Problem 19
Question
Use the given function values to estimate the area under the curve using left- endpoint and right-endpoint evaluation. $$\begin{array}{|l|r|r|r|r|r|r|r|r|r|} \hline x & 0.0 & 0.1 & 0.2 & 0.3 & 0.4 & 0.5 & 0.6 & 0.7 & 0.8 \\ \hline f(x) & 2.0 & 2.4 & 2.6 & 2.7 & 2.6 & 2.4 & 2.0 & 1.4 & 0.6 \\ \hline \end{array}$$
Step-by-Step Solution
Verified Answer
To estimate the area under the curve, we calculate the area of rectangles created using left-endpoint and right-endpoint values as heights. We then average these two results for a better estimate.
1Step 1: Calculation of rectangle area with left-endpoint evaluation
We start with the left-endpoint evaluation. Create rectangles for each interval, using the function value at the left endpoint as the height. The width of each rectangle is 0.1 (the step size). The area \( A \) can be calculated by summing the areas of each rectangle: \( A = \Sigma (width * height) \). The area estimations for each rectangle would be: \( A_{left} = \Sigma [0.1 * f(x_{i})], \) where \( x_i \) are the left endpoints 0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7.
2Step 2: Calculation of rectangle area with right-endpoint evaluation
We then move to the right-endpoint evaluation. Create rectangles for each interval, using the function value at the right endpoint as the height. The width of each rectangle is again 0.1 (the step size). The area can be calculated in a similar way to the left-endpoint evaluation: \( A = \Sigma (width * height) \). The area estimations for each rectangle would be: \( A_{right} = \Sigma [0.1 * f(x_{i})], \) where \( x_i \) are the right endpoints 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8.
3Step 3: Sum and Average of the areas
To better estimate the area under the curve, we can take the average of the results from left-endpoint and right-endpoint evaluations: \( A_{average} = (A_{left} + A_{right}) / 2 \).
Key Concepts
Left-Endpoint EvaluationRight-Endpoint EvaluationRiemann SumsIntegral Approximation
Left-Endpoint Evaluation
When we talk about left-endpoint evaluation, we are referring to a method for approximating the area under a curve by summing up areas of rectangles that use the left-endpoints of subintervals as their heights. Imagine a graph with a curve above the x-axis, and below this curve, we're drawing rectangles to fill up space all the way to the x-axis. For left-end endpoints, the top-left corner of each rectangle touches the curve.
To calculate the area of these rectangles, we multiply the height (the function value at the left-endpoint of each subinterval) by the width (the difference between consecutive x-values). In essence, we're building a 'staircase' that climbs up the curve, stepping off from the left at each interval.
This method can underestimate the area if the curve is increasing, and overestimate if the curve is decreasing. The reason is straightforward: as the actual curve rises, our rectangles from the left don't quite reach the curve's height within an interval. If the curve falls, our rectangles extend above and beyond the actual curve.
To calculate the area of these rectangles, we multiply the height (the function value at the left-endpoint of each subinterval) by the width (the difference between consecutive x-values). In essence, we're building a 'staircase' that climbs up the curve, stepping off from the left at each interval.
This method can underestimate the area if the curve is increasing, and overestimate if the curve is decreasing. The reason is straightforward: as the actual curve rises, our rectangles from the left don't quite reach the curve's height within an interval. If the curve falls, our rectangles extend above and beyond the actual curve.
Right-Endpoint Evaluation
Conversely, the right-endpoint evaluation uses the function values at the right ends of the intervals as the heights for the rectangles. These rectangles now begin at the curve and extend leftward to meet the y-axis. For a rising curve, right-endpoint evaluation tends to overestimate the actual area under the curve because the rectangles will jut above the curve line. Conversely, for a falling curve, it will underestimate it.
We follow a similar process as the left-endpoint method, but here we start our 'staircase' from the right side at each step. It's like turning around and looking back at how far the curve has risen or fallen at each point. This perspective shift from left to right can significantly alter our area approximation, especially with curves that have a lot of ups and downs.
We follow a similar process as the left-endpoint method, but here we start our 'staircase' from the right side at each step. It's like turning around and looking back at how far the curve has risen or fallen at each point. This perspective shift from left to right can significantly alter our area approximation, especially with curves that have a lot of ups and downs.
Riemann Sums
Both the left and right-endpoint evaluations are specific examples of Riemann sums, which are a broader category of techniques for estimating areas under curves. Essentially, Riemann sums cut the area into slices, use shapes (like our rectangles) to approximate the area of these slices, and then add them all up.
The power of Riemann sums lies in their flexibility. Depending on the situation, we can choose left-endpoints, right-endpoints, or even midpoints of subintervals — or we can get fancy with trapezoids or other shapes. The idea is to get as close as possible to the actual area under the curve. As we refine our partitions, making the width of each slice thinner, our Riemann sum becomes a better estimate, and in the limit, it converges to the exact area, which we call the definite integral.
The power of Riemann sums lies in their flexibility. Depending on the situation, we can choose left-endpoints, right-endpoints, or even midpoints of subintervals — or we can get fancy with trapezoids or other shapes. The idea is to get as close as possible to the actual area under the curve. As we refine our partitions, making the width of each slice thinner, our Riemann sum becomes a better estimate, and in the limit, it converges to the exact area, which we call the definite integral.
Integral Approximation
The approach towards integral approximation involves using techniques like Riemann sums to estimate the value of a definite integral, which is the exact mathematical representation of the area under a curve between two points. While Riemann sum is like drawing with a chunky marker, trying to fit within the lines of the curve, the integral is like using a fine brush, painting in all the details perfectly.
Even though the Riemann sums (left-endpoint, right-endpoint, or midpoints) give us an approximation, when we take the limit as the widths of the rectangles approach zero, we gain the exact value of the area under the curve. That's the essence behind integral approximation — it's a journey from a rough sketch to a detailed masterpiece of the area under a curve.
Even though the Riemann sums (left-endpoint, right-endpoint, or midpoints) give us an approximation, when we take the limit as the widths of the rectangles approach zero, we gain the exact value of the area under the curve. That's the essence behind integral approximation — it's a journey from a rough sketch to a detailed masterpiece of the area under a curve.
Other exercises in this chapter
Problem 19
Use Part I of the Fundamental Theorem to compute each integral exactly. $$\int_{0}^{\ln 2}\left(e^{x / 2}\right)^{2} d x$$
View solution Problem 19
Use the given velocity function and initial position to estimate the final position \(s(b)\). $$v(t)=40\left(1-e^{-2 t}\right), s(0)=0, b=4$$
View solution Problem 19
Find the general antiderivative. $$\int(3 \cos x-1 / x) d x$$
View solution Problem 19
Compute the sum and the limit of the sum as \(n \rightarrow \infty.\) $$\sum_{i=1}^{n} \frac{1}{n}\left[\left(\frac{i}{n}\right)^{2}+2\left(\frac{i}{n}\right)\r
View solution