in real-world problem solving.
Other exercises in this chapter
Problem 187
For the following exercises, find parametric equations for the normal line to the surface at the indicated point. (Recall that to find the equation of a line in
View solution Problem 191
Show that \(f(x, y)=e^{x y} x\) is differentiable at point \((1,0) .\)
View solution Problem 193
Show that \(f(x, y)=x^{2}+3 y\) is differentiable at every point. In other words, show that \(\Delta z=f(x+\Delta x, y+\Delta y)-f(x, y)=f_{x} \Delta x+f_{y} \D
View solution Problem 194
Find the total differential of the function \(z=\frac{x y}{y+x}\) where \(x\) changes from 10 to 10.5 and \(y\) changes from 15 to 13 .
View solution