Problem 190
Question
For the following exercises, find the equation of the tangent line to each of the given functions at the indicated values of \(x .\) Then use a calculator to graph both the function and the tangent line to ensure the equation for the tangent line is correct. $$[\mathbf{T}] f(x)=5 \cot x x=\frac{\pi}{4}$$
Step-by-Step Solution
Verified Answer
The equation of the tangent line is \( y = -10x + \frac{10\pi}{4} + 5 \).
1Step 1: Find the Derivative of the Function
To find the equation of the tangent line, we first need to find the derivative of the function, which gives the slope of the tangent line. The function given is \( f(x) = 5 \cot x \). The derivative of \( \cot x \) is \( -\csc^2 x \). Therefore, the derivative of \( f(x) \) is \( f'(x) = 5 \times (-\csc^2 x) = -5 \csc^2 x \).
2Step 2: Evaluate the Derivative at x = \( \pi/4 \)
Now we need to find the slope of the tangent line at \( x = \pi/4 \). Substitute \( x = \pi/4 \) into the derivative: \( f'(\pi/4) = -5 \csc^2(\pi/4) \). Since \( \csc(\pi/4) = \sqrt{2} \), \( \csc^2(\pi/4) = 2 \). Thus, \( f'(\pi/4) = -5 \, \times 2 = -10 \).
3Step 3: Find the Function Value at x = \( \pi/4 \)
We also need the function value at \( x = \pi/4 \). Substitute \( x = \pi/4 \) into the original function: \( f(\pi/4) = 5 \cot(\pi/4) \). Since \( \cot(\pi/4) = 1 \), \( f(\pi/4) = 5 \times 1 = 5 \).
4Step 4: Use the Point-Slope Form to Write the Equation of the Tangent Line
With the slope \( m = -10 \) and the point \((\pi/4, 5)\), we can use the point-slope form of a line: \( y - y_1 = m(x - x_1) \). Substituting the values, we get \( y - 5 = -10(x - \pi/4) \). Simplifying, the equation of the tangent line is \( y = -10x + \frac{10\pi}{4} + 5 \) or \( y = -10x + \frac{10\pi}{4} + 5 \).
5Step 5: Graph the Function and Tangent Line
Using a graphing calculator, graph the function \( f(x) = 5 \cot x \) and the tangent line \( y = -10x + \frac{10\pi}{4} + 5 \). Ensure the tangent line touches the curve only at \( x = \pi/4 \).
Key Concepts
Derivative of Trigonometric FunctionsPoint-Slope FormGraphing
Derivative of Trigonometric Functions
In mathematics, the derivative of a function helps to understand how the function behaves as its input value changes. When dealing with trigonometric functions like cotangent, the derivative provides the slope of the tangent line at any given point of the function.
For the function \( f(x) = 5 \cot x \), we first need to find the derivative, which gives us the slope crucial for defining the tangent line.
For the function \( f(x) = 5 \cot x \), we first need to find the derivative, which gives us the slope crucial for defining the tangent line.
- The derivative of \( \cot x \) is \( -\csc^2 x \).
- Thus, for \( f(x) = 5 \cot x \), the derivative becomes \( f'(x) = -5 \csc^2 x \).
Point-Slope Form
When you find the slope of the tangent line at a specific point, you can use it to write the equation of the tangent line using the point-slope form. This special form is practical for constructing a line equation when a point and the slope are known.
The point-slope formula can be expressed as:
The point-slope formula can be expressed as:
- \( y - y_1 = m(x - x_1) \)
- \( m \) is the slope of the line.
- \( (x_1, y_1) \) is the point through which the line passes.
- \( y - 5 = -10 \left( x - \frac{\pi}{4} \right) \)
Graphing
Graphing is a powerful tool for visualizing mathematical concepts. By graphing functions and their tangent lines, you gain insight into how these lines only touch the curve at a point, showing instant rate of change.
For graphing:
Graphing helps bridge the gap between abstract equations and their real-world representations, making it easier to understand complex relationships and behaviors.
For graphing:
- Use a graphing calculator or software to plot \( f(x) = 5 \cot x \).
- Also plot the tangent line \( y = -10x + \frac{10\pi}{4} + 5 \).
Graphing helps bridge the gap between abstract equations and their real-world representations, making it easier to understand complex relationships and behaviors.
Other exercises in this chapter
Problem 188
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