Problem 19
Question
The functions in Exercises \(11-28\) are all one-to-one. For each function, a. Find an equation for \(f^{-1}(x),\) the inverse function. b. Verify that your equation is correct by showing that \(f\left(f^{-1}(x)\right)=x\) and \(f^{-1}(f(x))=x\) $$f(x)=(x+2)^{3}$$
Step-by-Step Solution
Verified Answer
The inverse function is \(f^{-1}(x) = \sqrt[3]{x} - 2\), and both \(f(f^{-1}(x))=x\) and \(f^{-1}(f(x))=x\) hold true.
1Step 1: Finding the inverse of the function
Firstly, replace \(f(x)\) with \(y\), the equation becomes \(y = (x+2)^{3}\). To find the inverse, exchange \(x\) and \(y\), leading to \(x = (y+2)^{3}\). Now, solve for \(y\) to get the inverse function. The cube root of \(x\) is equal to \(y+2\). Substract \(2\) from both sides to isolate \(y\), which results \(y = \sqrt[3]{x} - 2\). So, \(f^{-1}(x) = \sqrt[3]{x} - 2\).
2Step 2: Verifying the inverse function Part I
To verify the found inverse function, substitute \(f^{-1}(x)\) into \(f(x)\) such that \(f(f^{-1}(x))\). Substituting \(f^{-1}(x) = \sqrt[3]{x} - 2\) into \(f(x) = (x+2)^{3}\) yields \(f(f^{-1}(x)) = ((\sqrt[3]{x} - 2) + 2)^{3}\). After simplification, the equation becomes \(f(f^{-1}(x)) = (\sqrt[3]{x})^{3}\) which equals to \(x\).
3Step 3: Verifying the inverse function Part II
Now, substitute \(f(x)\) into \(f^{-1}(x)\) such that \(f^{-1}(f(x))\). Substituting \(f(x) = (x + 2)^{3}\) into \(f^{-1}(x) = \sqrt[3]{x} - 2\) yields \(f^{-1}(f(x)) = \sqrt[3]{(x+2)^{3}} - 2\). Simplifying it results in \(f^{-1}(f(x)) = x + 2 - 2 = x\). Hence, the equation \(f^{-1}(f(x)) = x\) has been satisfied.
Key Concepts
One-to-One FunctionsVerification of Inverse FunctionsCubic Functions
One-to-One Functions
A one-to-one function is a specific type of function where each input is paired with a unique output. This means no two different inputs map to the same output.
This unique pairing is key for ensuring that an inverse function can exist. In other words, a function is one-to-one if different inputs produce different outputs.
This unique pairing is key for ensuring that an inverse function can exist. In other words, a function is one-to-one if different inputs produce different outputs.
- For every value of \(x_1\) and \(x_2\), if \(x_1 eq x_2\), then \(f(x_1) eq f(x_2)\).
- It passes the Horizontal Line Test: A horizontal line drawn through the graph of the function will intersect the graph at most once.
Verification of Inverse Functions
To verify that one function is indeed the inverse of another, you need to perform specific operations to ensure their compositions yield expected results.
Specifically, the following two conditions must be satisfied:
Specifically, the following two conditions must be satisfied:
- For the function \(f\) and its inverse \(f^{-1}\), \(f(f^{-1}(x)) = x\) should hold true for every \(x\) in the domain of \(f^{-1}\).
- Also, \(f^{-1}(f(x)) = x\) should be true for every \(x\) in the domain of \(f\).
Cubic Functions
Cubic functions are polynomial functions of degree three. They take the form \(f(x) = ax^3 + bx^2 + cx + d\). Each cubic function graph has a distinct characteristic look, often possessing a sort of 'curved' shape.
They can have up to three real roots and create an "S" shape in the Cartesian plane, depending on coefficients.
They can have up to three real roots and create an "S" shape in the Cartesian plane, depending on coefficients.
- Cubic functions can have one, two, or three real roots.
- Their graphs are continuous and smooth, without breaks or sharp angles.
- They can be strictly increasing, decreasing, or have inflection points (points where the direction of curvature changes).
Other exercises in this chapter
Problem 18
Determine whether each function is even, odd, or neither. $$f(x)=x^{3}-x$$
View solution Problem 19
find the midpoint of each line segment with the given endpoints. $$ (6,8) \text { and }(2,4) $$
View solution Problem 19
Find the domain of each function. $$g(x)=\frac{1}{\sqrt{x-3}}$$
View solution Problem 19
Determine whether each equation defines \(y\) as a function of \(x .\) $$ y=\sqrt{x+4} $$
View solution