Problem 190
Question
Out of the following, the alkene that exhibits optical isomerism is (a) 3 - methyl \(-2\) - pentene (b) 4 - methyl \(-1\) - pentene (c) 3 - methyl \(-1\) - pentene (d) 2- methyl \(-2\) - pentene
Step-by-Step Solution
Verified Answer
The alkene that exhibits optical isomerism is (a) 3-methyl-2-pentene.
1Step 1: Understand Optical Isomerism
Optical isomerism occurs when there is a chiral center in a molecule. A chiral center is typically a carbon atom bonded to four different groups. This asymmetry allows the molecule to have non-superimposable mirror images, known as enantiomers.
2Step 2: Analyze the Given Alkenes for Chirality
For each provided alkene, identify potential chiral centers. A chiral center is absent in small alkenes with symmetry or identical substituents. Check each alkene structure to locate carbons that may have four different substituents.
3Step 3: Evaluate 3-methyl-2-pentene
- Structure: CH3-CH=C(CH3)-CH2-CH3
- Check: The carbon labeled C2 has different groups attached (H, CH3, ethyl group), making it a potential chiral center. Therefore, 3-methyl-2-pentene has chiral carbon.
4Step 4: Evaluate 4-methyl-1-pentene
- Structure: CH3-CH2-CH(CH3)-CH=CH2
- Check: The carbon labeled C4 (CH3-CH(CH3)-) is not a chiral center as it doesn't have four different groups; it has two hydrogen atoms.
5Step 5: Evaluate 3-methyl-1-pentene
- Structure: CH3-CH=C(CH3)-CH2-CH3
- Check: Similar to 3-methyl-2-pentene, but without making C2 a chiral center since one of the double-bonded carbons can't form four bonds.
6Step 6: Evaluate 2-methyl-2-pentene
- Structure: CH3-C(CH3)=C(CH3)-CH2-CH3
- Check: This structure has no carbon with four different substituents, thus lacks any chiral center.
Key Concepts
Chiral CenterAlkenesEnantiomers
Chiral Center
A chiral center is like the heart of optical isomerism. Imagine you're holding a carbon atom with arms stretching out in four different directions, each holding a different object. This means the carbon is attached to four unique groups.
A chiral center makes your molecule like a pair of left and right hands. Even if they look similar, you can't perfectly overlay one on the other. Such non-superimposable mirror images are what we call enantiomers. The ability to have these mirror images is what gives rise to optical isomerism.
A chiral center makes your molecule like a pair of left and right hands. Even if they look similar, you can't perfectly overlay one on the other. Such non-superimposable mirror images are what we call enantiomers. The ability to have these mirror images is what gives rise to optical isomerism.
- Look for carbon atoms bonded to four different atoms or groups.
- This unique arrangement is essential for chirality and hence optical activity.
- If any two groups attached to the carbon are the same, it is not a chiral center.
Alkenes
Alkenes are hydrocarbons that include at least one carbon-carbon double bond. The presence of a double bond influences the geometry and chemistry of the molecule. When identifying a chiral center in alkenes, the double bond restricts rotation, which affects the spatial arrangement of attached groups.
However, a chiral center is less common in simple alkenes because the carbon atoms participating in the double bond can only attach to three different groups.
Alkenes carry:
However, a chiral center is less common in simple alkenes because the carbon atoms participating in the double bond can only attach to three different groups.
Alkenes carry:
- At least one carbon-carbon double bond.
- A tendency to be non-chiral due to the double-bonded carbons having fewer different substituents.
Enantiomers
Enantiomers are mirror-image molecules that cannot be superimposed on one another, much like our left and right hands. They are a result of chiral centers in molecules.
The key characteristics of enantiomers include:
The key characteristics of enantiomers include:
- Identical physical properties (like melting point and boiling point).
- Different interaction with polarized light; they rotate plane-polarized light in opposite directions.
- Potentially very different effects in biological systems due to how they interact with other chiral molecules (like enzymes or receptors).
Other exercises in this chapter
Problem 188
The IUPAC name of neopentane is: (a) 2,2 - dimethylpropane (b) 2-mehylpropane (c) 2,2 - dimethylbutane (d) 2 - methylbytane
View solution Problem 189
The number of stereo isomers possible for a com[2009] \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}(\mathrm{OH})-\mathrm{Me}\) is: (a) 2 (b) 4 (c) 6 (d)
View solution Problem 191
Identify the compound that exhibits tautomerism. [2011] (a) Lactic acid (b) 2- Pentanone (c) Phenol (d) 2- Butene
View solution Problem 192
How many chiral compounds are possible on monochlorination of 2 - methyl butane? [2012] (a) 4 (b) 8 (c) 6 (d) 2
View solution