Problem 19
Question
Use the formal definition of limits to prove each statement. $$ \lim _{x \rightarrow 3^{+}} \frac{1}{3-x}=-\infty $$
Step-by-Step Solution
Verified Answer
As \( x \rightarrow 3^{+} \), \( \frac{1}{3-x} \) decreases without bound, confirming \( \lim_{x \rightarrow 3^{+}} \frac{1}{3-x} = -\infty \).
1Step 1: Understanding the Limit Notation
We want to show that as \( x \) approaches 3 from the right, the limit of \( \frac{1}{3-x} \) is \(-\infty\). This means that for every large positive number \( M \), there exists a \( \delta > 0 \) such that whenever \( 3 < x < 3 + \delta \), \( \frac{1}{3-x} < -M \).
2Step 2: Expressing \( \frac{1}{3-x} < -M \)
Start by rewriting the inequality \( \frac{1}{3-x} < -M \) which implies \( 3-x < \frac{-1}{M} \). This shows that \( x-3 > \frac{1}{M} \) and due to the absolute value in the formal definition of limits, we want \( 0 < x-3 < \delta \).
3Step 3: Finding \( \delta \)
We need \( \frac{1}{M} < x-3 < \delta \). Therefore, choose \( \delta = \frac{1}{M} \). This ensures that whenever \( x \) is in the interval \( (3, 3 + \delta) \), the inequality \( \frac{1}{3-x} < -M \) holds true.
4Step 4: Formal Proof
For every \( M > 0 \), select \( \delta = \frac{1}{M} \). Assume \( 0 < x - 3 < \delta \). Then \( x-3 < \frac{1}{M} \) or equivalently \( 3-x > \frac{-1}{M} \), which implies \( \frac{1}{3-x} < -M \). Hence, the limit \( \lim_{x \rightarrow 3^{+}} \frac{1}{3-x} = -\infty \) is proven.
Key Concepts
Limit ProofFormal Definition of LimitsOne-Sided Limit
Limit Proof
Proving limits can seem daunting, but breaking down the process helps simplify things. In our example, the goal is to show that as \( x \) approaches 3 from the right, the expression \( \frac{1}{3-x} \) tends towards \(-\infty\). This indicates that, for every large positive number \( M \), there must be a small positive number \( \delta \) such that whenever \( x \) is within the interval \( (3, 3 + \delta) \), the expression \( \frac{1}{3-x} \) becomes smaller than \(-M\). To prove this, we convert the inequality \( \frac{1}{3-x} < -M \) into another form: \( 3-x < \frac{-1}{M} \). By reorganizing terms, we find \( x-3 > \frac{1}{M} \), and to fit the limits definition, we need:
- \( 0 < x-3 < \delta \)
- Ensure \( \delta = \frac{1}{M} \)
Formal Definition of Limits
At the heart of calculus limits is a precise definition that ensures mathematics works the way we expect it to. For the function limit, the statement \( \lim_{x \to a} f(x) = L \) relies on this formal definition. It means that for every small positive number \( \epsilon \), there exists a small positive number \( \delta \) such that whenever \( x \) is within \( 0 < |x-a| < \delta \), the function \( f(x) \) is within \( |f(x) - L| < \epsilon \) of \( L \). This precise definition allows us to prove the behavior of functions near a point without relying on visual graphs.In the problem given, as \( x \) approaches 3 from values greater than 3, the value \( \frac{1}{3-x} \) decreases to \(-\infty\). The formal definition ensures we can state this behavior using clearly defined parameters \( M \) and \( \delta \).1. Set a large \( M \) to represent a "cut-off" value that \( \frac{1}{3-x} \) must go beneath.2. Determine \( \delta \) such that if \( x \) strays from 3 within this distance, our inequality is satisfied.This structure provides a robust way to convey, validate, and understand the behavior of limits mathematically.
One-Sided Limit
One-sided limits focus on what happens to a function as values approach a specific number from one direction: either the left or the right. This is crucial in understanding behaviors like discontinuous points or vertical asymptotes, where differing behaviors occur on either side of a specific point.In our example, \( \lim_{x \rightarrow 3^{+}} \frac{1}{3-x} = -\infty \), specifically indicates a right-hand limit, where \( x \) creeps up to 3 from values greater than 3. Such a limit takes into account the behavior of the function when approaching that point strictly from one side, highlighting any asymmetrical tendencies.This emphasis on directionality is vital because:- Different behavior might occur when approaching from different sides.- It highlights infinite discontinuities or vertical asymptotes where the limit can be \( \infty \) or \(-\infty\). Understanding one-sided limits assists in sketching accurate graphs and identifying asymmetrical behaviors in functions, allowing us to capture a complete picture of their behavior near specified points.
Other exercises in this chapter
Problem 18
In Problems 1-32, use a table or a graph to investigate each limit. $$ \lim _{x \rightarrow 0} \frac{1}{x^{2}-1} $$
View solution Problem 19
Let \(f(x)=\frac{\ln x}{x}, \quad x>0\) (a) Use a graphing calculator to graph \(y=f(x)\). (b) Use a graphing calculator to investigate the values of \(x\) for
View solution Problem 19
Evaluate the limits. $$ \lim _{x \rightarrow \infty} \frac{3 e^{2 x}+1}{2 e^{2 x}-e^{x}} $$
View solution Problem 19
In Problems 1-32, use a table or a graph to investigate each limit. $$ \lim _{x \rightarrow 0^{+}} \frac{1}{\left(1-e^{-x}\right)} $$
View solution