Problem 19
Question
Use the binomial theorem to expand each expression. $$ (m+2)^{3} $$
Step-by-Step Solution
Verified Answer
The expanded form is \\( m^3 + 6m^2 + 12m + 8 \\\).
1Step 1: Identify Components of the Binomial
The binomial theorem allows us to expand expressions of the form \( (a+b)^n \). In our expression, \( (m+2)^3 \), we identify \( a = m \), \( b = 2 \), and \( n = 3 \).
2Step 2: Apply the Binomial Theorem Formula
The binomial theorem states that \( (a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^{k} \). We'll apply this formula to \( (m+2)^{3} \) with \( n = 3 \).
3Step 3: Calculate Binomial Coefficients
For each term \( k \) from 0 to 3, calculate the binomial coefficient \( \binom{3}{k} \) using the formula \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \). The coefficients are \( \binom{3}{0} = 1 \), \( \binom{3}{1} = 3 \), \( \binom{3}{2} = 3 \), \( \binom{3}{3} = 1 \).
4Step 4: Expand the Expression using Each Term
Now substitute each term into the expression: \( (m+2)^3 = \binom{3}{0}m^{3}2^{0} + \binom{3}{1}m^{2}2^{1} + \binom{3}{2}m^{1}2^{2} + \binom{3}{3}m^{0}2^{3} \). Simplifying each term, we get: \( 1 \cdot m^3 \cdot 1 + 3 \cdot m^2 \cdot 2 + 3 \cdot m \cdot 4 + 1 \cdot 8 \).
5Step 5: Simplify the Final Expression
Calculate and combine the terms: \( m^3 + 6m^2 + 12m + 8 \). This is the expanded form of \( (m+2)^3 \).
Key Concepts
Binomial CoefficientsPolynomial ExpansionFactorialsAlgebra
Binomial Coefficients
In algebra, binomial coefficients play a significant role in expanding polynomial expressions raised to a power. They are represented as \( \binom{n}{k} \) and are essential in the binomial theorem, helping determine the coefficients for each term in the expansion.
- The general formula is \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \), where \( n! \) represents the factorial of \( n \), \( k! \) the factorial of \( k \), and \( (n-k)! \) the factorial of \( (n-k) \).
- These coefficients show how many ways we can choose \( k \) elements from a set of \( n \) elements and are commonly used to calculate combinations.
Polynomial Expansion
Polynomial expansion involves breaking down expressions like \( (a+b)^n \) into simpler, additive forms. By applying the binomial theorem, any binomial expression can be expressed as a sum of terms.
- Each term in the expansion of \( (a+b)^n \) is structured as \( \binom{n}{k} a^{n-k} b^k \), where \( k \) iterates from 0 to \( n \).
- This structure is rooted in understanding both algebraic patterns and the power of binomials, allowing predictions about the form of various polynomial expressions.
Factorials
The concept of factorials, denoted by the symbol \(!\), forms a foundation in calculating binomial coefficients. Factorials are products of a sequence of descending natural numbers.
- For any positive integer \( n \), the factorial \( n! \) is calculated as \( n \times (n-1) \times (n-2) \times \, ... \, \times 1 \).
- Special factorial values include 0! which is defined as 1.
Algebra
Algebra is the overarching mathematical language used to manipulate symbols and numbers. It provides tools and rules to solve equations and expand expressions like binomials.
- Understanding algebra involves recognizing patterns, learning how to rearrange equations, and knowing how to identify components in expressions such as \( (m+2)^3 \).
- It requires the use of operations like addition, multiplication, and exponentiation.
Other exercises in this chapter
Problem 18
\(\mathbf{A}\) typical combination for a padlock consists of three numbers from 0 to 39. Count the combinations possible with this type of lock if a number may
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Use a formula to find the sum of the arithmetic series. $$ 1+3+5+7+\dots+97 $$
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Prove the statement by mathematical induction. \(\left(a^{m}\right)^{n}=a^{m n}(\text { Assume } a \text { and } m\) are constants.)
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Complete the following for the recursively defined sequence. (a) Find the first four terms. (b) Graph these terms. \(a_{n}=3 a_{n-1}-1 ; a_{1}=2\)
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