Problem 19
Question
Write a balanced equation to represent (a) the reduction of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) with carbon monoxide in a blast fumace. (b) the production of hydrogen gas when hydrochloric acid reacts with an iron nail.
Step-by-Step Solution
Verified Answer
(a) \(\mathrm{Fe}_{2} \mathrm{O}_{3} + 3 \mathrm{CO} \rightarrow 2 \mathrm{Fe} + 3 \mathrm{CO}_{2}\); (b) \(2\mathrm{HCl} + \mathrm{Fe} \rightarrow \mathrm{FeCl}_{2} + \mathrm{H}_{2}\).
1Step 1: Identify the Reactants and Products for Reaction (a)
In reaction (a), we are focusing on the reduction of iron(III) oxide, \(\mathrm{Fe}_{2} \mathrm{O}_{3}\), with carbon monoxide, \(\mathrm{CO}\). The main reduction product is iron, \(\mathrm{Fe}\), while \(\mathrm{CO}\) is oxidized to form carbon dioxide, \(\mathrm{CO}_{2}\).
2Step 2: Write the Unbalanced Equation for Reaction (a)
The unbalanced chemical equation for reaction (a) is: \[ \mathrm{Fe}_{2} \mathrm{O}_{3} + \mathrm{CO} \rightarrow \mathrm{Fe} + \mathrm{CO}_{2} \]
3Step 3: Balance the Equation for Reaction (a)
Now, balance the equation by adjusting the coefficients. Balance iron first: \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) gives 2 iron atoms. Then balance the carbon and oxygen: \[ \mathrm{Fe}_{2} \mathrm{O}_{3} + 3 \mathrm{CO} \rightarrow 2 \mathrm{Fe} + 3 \mathrm{CO}_{2} \]
4Step 4: Identify the Reactants and Products for Reaction (b)
In reaction (b), hydrochloric acid, \(\mathrm{HCl}\), reacts with iron to produce iron chloride, \(\mathrm{FeCl}_2\), and hydrogen gas, \(\mathrm{H}_2\).
5Step 5: Write the Unbalanced Equation for Reaction (b)
The initial unbalanced chemical equation for this reaction is: \[ 2\mathrm{HCl} + \mathrm{Fe} \rightarrow \mathrm{FeCl}_{2} + \mathrm{H}_{2} \]
6Step 6: Balance the Equation for Reaction (b)
The coefficients are correct for the balanced state after checking that both sides have equivalent amounts of each element. Therefore, the balanced equation is: \[ 2\mathrm{HCl} + \mathrm{Fe} \rightarrow \mathrm{FeCl}_{2} + \mathrm{H}_{2} \]
Key Concepts
Reduction-Oxidation ReactionsBlast Furnace ChemistryHydrogen Gas Production
Reduction-Oxidation Reactions
Reduction-Oxidation reactions, or redox reactions for short, are chemical processes where one substance loses electrons and another gains electrons. Here's a simple way to remember it:
The chemical equation shows \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) gaining electrons (and hence being reduced) to form iron, \(\mathrm{Fe}\), while \(\mathrm{CO}\) loses electrons (being oxidized) to form carbon dioxide, \(\mathrm{CO}_{2}\).
When balancing redox reactions, focus on ensuring that the loss and gain of electrons cancel out so that the overall charge and number of atoms stay consistent on both sides of the equation.
This is why we end up with a balanced equation of: \[\mathrm{Fe}_{2} \mathrm{O}_{3} + 3 \mathrm{CO} \rightarrow 2 \mathrm{Fe} + 3 \mathrm{CO}_{2}\]
- Oxidation: When a substance loses electrons, it's oxidized.
- Reduction: When a substance gains electrons, it's reduced.
The chemical equation shows \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) gaining electrons (and hence being reduced) to form iron, \(\mathrm{Fe}\), while \(\mathrm{CO}\) loses electrons (being oxidized) to form carbon dioxide, \(\mathrm{CO}_{2}\).
When balancing redox reactions, focus on ensuring that the loss and gain of electrons cancel out so that the overall charge and number of atoms stay consistent on both sides of the equation.
This is why we end up with a balanced equation of: \[\mathrm{Fe}_{2} \mathrm{O}_{3} + 3 \mathrm{CO} \rightarrow 2 \mathrm{Fe} + 3 \mathrm{CO}_{2}\]
Blast Furnace Chemistry
Blast furnace chemistry is essential in the extraction of iron from its ores, particularly iron oxides. A blast furnace is a huge steel stack lined with refractory brick. It's charged with iron ore, pellets, sinters, and coke, which act as the reducing agent.
During this process, carbon in the form of coke combines with oxygen to form carbon monoxide (\(\mathrm{CO}\)). This \(\mathrm{CO}\) acts to reduce the iron ore and produce molten iron, while being itself oxidized to carbon dioxide (\(\mathrm{CO}_{2}\)).
During this process, carbon in the form of coke combines with oxygen to form carbon monoxide (\(\mathrm{CO}\)). This \(\mathrm{CO}\) acts to reduce the iron ore and produce molten iron, while being itself oxidized to carbon dioxide (\(\mathrm{CO}_{2}\)).
- Step 1: The carbon reacts with oxygen in the air to form \(\mathrm{CO}\).
- Step 2: \(\mathrm{CO}\) reduces the iron ore to \(\mathrm{Fe}\).
- Step 3: The product, \(\mathrm{Fe}\), melts and collects at the bottom of the furnace.
Hydrogen Gas Production
Hydrogen gas production through chemical reactions is an interesting application of redox processes. For reaction (b), when hydrochloric acid (\(\mathrm{HCl}\)) reacts with an iron nail, hydrogen gas is released.
In this reaction:
This process is not only fascinating in a laboratory setting but also has real-world applications, especially in industries where hydrogen is a critical component.
In this reaction:
- \(\mathrm{HCl}\) donates its hydrogen ion \(\mathrm{H}^+\), which gets reduced by gaining electrons to form \(\mathrm{H}_2\) gas.
- Iron (\(\mathrm{Fe}\)) serves as the reducing agent, forming \(\mathrm{FeCl}_2\), and losing electrons in the process.
This process is not only fascinating in a laboratory setting but also has real-world applications, especially in industries where hydrogen is a critical component.
Other exercises in this chapter
Problem 14
Write electron configurations for the \(2+\) ions of (a) iron. (b) copper. (c) chromium.
View solution Problem 16
Which Period 4 transition-metal ions are isoelectronic with (a) \(\mathrm{Zn}^{2+}\) (b) \(\mathrm{Mn}^{2+}\) (c) \(\mathrm{Cr}^{3+}\) (d) \(\mathrm{Fe}^{3+}\)
View solution Problem 20
Write a balanced equation to represent (a) the roasting of \(\mathrm{Cu}_{2} \mathrm{~S}\) to copper metal. (b) the reduction of \(\mathrm{Fe}_{2} \mathrm{O}_{3
View solution Problem 21
Balance this redox reaction (in acidic solution). $$ \mathrm{Fe}(\mathrm{s})+\mathrm{NO}_{3}^{-}(\mathrm{aq}) \longrightarrow \mathrm{Fe}^{3+}(\mathrm{aq})+\mat
View solution