Problem 19
Question
Write a balanced equation to show (a) the reaction of chromate ion with strong acid. (b) the oxidation of water to oxygen gas by permanganate ion in basic solution. (c) the reduction half-reaction of chromate ion to chromium(III) hydroxide in basic solution.
Step-by-Step Solution
Verified Answer
(a) Reaction of chromate ion with strong acid
(b) Oxidation of water to oxygen gas by permanganate ion in basic solution
(c) Reduction half-reaction of chromate ion to chromium(III) hydroxide in basic solution
Answer:
(a) 2 CrO_4^{2-} + 2 H^+ -> Cr_2O_7^{2-} + H_2O
(b) 2 MnO_4^{-} + 3 H_2O -> 2 MnO_2 + 3 O_2 + 4 OH^-
(c) 2 CrO_4^{2-} + 2 OH^- -> 2 Cr(OH)_3 + 6 e^-
1Step 1: Write the unbalanced equation
Write the unbalanced equation with chromate ion (CrO_4^{2-}) reacting with a strong acid (H^+):
CrO_4^{2-} + H^+ -> ?
2Step 2: Determine the products
In the presence of a strong acid, chromate ion is protonated to form dichromate ion (Cr_2O_7^{2-}) and water:
CrO_4^{2-} + H^+ -> Cr_2O_7^{2-} + H_2O
3Step 3: Balance the equation
To balance the equation, we need to adjust the number of atoms on both sides:
2 CrO_4^{2-} + 2 H^+ -> Cr_2O_7^{2-} + H_2O
(b) Oxidation of water to oxygen gas by permanganate ion in basic solution
4Step 1: Write the unbalanced equation
Write the unbalanced equation with permanganate ion (MnO_4^{-}) oxidizing water (H_2O) to oxygen gas (O_2) in a basic solution:
MnO_4^{-} + H_2O -> MnO_2 + O_2
5Step 2: Balance the equation
Balance the equation by adjusting the number of atoms on both sides:
2 MnO_4^{-} + 3 H_2O -> 2 MnO_2 + 3 O_2 + 4 OH^-
(c) Reduction half-reaction of chromate ion to chromium(III) hydroxide in basic solution
6Step 1: Write the unbalanced half-reaction
Write the unbalanced reduction half-reaction, in which chromate ion (CrO_4^{2-}) is reduced to chromium(III) hydroxide (Cr(OH)_3) in a basic solution:
CrO_4^{2-} -> Cr(OH)_3
7Step 2: Balance the oxygen atoms
Add water (H_2O) to balance the oxygen atoms:
CrO_4^{2-} + 3 H_2O -> Cr(OH)_3
8Step 3: Balance the hydrogen atoms
Add hydroxide ions (OH^-) to the other side to balance the hydrogen atoms:
CrO_4^{2-} + 3 H_2O -> Cr(OH)_3 + 6 OH^-
9Step 4: Balance charges
Add electrons (e^-) to the appropriate side of the equation to balance the charges:
2 CrO_4^{2-} + 8 OH^- -> 2 Cr(OH)_3 + 6 OH^- + 6 e^-
10Step 5: Simplify the equation
Simplify the equation by eliminating the common species:
2 CrO_4^{2-} + 2 OH^- -> 2 Cr(OH)_3 + 6 e^-
Key Concepts
Balanced Chemical EquationsOxidation-Reduction ReactionsChromate Ion ReactionsPermanganate Ion Reactions
Balanced Chemical Equations
Chemical reactions need to be represented by balanced chemical equations. This means that the number of each type of atom on the reactants side must equal the number on the products side. This balance is in accordance with the Law of Conservation of Mass, which states that mass cannot be created or destroyed in a chemical reaction.
Balancing equations requires some steps:
Balancing equations requires some steps:
- Identify all reactants and products in the equation.
- Count the number of atoms of each element in the reactants and products.
- Add coefficients in front of compounds to balance the number of atoms of each element on both sides.
- Ensure all coefficients are the smallest set of whole numbers that balance the equation.
Oxidation-Reduction Reactions
Oxidation-reduction reactions, or redox reactions, involve the transfer of electrons between substances. Oxidation refers to the loss of electrons, while reduction refers to the gain of electrons. These reactions are crucial because they are involved in many chemical and biological processes, such as cellular respiration and combustion.
Understanding oxidation numbers can help identify what is being oxidized and reduced:
Understanding oxidation numbers can help identify what is being oxidized and reduced:
- Oxidation number increases when a substance is oxidized.
- Oxidation number decreases when a substance is reduced.
Chromate Ion Reactions
Chromate ions ( ext{CrO}_4^{2-}) are involved in a number of reactions, especially redox reactions. A significant chromate reaction occurs when chromate ions are introduced to an acidic environment, causing them to convert into dichromate ions ( ext{Cr}_2 ext{O}_7^{2-}). The chromate-dichromate equilibrium is an important aspect of this chemistry.
In acidic conditions, the reaction can be shown as:
In acidic conditions, the reaction can be shown as:
- Chromate ions react with hydrogen ions ( ext{H}^+) to form dichromate ions and water.
Permanganate Ion Reactions
Permanganate ions ( ext{MnO}_4^{-}) are strong oxidizing agents. In basic solutions, they play a role in a variety of oxidation reactions. The permanganate ion can oxidize water into oxygen gas while itself being reduced to manganese dioxide ( ext{MnO}_2).
Key points in permanganate ion reactions:
Key points in permanganate ion reactions:
- Permanganate ions usually change color during the reaction, from vibrant purple to brown, indicating their reduction.
- In acidic solutions, permanganate ions are reduced to manganese ( ext{Mn}^{2+}), illustrating different behavior in varying pH contexts.
- In basic solutions, the reduction typically halts at manganese dioxide ( ext{MnO}_2).
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