Problem 19
Question
The hydrogen molecular ion, \(\mathrm{H}_{2}^{+},\) can be detected spectroscopically. Write the electron configuration of the ion in molecular orbital terms. What is the bond order of the ion? Is the hydrogen-hydrogen bond stronger or weaker in \(\mathrm{H}_{2}^{+}\) than in \(\mathrm{H}_{2} ?\)
Step-by-Step Solution
Verified Answer
Electron configuration: \( \sigma_{1s}^{1} \). Bond order: \( \frac{1}{2} \). The bond in \( \mathrm{H}_{2}^{+} \) is weaker than \( \mathrm{H}_{2} \).
1Step 1: Electron Configuration for \\ \( \mathrm{H}_{2}^{+} \)
The ion \( \mathrm{H}_{2}^{+} \) has one proton from each hydrogen and a single electron, as one electron is removed. The electron will occupy the lowest available molecular orbital which is the bonding sigma orbital (\( \sigma_{1s} \)). Therefore, the electron configuration is \( \sigma_{1s}^{1} \).
2Step 2: Calculate Bond Order
The bond order is calculated using the formula: \( \text{Bond Order} = \frac{1}{2} (\text{Number of electrons in bonding orbitals} - \text{Number of electrons in antibonding orbitals}) \). For \( \mathrm{H}_{2}^{+} \), there is 1 electron in the bonding orbital \( \sigma_{1s} \) and 0 in antibonding, so Bond Order = \( \frac{1}{2}(1 - 0) = \frac{1}{2} \).
3Step 3: Compare Bond Strength with \( \mathrm{H}_{2} \)
The bond order of \( \mathrm{H}_{2} \) is 1 (since \( \mathrm{H}_{2} \) has 2 electrons in the \( \sigma_{1s} \) bonding orbital and 0 in antibonding, Bond Order = \( \frac{1}{2}(2 - 0) = 1 \)). Since \( \mathrm{H}_{2}^{+} \) has a lower bond order of \( \frac{1}{2} \), the bond in \( \mathrm{H}_{2}^{+} \) is weaker than the bond in \( \mathrm{H}_{2} \).
Key Concepts
Electron ConfigurationBond OrderSpectroscopyHydrogen IonBond Strength
Electron Configuration
Electron configuration describes the distribution of electrons in atomic or molecular orbitals. For \( \mathrm{H}_{2}^{+} \), the ion consists of two protons and one electron—the molecule loses one electron from the diatomic hydrogen molecule \( \mathrm{H}_{2} \). This lone electron occupies the lowest energy level, which is the bonding sigma orbital. Thus, the electron configuration for \( \mathrm{H}_{2}^{+} \) is represented as \( \sigma_{1s}^{1} \). This signifies that one electron is in the \( \sigma_{1s} \) bonding molecular orbital. Understanding this distribution is crucial as it influences properties like bonding and spectral characteristics.
Bond Order
Bond order is an essential concept in molecular orbital theory as it gives insight into the stability of the bond between atoms. It relates directly to the strength and length of a bond. The formula for bond order is:
- \( \text{Bond Order} = \frac{1}{2} (N_{b} - N_{a}) \),
- where \( N_{b} \) is the number of electrons in bonding orbitals,
- and \( N_{a} \) is the number of electrons in antibonding orbitals.
Spectroscopy
Spectroscopy is a technique used to detect and analyze molecules through their interaction with light. This technique can detect the presence of the \( \mathrm{H}_{2}^{+} \) ion, as molecules absorb specific wavelengths of light which leads to electronic transitions. By studying these transitions, scientists can determine the energy levels of molecular orbitals and observe the configuration of electrons. Spectroscopic methods thus serve as powerful tools in determining molecular structure and detecting ions like \( \mathrm{H}_{2}^{+} \).
Hydrogen Ion
The hydrogen ion \( \mathrm{H}_{2}^{+} \) is interesting because it holds a singular electron between two protons. This makes it a one-electron system, often used as a simple model for studying molecular bonding and quantum mechanical effects. Unlike the neutral hydrogen molecule \( \mathrm{H}_{2} \), which has a stable electron pair, \( \mathrm{H}_{2}^{+} \) lacks this stability and thus results in a weaker bond. The uniqueness and simplicity of \( \mathrm{H}_{2}^{+} \) make it crucial in exploring theoretical principles.
Bond Strength
Bond strength is an indication of how strongly atoms are bonded together in a molecule. This is directly related to bond order; a higher bond order generally means stronger bond strength. In \( \mathrm{H}_{2}^{+} \), the bond order is \( \frac{1}{2} \), whereas, in \( \mathrm{H}_{2} \), it is 1. This comparison shows that the single electron bond in \( \mathrm{H}_{2}^{+} \) is inherently weaker than the two-electron bond in \( \mathrm{H}_{2} \). Understanding bond strength is important to infer the reactivity and stability of molecules.
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