Problem 19
Question
Use the limit definition to find the slope of the tangent line to the graph of \(f\) at the given point. $$ f(x)=x^{2}-1 ;(2,3) $$
Step-by-Step Solution
Verified Answer
The slope of the tangent line to the graph of \(f(x) = x^{2} - 1\) at the point (2,3) is 4.
1Step 1: Identify \(a\), \( \) and \(f(x)\)
In this case, \(a\) is the x-coordinate of the given point, so \(a=2\). The function \(f(x)\) is given as \(x^{2} - 1\).
2Step 2: Substitute \(a\), \(h\), and \(f(x)\) to the formula
The formula for the slope of the tangent line using limits is: \(m = \lim_{h->0}\frac{f(a+h) - f(a)}{h}\). If we substitute \(a=2\) and \(f(x) = x^{2} - 1\) into the formula, it becomes: \(m = \lim_{h->0}\frac{((2+h)^{2} - 1) - (2^{2} - 1)}{h}\). This simplifies to: \(m = \lim_{h->0}\frac{4+4h+h^{2} - 1 - 3}{h}\).
3Step 3: Simplify the expression and compute the limit as \(h->0\)
Simplify the numerator to get: \(m = \lim_{h->0}\frac{4h + h^{2}}{h}\). Then factor \(h\) out of the numerator: \(m = \lim_{h->0} h(4 + h)\). As \(h\) is a factor of both the numerator and denominator, we can cancel \(h\) out to get: \(m = \lim_{h->0}(4 + h)\). Evaluating the limit as \(h\) approaches 0, we get: \(m = 4\).
Key Concepts
Limit DefinitionSlope of Tangent LineTangent Line
Limit Definition
The limit definition is a foundational concept in calculus that helps us understand the behavior of functions as they approach a particular point. When evaluating the slope of a tangent line, we use this definition to find the instantaneous rate of change at a specific point. This involves the expression:
To apply this definition, we evaluate how the function value at \( a + h \) differs from the function value at \( a \) as \( h \) shrinks towards zero. This gives us insight into how steep the graph of the function is at that point. The limit is essential because it allows us to calculate this exact slope without having a secant line's influence, which represents an average rate of change over an interval.
- \( m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h} \)
To apply this definition, we evaluate how the function value at \( a + h \) differs from the function value at \( a \) as \( h \) shrinks towards zero. This gives us insight into how steep the graph of the function is at that point. The limit is essential because it allows us to calculate this exact slope without having a secant line's influence, which represents an average rate of change over an interval.
Slope of Tangent Line
The slope of the tangent line at a point on a curve is crucial for understanding the behavior of the function at that exact point. It effectively measures how the function is changing at that point, which can be thought of as its instantaneous rate of change.
For the function \( f(x) = x^2 - 1 \) at the point \( (2, 3) \), we calculate this slope using the limit definition discussed before. Substituting the point and the function into the limit expression:
This tells us that at the point \( (2, 3) \), the curve is rising steeply, with a slope of 4, meaning for every unit moved horizontally, the function moves up 4 units. Understanding this slope gives insights into the nature and behavior of the function at this specific point.
For the function \( f(x) = x^2 - 1 \) at the point \( (2, 3) \), we calculate this slope using the limit definition discussed before. Substituting the point and the function into the limit expression:
- \( m = \lim_{h \to 0} \frac{(2+h)^2 - 1 - (2^2 - 1)}{h} \)
- This simplifies to \( m = \lim_{h \to 0} \frac{4h + h^2}{h} \).
This tells us that at the point \( (2, 3) \), the curve is rising steeply, with a slope of 4, meaning for every unit moved horizontally, the function moves up 4 units. Understanding this slope gives insights into the nature and behavior of the function at this specific point.
Tangent Line
The tangent line to a curve at a given point is a straight line that just "touches" the curve at that point. It doesn't intersect the curve anywhere near that vicinity (if the curve isn't sharply turning).
Having already found the slope of the tangent line at the point \( (2, 3) \), which is 4, we can determine the equation of this line using the point-slope form of a line:
The tangent line equation is essential in calculus because it best approximates the function near that point. This concept can be expanded and used in many applications, such as finding the linear approximation of non-linear functions or solving optimization problems. It showcases the power of calculus in describing and predicting behavior at infinitesimally small scales.
Having already found the slope of the tangent line at the point \( (2, 3) \), which is 4, we can determine the equation of this line using the point-slope form of a line:
- \( y - y_1 = m(x - x_1) \)
- \( y - 3 = 4(x - 2) \)
The tangent line equation is essential in calculus because it best approximates the function near that point. This concept can be expanded and used in many applications, such as finding the linear approximation of non-linear functions or solving optimization problems. It showcases the power of calculus in describing and predicting behavior at infinitesimally small scales.
Other exercises in this chapter
Problem 19
Find \(d y / d x\) by implicit differentiation and evaluate the derivative at the given point. Equation \(\quad\) Point \(x^{3} y^{3}-y=x\) \(\quad\) \((0,0)\)
View solution Problem 19
find the third derivative of the function. $$ f(x)=5 x(x+4)^{3} $$
View solution Problem 20
Find the marginal cost for producing units. (The cost is measured in dollars.) $$ C=205,000+9800 x $$
View solution Problem 20
Find the derivative of the function. $$ g(x)=4 \sqrt[3]{x}+2 $$
View solution