Problem 19
Question
Which of the following solutions is a buffer? (a) \(0.20 \mathrm{M}\) for\(\operatorname{mic}\) acid \((\mathrm{HCOOH}),(\mathbf{b}) 0.20 M\) formic acid \((\mathrm{HCOOH})\) and \(0.20 \mathrm{M}\) sodium formate \((\mathrm{HCOONa}),(\mathbf{c}) 0.20 \mathrm{Mnitric}\) acid \(\left(\mathrm{HNO}_{3}\right)\) and \(0.20 \mathrm{M}\) sodium nitrate \(\left(\mathrm{NaNO}_{3}\right)\) (d) both b and \(\mathrm{c},(\mathbf{e})\) all of \(\mathrm{a}, \mathrm{b},\) and \(\mathrm{c}\).
Step-by-Step Solution
Verified Answer
The correct answer is (b) \(0.20 \mathrm{M}\) formic acid \((\mathrm{HCOOH})\) and \(0.20 \mathrm{M}\) sodium formate \((\mathrm{HCOONa})\), as this is the buffer solution among the given options.
1Step 1: Identify weak acids and their conjugate bases in the given solutions
In this step, we will identify the weak acids and their conjugate bases (or weak bases and their conjugate acids) in each given solution:
(a) \(0.20 \mathrm{M}\) formic acid \((\mathrm{HCOOH})\): This solution has only a weak acid, and its conjugate base is not present.
(b) \(0.20 \mathrm{M}\) formic acid \((\mathrm{HCOOH})\) and \(0.20 \mathrm{M}\) sodium formate \((\mathrm{HCOONa})\): This solution has both a weak acid and its conjugate base present.
(c) \(0.20 \mathrm{M}\) nitric acid \(\left(\mathrm{HNO}_{3}\right)\) and \(0.20 \mathrm{M}\) sodium nitrate \(\left(\mathrm{NaNO}_{3}\right)\): Nitric acid (\(\mathrm{HNO}_{3}\)) is a strong acid, so this solution does not contain a weak acid and its conjugate base.
2Step 2: Identify the buffer solution(s)
Based on our analysis in Step 1, we can now identify the buffer solution(s) from the given options:
(a) \(0.20 \mathrm{M}\) formic acid \((\mathrm{HCOOH})\): Not a buffer solution.
(b) \(0.20 \mathrm{M}\) formic acid \((\mathrm{HCOOH})\) and \(0.20 \mathrm{M}\) sodium formate \((\mathrm{HCOONa})\): This is a buffer solution because it contains both a weak acid and its conjugate base.
(c) \(0.20 \mathrm{M}\) nitric acid \(\left(\mathrm{HNO}_{3}\right)\) and \(0.20 \mathrm{M}\) sodium nitrate \(\left(\mathrm{NaNO}_{3}\right)\): Not a buffer solution.
(d) Both b and c: Not valid since option (c) is not a buffer solution.
(e) All of a, b, and c: Not valid since options (a) and (c) are not buffer solutions.
From our evaluation, we can conclude that the correct answer is (b) \(0.20 \mathrm{M}\) formic acid \((\mathrm{HCOOH})\) and \(0.20 \mathrm{M}\) sodium formate \((\mathrm{HCOONa})\), as this is the buffer solution among the given options.
Key Concepts
Weak AcidsConjugate BasesFormic AcidSodium Formate
Weak Acids
Weak acids are crucial components in chemistry and buffer solutions. Unlike strong acids, which completely dissociate into their ions in water, weak acids only partially dissociate. This means not all of the acid molecules break apart into ions. This partial dissociation establishes an equilibrium between the undissociated acid and its ions.
For example:
For example:
- Acetic acid: A common weak acid known for its role in vinegar.
- Formic acid (HCOOH): Used in the food industry and as a buffer component.
Conjugate Bases
Conjugate bases are the partners to weak acids in buffer solutions. When a weak acid loses a hydrogen ion, it forms its conjugate base. This base has the ability to re-associate with hydrogen ions, contributing to the stability of a solution's pH.
For instance, when formic acid (\( ext{HCOOH} \)) donates a proton, its conjugate base is the formate ion (\( ext{HCOO}^- \)).
For instance, when formic acid (\( ext{HCOOH} \)) donates a proton, its conjugate base is the formate ion (\( ext{HCOO}^- \)).
- Function: Conjugate bases capture and neutralize additional hydrogen ions, helping to maintain equilibrium.
- Buffer Role: They work alongside weak acids to mitigate pH changes.
Formic Acid
Formic acid (\( ext{HCOOH} \)), the simplest carboxylic acid, plays a vital role in buffer solutions due to its weak acidic properties. It's used in many industrial applications, such as leather tanning and food preservation. In a chemical context, formic acid partly dissociates in water:\[ ext{HCOOH}
ightleftharpoons ext{H}^+ + ext{HCOO}^- \]
- Dissociation: Only partially in water, allowing equilibrium with its conjugate base.
- Application: Commonly used in labs for preparing buffer solutions.
Sodium Formate
Sodium formate (\( ext{HCOONa} \)) is the sodium salt of formic acid. In aqueous solutions, it dissociates completely into sodium ions (\( ext{Na}^+ \)) and formate ions (\( ext{HCOO}^- \)). This dissociation makes sodium formate an essential component in buffer systems.
- Conjugate Base Role: Provides formate ions, the conjugate base of formic acid, ready to react with additional hydrogen ions.
- Buffer Creation: When combined with formic acid, it forms a buffer solution capable of resisting pH changes.
Other exercises in this chapter
Problem 17
(a) Calculate the percent ionization of \(0.0085 \mathrm{Mbutanoic}\) acid \(\left(K_{a}=1.5 \times 10^{-5}\right) .(\mathbf{b})\) Calculate the percent ionizat
View solution Problem 18
(a) Calculate the percent ionization of \(0.250 \mathrm{M}\) lactic acid \(\left(K_{a}=1.4 \times 10^{-4}\right) .(\mathbf{b})\) Calculate the percent ionizatio
View solution Problem 20
Which of the following solutions is a buffer? (a) A solution made by mixing \(50 \mathrm{~mL}\) of \(0.200 \mathrm{M}\) formic acid \((\mathrm{HCOOH})\) and \(2
View solution Problem 21
(a) Calculate the pH of a buffer that is \(0.150 \mathrm{M}\) in lactic acid and \(0.120 M\) in sodium lactate. (b) Calculate the pH of a buffer formed by mixin
View solution