Problem 19
Question
Use the difference-of-squares pattern to factor each of the following. $$(x+2)^{2}-(x+7)^{2}$$
Step-by-Step Solution
Verified Answer
Factored form is \((-5)(2x+9)\).
1Step 1: Recognize the Difference of Squares
The expression \((x+2)^{2}-(x+7)^{2}\) is a difference of squares because it is in the form \(a^2 - b^2\), where \(a = x+2\) and \(b = x+7\). The difference of squares pattern is \(a^2 - b^2 = (a - b)(a + b)\).
2Step 2: Apply the Difference of Squares Formula
Substitute \(a = x+2\) and \(b = x+7\) into the formula: \[(x+2)^{2}-(x+7)^{2} = ((x+2)-(x+7))((x+2)+(x+7))\]
3Step 3: Simplify the Expression
First, simplify \((x+2)-(x+7)\): \((x+2)-(x+7) = x + 2 - x - 7 = -5\)Next, simplify \((x+2)+(x+7)\): \((x+2)+(x+7) = x + 2 + x + 7 = 2x + 9\)
4Step 4: Write the Final Factored Expression
Combine the simplified terms from Step 3 to write the final factored expression: \((x+2)^{2}-(x+7)^{2} = (-5)(2x+9)\)
Key Concepts
Factoring PolynomialsAlgebraic ExpressionsMathematical Formulas
Factoring Polynomials
Factoring polynomials is a critical skill in algebra that simplifies expressions and solves equations more feasible. By breaking down a polynomial into simpler components or factors, you make it easier to understand and work with. In this exercise, we're specifically dealing with the method of factoring using the "difference of squares". This method applies when you have an expression that fits the format of \(a^2 - b^2\), which can be factored into \((a-b)(a+b)\).
This is a special polynomial case where every number or variable squared has a distinct square root, making it notably straightforward to factor.
Here are some key points to remember about factoring polynomials:
This is a special polynomial case where every number or variable squared has a distinct square root, making it notably straightforward to factor.
Here are some key points to remember about factoring polynomials:
- Identifying the pattern in expressions is crucial. Look for the square terms first.
- Factor them by applying appropriate formulas such as the difference of squares.
- Simplifying the resultant factors can help in identifying further common factors, if any exist.
Algebraic Expressions
Algebraic expressions are mathematical phrases that can contain numbers, variables, and operators. They're fundamental in expressing mathematical relationships, and they set the stage for equations.
Expressions like
An important aspect of algebraic expressions:
Expressions like
- \((x+2)\) and \((x+7)\)
An important aspect of algebraic expressions:
- They're the building blocks for more complex mathematics, such as equations and functions.
- In any subtraction or addition within them, maintain proper attention to detail because every part contributes to the bigger picture in math operations.
- Recognizing where an expression can be modified or simplified is part of mastering algebra.
Mathematical Formulas
Mathematical formulas serve as standardized methods for solving a wide variety of problems. In the context of this problem, the formula for the difference of squares \(a^2 - b^2 = (a-b)(a+b)\) is instrumental. It provides a straightforward way to decompose specific polynomial expressions.
Formulas are valuable because:
With practice, applying such formulas becomes intuitive, making them indispensable tools in a student's mathematical journey.
Formulas are valuable because:
- They save time and reduce the potential for error by providing step-by-step methods.
- They assist in recognizing patterns quickly, which simplifies complex problems.
- Knowing a formula allows you to approach a problem strategically instead of always calculating from scratch.
With practice, applying such formulas becomes intuitive, making them indispensable tools in a student's mathematical journey.
Other exercises in this chapter
Problem 19
Solve each equation. You will need to use the factoring techniques that we discussed throughout this chapter. $$-6 n^{2}+13 n-2=0$$
View solution Problem 19
Factor completely each of the polynomials and indicate any that are not factorable using integers. $$15 x^{2}+23 x+6$$
View solution Problem 19
Factor each of the composite numbers into the product of prime numbers. For example, \(30=2 \cdot 3 \cdot 5 .\) $$87$$
View solution Problem 19
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(x+6)(x-6)$$
View solution