Problem 191
Question
In the following exercises, translate to a system of equations and solve the system. A married couple together earn \(\$ 75,000\). The husband earns \(\$ 15,000\) more than five times what his wife earns. What does the wife earn?
Step-by-Step Solution
Verified Answer
The wife earns \(\$10,000\).
1Step 1: Define Variables
Let \(H\) represent the husband's earnings and \(W\) represent the wife's earnings.
2Step 2: Formulate Equations
Using the given information, we can write the following two equations: 1. \(H + W = 75000\) 2. \(H = 5W + 15000\)
3Step 3: Substitute the Second Equation into the First
Replace \(H\) in the first equation with the expression from the second equation:\(5W + 15000 + W = 75000\)
4Step 4: Combine Like Terms
Combine the \(W\) terms in the equation:\(6W + 15000 = 75000\)
5Step 5: Isolate \(W\)
Subtract 15000 from both sides of the equation:\(6W = 60000\)Next, divide both sides by 6 to find \(W\):\(W = 10000\)
6Step 6: Verify Solution
Substitute \(W = 10000\) back into both original equations to ensure the solution is correct. Using equation 2: \(H = 5(10000) + 15000 = 65000\). Using equation 1: \(65000 + 10000 = 75000\), which is correct.
Key Concepts
variablessubstitution methodlinear equationssolving equations
variables
In algebra, variables are symbols that represent unknown values. For example, in the problem about the married couple's earnings, we use variables to represent the husband's and wife's earnings. We define these as:
Let H represent the husband's earnings.
Let W represent the wife's earnings.
Choosing appropriate variables helps us to translate real-world problems into mathematical equations that we can solve.
Let H represent the husband's earnings.
Let W represent the wife's earnings.
Choosing appropriate variables helps us to translate real-world problems into mathematical equations that we can solve.
substitution method
The substitution method is a technique for solving systems of equations. This method involves substituting one equation into another to eliminate one of the variables. For this problem, we had two equations:
We can substitute the expression for H from the second equation into the first equation. This substitution helps us to solve for W because it gives us one equation with one variable. Thus, the problem becomes easier.
- 1. H + W = 75000
- 2. H = 5W + 15000
We can substitute the expression for H from the second equation into the first equation. This substitution helps us to solve for W because it gives us one equation with one variable. Thus, the problem becomes easier.
linear equations
Linear equations are equations where the variables are not raised to any power other than one. They graph as straight lines on a coordinate plane. Our problem involved two linear equations:
H + W = 75000 and H = 5W + 15000.
These equations are linear because the variables H and W are to the first power. By solving these linear equations, we can determine the values of the husband's and wife's earnings.
H + W = 75000 and H = 5W + 15000.
These equations are linear because the variables H and W are to the first power. By solving these linear equations, we can determine the values of the husband's and wife's earnings.
solving equations
Solving equations involves finding the values of the variables that make the equation true. In this problem, after substituting H from the second equation into the first equation, we combined like terms to simplify the equation:
6W + 15000 = 75000.
Next, we isolated W by subtracting 15000 from both sides to get:
6W = 60000.
Finally, we divided by 6 to find the wife's earnings:
W = 10000.
To ensure our solution is correct, we checked it by substituting W back into the original equations. The calculations confirmed that both equations were satisfied.
6W + 15000 = 75000.
Next, we isolated W by subtracting 15000 from both sides to get:
6W = 60000.
Finally, we divided by 6 to find the wife's earnings:
W = 10000.
To ensure our solution is correct, we checked it by substituting W back into the original equations. The calculations confirmed that both equations were satisfied.
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