Problem 19
Question
Write a formula for the general term (the nth term) of each geometric sequence. Then use the formula for \(a_{n}\)to find \(a_{7},\) the seventh term of the sequence. $$18,6,2, \frac{2}{3}, \dots$$
Step-by-Step Solution
Verified Answer
The 7th term of the sequence is \( \frac {2}{243}\).
1Step 1: Find the Common Ratio
First order of business is to find the common ratio of the geometric sequence. This can be done by dividing any term in the sequence by its previous term. For example, dividing the second term by the first term, \(r = \frac {6}{18} = \frac {1}{3}\)
2Step 2: Formulate the General Term Formula
Now that we have the common ratio, the next step is to derive the expression for the nth term of the geometric sequence. A geometric sequence can be represented generally as \(a_n = a_1 * r^{(n-1)}\), where \(a_n\) is the nth term, \(a_1\) is the first term, r is the common ratio, and n is the term number. Substituting \(a_1 = 18\) and \(r = \frac {1}{3}\), we have \(a_n = 18 * (\frac{1}{3})^{n-1}\)
3Step 3: Calculate Term a7
The final step is to calculate the 7th term \(a_7\) in the sequence. Substitute \(n = 7\) into the general term formula. Thus, \(a_7 = 18 * (\frac{1}{3})^{7-1} = \frac {2}{243}\)
Key Concepts
Understanding the Common RatioExploring the nth Term FormulaHow to Use the General Term of a Sequence
Understanding the Common Ratio
In a geometric sequence, each term after the first is found by multiplying the previous one by a fixed, non-zero number known as the "common ratio." This ratio is a crucial part of understanding how the sequence progresses.
If you know any two consecutive terms in a sequence, you can calculate the common ratio by dividing the second term by the first. For instance, in the sequence given in the exercise, we have the terms 18 and 6. Dividing 6 by 18 results in \( \frac{1}{3} \), indicating that each term is \( \frac{1}{3} \) of the term before it.
Knowing the common ratio helps you predict the sequence's future behavior, as each term becomes more predictable as you understand this pattern.
If you know any two consecutive terms in a sequence, you can calculate the common ratio by dividing the second term by the first. For instance, in the sequence given in the exercise, we have the terms 18 and 6. Dividing 6 by 18 results in \( \frac{1}{3} \), indicating that each term is \( \frac{1}{3} \) of the term before it.
Knowing the common ratio helps you predict the sequence's future behavior, as each term becomes more predictable as you understand this pattern.
Exploring the nth Term Formula
The nth term formula is a key tool in identifying any term in a geometric sequence without needing to list all the terms. This formula is handy, especially when working with large sequences.
For a geometric sequence, the nth term \( a_n \) can be defined using the formula \( a_n = a_1 \cdot r^{(n-1)} \). Here, \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the term's position.
For the sequence in question, substituting \( a_1 = 18 \) and \( r = \frac{1}{3} \) gives us the formula \( a_n = 18 \cdot \left( \frac{1}{3} \right)^{n-1} \). This formula allows you to compute any term in the sequence with ease and precision.
For a geometric sequence, the nth term \( a_n \) can be defined using the formula \( a_n = a_1 \cdot r^{(n-1)} \). Here, \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the term's position.
For the sequence in question, substituting \( a_1 = 18 \) and \( r = \frac{1}{3} \) gives us the formula \( a_n = 18 \cdot \left( \frac{1}{3} \right)^{n-1} \). This formula allows you to compute any term in the sequence with ease and precision.
How to Use the General Term of a Sequence
Using the general term formula, you can calculate any term in a geometric sequence. This is particularly useful when asked to find a specific term, such as the seventh term, without listing every term up to that point.
For example, using the formula derived \( a_n = 18 \cdot \left( \frac{1}{3} \right)^{n-1} \), to find the seventh term \( a_7 \), simply substitute 7 for \( n \).
This leads to \( a_7 = 18 \cdot \left( \frac{1}{3} \right)^{6} \). Calculating this step-by-step ensures accuracy:
For example, using the formula derived \( a_n = 18 \cdot \left( \frac{1}{3} \right)^{n-1} \), to find the seventh term \( a_7 \), simply substitute 7 for \( n \).
This leads to \( a_7 = 18 \cdot \left( \frac{1}{3} \right)^{6} \). Calculating this step-by-step ensures accuracy:
- Calculate \( \left( \frac{1}{3} \right)^{6} = \frac{1}{729} \)
- Multiply \( 18 \cdot \frac{1}{729} = \frac{18}{729} = \frac{2}{243} \)
Other exercises in this chapter
Problem 19
In Exercises \(11-30,\) use mathematical induction to prove that each statement is true for every positive integer \(n\) $$ 2+4+8+\dots+2^{n}=2^{n+1}-2 $$
View solution Problem 19
In Exercises \(17-20,\) does the problem involve permutations or combinations? Explain your answer. (It is not necessary to solve the problem. \()\) How many di
View solution Problem 19
Find the indicated term of the arithmetic sequence with first term, \(a_{1},\) and common difference, \(d\). Find \(a_{200}\) when \(a_{1}=-40, d=5\)
View solution Problem 19
The general term of a sequence is given and involves a factorial. Write the first four terms of each sequence. $$a_{n}=\frac{n^{2}}{n !}$$
View solution