Problem 19
Question
The equation of a conic section is given in a familiar form. Identify the type of graph (if any) that each equation has, without actually graphing. See the summary chart in this section. Do not use a calculator. $$4(x-3)^{2}+3(y+4)^{2}=0$$
Step-by-Step Solution
Verified Answer
The "graph" of the equation is a single point at (3, -4), not a conic section.
1Step 1: Understanding the Given Equation
The given equation is \(4(x-3)^2 + 3(y+4)^2 = 0\). This resembles the standard form of an ellipse, \(\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\), or a circle, when both terms are positive and equal.
2Step 2: Analyzing the Equation Structure
Observe that the sum of two squared terms \(4(x-3)^2\) and \(3(y+4)^2\) is set equal to zero. In the standard equations for conic sections (ellipse, hyperbola, circle, and parabola), the right side is usually a positive number.
3Step 3: Checking the Equation for a Graph
Since \(4(x-3)^2 + 3(y+4)^2 = 0\) is a sum of non-negative terms (squares), and squares cannot produce a negative total unless both are zero, this equation implies both terms must individually be zero: \((x-3)^2 = 0\) and \((y+4)^2 = 0\).
4Step 4: Implicit Solution to Individual Terms
Solving \((x-3)^2 = 0\) gives \(x = 3\), and solving \((y+4)^2 = 0\) gives \(y = -4\). The equation only has a solution at the point \((3, -4)\).
5Step 5: Conclusion on the Type of Graph
Since the equation does not satisfy the standard form of any conic section for a range of values (but instead defines a single point), the graph is not that of a conic section.
Key Concepts
Equations of Conic SectionsEllipsesHyperbolasCircles
Equations of Conic Sections
Conic sections, or conics, are the curves obtained by intersecting a plane with a double-napped cone. The primary types of conics are circles, ellipses, parabolas, and hyperbolas. Each of these types has a standard equation in either Cartesian or polar coordinates. To identify the graph derived from a conic section equation, it is essential to recognize the specific form it takes. For instance, the equation of an ellipse typically looks like this: \( \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \).
- If \( a = b \), the ellipse becomes a circle.
- For a hyperbola, the equation is \( \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \).
- A parabola has the form \( y = ax^2 + bx + c \).
Ellipses
An ellipse might look complicated at first glance, but it's quite straightforward! Ellipses are the "stretched" circles you see around. They have two focal points (foci) and exhibit symmetry around both the x- and y-axes. The standard equation for ellipses is \( \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \), where \( (h, k) \) is the center of the ellipse.If you look closely:
- \(a^2\) is always under \((x-h)^2\) if the ellipse is wider horizontally.
- \(b^2\) is under \((y-k)^2\) if the ellipse is taller vertically.
Hyperbolas
Hyperbolas look like two curves waving away from each other. They might seem unusual, but they're fascinating to study. Their standard form equation is \( \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \). Using this, you can determine their orientation:
- When the \(x\)-term (\((x-h)^2/a^2\)) is positive, the hyperbola opens horizontally.
- If the \(y\)-term (\((y-k)^2/b^2\)) is positive, it opens vertically.
Circles
Circles are usually the first conic section students learn about, given their simple and symmetrical nature. They are perfect forms and extremely easy to work with. The standard equation for a circle is depicted as \( (x-h)^2 + (y-k)^2 = r^2 \). Here,
- \((h, k)\) represents the circle's center.
- \(r\) is the radius of the circle.
Other exercises in this chapter
Problem 19
Use a graphing calculator to generate the curve over the interval for the parameter \(t\), in the window specified. Then find a rectangular equation for the cur
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Graph each ellipse by hand. Give the domain and range. Give the foci in Exercises \(11-14\) and identify the center in Exercises \(17-22 .\) Do not use a calcul
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Describe the graph of the following equation. $$(x-3)^{2}+(y-3)^{2}=0$$
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Graph each ellipse by hand. Give the domain and range. Give the foci in Exercises \(11-14\) and identify the center in Exercises \(17-22 .\) Do not use a calcul
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